Answer:
<h2>It takes 36 minutes to fill the bathtub using just hot water.</h2>
Step-by-step explanation:
We are gonna name V the complete volume of the bathtub, which is filled a certain amount of minutes. Each filling rate or speed is gonna be expressed as:
.
So, if we apply this consideration to each case we have:
Using cold and hot water: 
Using only cold water: 
Using only hot water:
; because we don't knot the time it takes to fill the bathtub with hot water.
Now, as you can see, Cold and Hot water is a sum of cold water only and hot water only:

Solving the equation for <em>x: </em>

Therefore, it takes 36 minutes to fill the bathtub using just hot water.
Hi there!
PART A:
The system of equations we would use would be:
x + y = 22 (amount of items)
3x + 1y = 30 (cost)
Variables:
x = the amount of strawberry wafers bought at the price of $3
y = the amount of chocolate wafers bought at the price of $1
PART B:
To solve, we'll use substitution because we can easily isolate a variable using the first equation.
Work:
x + y = 22 (first equation)
y = 22 - x (isolating a variable)
3x + 1y = 30 (second equation)
3x + (22 - x) = 30 (substituting into the second equation)
2x + 22 = 30 (simplifying)
2x = 8 (subtracting)
x = 4 strawberry wafers
4 + y = 22 (substituting x into the first equation to solve for y)
y = 18 chocolate wafers
ANSWER:
They bought 4 strawberry wafers and 18 chocolate wafers.
Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
Answer:
Since p value <0.1 accept the claim that oven I repair costs are more
Step-by-step explanation:
The data given for two types of ovens are summarised below:
Group Group One Group Two
Mean 85.7900 78.6700
SD 15.1300 17.8400
SEM 1.9533 2.3840
N 60 56
Alpha = 10%

(Right tailed test)
The mean of Group One minus Group Two equals 7.1200
df = 114
standard error of difference = 3.065
t = 2.3234
p value = 0.0219
If p value <0.10 reject null hypothesis
4) Since p value <0.1 accept the claim that oven I repair costs are more
Solution:
The square of the given equation can be completed as below:
Here we will make the terms on left hand side such that it gets the form of 

Hence the correct option is isolating the constant , -3.
Answer: 0.46, 0.056, the distribution is approximately normal
Step-by-step explanation: The shape is approximately normal since the expected number of successes equals 36.8 and the expected number of failures equals 43.2 are both larger than 10