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mash [69]
2 years ago
11

Mr. Santos is carpeting his living room. The room measures 21 feet by 15 feet. The carpeting costs $9 per square foot. How much

carpeting will he need (in square feet), and how much will it cost?
Mathematics
1 answer:
MariettaO [177]2 years ago
6 0
To solve this problem you must apply the proccedure shown below:
 1- You have that the area of the living room is:
 A=lw (Area of the rectangle); where l is the lengt and w is the width.
 A=(21 feet)(15 feet)
 A=315 feet²
 2- The cost is:
 Cost=315 feet²x$9
 Cost=$2835 
 The answer is: He will need 315 feet² and it will cost $2835
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mamaluj [8]
So the new total is:
9 * (44*.8) since the 20% discount means you only pay 80% of the original $44 per item
4 0
2 years ago
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a school district requires all graduating seniors to take a mathematics test. This year, the rest scores were approximately norm
Klio2033 [76]
A score of 85 would be 1 standard deviation from the mean, 74.  Using the 68-95-99.7 rule, we know that 68% of normally distributed data falls within 1 standard deviation of the mean.  This means that 100%-68% = 32% of the data is either higher or lower.  32/2 = 16% of the data will be higher than 1 standard deviation from the mean and 16% of the data will be lower than 1 standard deviation from the mean.  This means that 16% of the graduating seniors should have a score above 85%.
3 0
2 years ago
You have just timed a person doing a hair cut for the first time. It took 50 minutes. What unit improvement factor learning curv
Sladkaya [172]

Answer: C. 70 percent

Step-by-step explanation:

Given, Time for the first unit = 50 minutes

Time for the second unit = 35 minutes

The unit improvement factor learning curve = (The time for the second unit) ÷ (time for the first unit) x 100.

So, The unit improvement factor learning curve  = 35÷ 50 × 100 = 70 percent.

Hence, the correct option is "C. 70 percent".

3 0
2 years ago
The drama club at Del Rosa Middle School is having a production.
Firdavs [7]

Answer:

320 Student Tickets

180 Adult Tickets

Step-by-step explanation:

You can solve this problem by using system of equations. First, we need to figure out our equations.

Equation 1: x as students and y as adults

x+y=500

We get this equation because the total tickets sold was 500. The x represents the students sold to students, and the y represents the tickets sold to adults.

Equation 2:

3x+5y=1850

We get this equation based on the prices. Each student ticket costs $3, and each adult ticket costs $5. The total amount earned was $1850.

Now that we have out equations, we can use system of equations to find our students and adults.

x+y=500

3x+5y=1860

Typically elimination is the easiest strategy because you are able to cross out variables.

3(x+y=500)

3x+5y=1860

Becomes:

3x+3y=1500

3x+5y=1860

We see that both equations now have 3x. We can cancel out 3x.

-2y=-360

y=180

Now that we know y=180, we can plug it back into one of our equations to find x.

x+180=500

x=320

320 student tickets and 180 adult tickets were sold.

6 0
2 years ago
Triangle A has a height of 2.5\text{ cm}2.5 cm2, point, 5, start text, space, c, m, end text and a base of 1.6\text{ cm}1.6 cm1,
konstantin123 [22]

Answer:

Option A

Option D

Option E

Step-by-step explanation:

we know that

If the height and base of triangle B are proportional to the height and base of triangle A

then

Triangle A and Triangle B are similar

Remember that

If two triangles are similar then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

so

\frac{h_A}{h_B} =\frac{b_A}{b_B}

where

h_A and h_B are the height of triangle A and triangle B

b_A and b_B are the base of triangle A and triangle B

In his problem we have

h_A=2.5\ cm\\b_A=1.6\ cm

substitute

\frac{2.5}{h_B} =\frac{1.6}{b_B}

Rewrite

\frac{2.5}{1.6} =\frac{h_B}{b_B}

\frac{h_B}{b_B}=1.5625

<u><em>Verify all the options</em></u>

A) we have

h_B=2.75\ cm\\b_B=1.76\ cm

Find the ratio of the height to the base of triangle B and compare the result with the ratio of height to the base of triangle A (the value is 1.5625)

substitute the values in the proportion

\frac{2.75}{1.76}=1.5625

The ratios are the same

That means that are proportional

therefore

These values could be the height and base of triangle B

B) we have

h_B=9.25\ cm\\b_B=9.16\ cm

Find the ratio of the height to the base of triangle B and compare the result with the ratio of height to the base of triangle A (the value is 1.5625)

substitute the values in the proportion

\frac{9.25}{9.16}=1.0098

The ratios are not equal

That means that are not proportional

therefore

These values could not be the height and base of triangle B

C) we have

h_B=3.2\ cm\\b_B=5\ cm

Find the ratio of the height to the base of triangle B and compare the result with the ratio of height to the base of triangle A (the value is 1.5625)

substitute the values in the proportion

\frac{3.2}{5}=0.64

The ratios are not the same

That means that are not proportional

therefore

These values could not be the height and base of triangle B

D) we have

h_B=1.25\ cm\\b_B=0.8\ cm

Find the ratio of the height to the base of triangle B and compare the result with the ratio of height to the base of triangle A (the value is 1.5625)

substitute the values in the proportion

\frac{1.25}{0.8}=1.5625

The ratios are the same

That means that are proportional

therefore

These values could be the height and base of triangle B

E) we have

h_B=2\ cm\\b_B=1.28\ cm

Find the ratio of the height to the base of triangle B and compare the result with the ratio of height to the base of triangle A (the value is 1.5625)

substitute the values in the proportion

\frac{2}{1.28}=1.5625

The ratios are the same

That means that are proportional

therefore

These values could be the height and base of triangle B

8 0
2 years ago
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