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WINSTONCH [101]
1 year ago
15

Train A and Train B leave the station at 2 P.M. The graph below shows the distance covered by the two trains. Compare the speeds

of the two trains.

Mathematics
1 answer:
adoni [48]1 year ago
8 0

Answer:

Train b is moving faster than a by 45 units an hour

Step-by-step explanation:

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The function below shows the number of car owners f(t), in thousands, in a city in different years t: f(t) = 0.25t^2 - 0.5t + 3.
Bingel [31]
The average rate of change (m) is the ratio of the change in function value to the width of the interval:
  m = (f(6) - f(2))/(6 - 2)

To compute this, we need to compute f(6) and f(2).
  f(6) = (0.25*6 -0.5)*6 +3.5 = 9.5
  f(2) = (0.25*2 - 0.5)*2 +3.5 = 3.5
Then the average rate of change is
  m = (9.5 - 3.5)/(6 - 2) = 6/4 = 1.5

The average rate of change is 1.5 thousand owners per year.
3 0
2 years ago
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The students at Barton academy are planning a fundraiser to give money to an organization in their community. They voted for whi
Aneli [31]
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4 0
2 years ago
Rob says that this graph shows a proportional<br> relationship. Is he correct? Explain.
zysi [14]

Answer:

No. Rob was correct to extend the lines to the origin, but the points should be on a single straight line. He made two straight lines.

Step-by-step explanation:

this is from the sample responds so you can see what they want

5 0
1 year ago
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Landry earned $2,300 over the summer and decided to invest it in an account that earns 4% annual compound interest. If Landry do
solniwko [45]

Answer:

Landry will have $5039.58

Step-by-step explanation:

compound interest formula: amount = p(1 + \frac{r}{n})^{nt}

p= principal ($2,300)

r= interest rate as a decimal (4% = 0.04)

n= number of times the principal is compounded per year (annually = once per year so 1 time per year)

t= time in years (20 years)

new equation: amount = 2300(1+\frac{0.04}{1} )^{1*20}

That equation equals $2,739.58 which you add to the principal.

$2,739.58 + $2,300 = $5039.58

hope this helps :) the equations aren't showing up right :(

6 0
2 years ago
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A local fraternity is conducting a raffle where 55 tickets are to be sold—one per customer. There are three prizes to be awarded
harkovskaia [24]

Answer:

(a) 0.0152%

(b) 1.1663%

(c) 19.4297%

(d) 79.3787%

Step-by-step explanation:

Tickets bought by organizers = 4

Number of tickets = 55

Prizes = 3

(a) The probability that the four organizers win all of the prizes is:

P = \frac{4}{55}*\frac{3}{54}*\frac{2}{53}\\P=0.0152\%

(b) The probability that the four organizers win exactly two of the prizes is:

P = \frac{4}{55}*\frac{3}{54}*\frac{51}{53}+\frac{4}{55}*\frac{51}{54}*\frac{3}{53}+\frac{51}{55}*\frac{4}{54}*\frac{3}{53}\\P=1.1663\%

(c) The probability that the four organizers win exactly one of the prizes is:

P = \frac{4}{55}*\frac{51}{54}*\frac{50}{53}+\frac{51}{55}*\frac{4}{54}*\frac{50}{53}+\frac{51}{55}*\frac{50}{54}*\frac{4}{53}\\P=19.4397\%

(d) The probability that the four organizers win none of the prizes is:

P = \frac{51}{55}*\frac{50}{54}*\frac{49}{53}}\\P=79.3787\%

5 0
2 years ago
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