Answer:
The total time it will take for the discus to reach the ground is 2.892 s
Step-by-step explanation:
To answer the question, we will first calculate the total time before the discus touches the ground as follows;
The vertical component of the velocity = v × sinθ = 65 × sin 44° = 45.153 ft/s
Maximum height reached = v² = u² - 2 × g × h
0² = 45.153² - 2×32.2×h
h = 45.153²/(2×32.2) = 31.673 ft
Time to reach maximum height is v = u - gt, t = u/g. where v = 0
t = 45.153/32.2 = 1.403 s
Time to go from maximum height to just before touching the ground is given by s = u·t + 0.5·g·t², which gives;
31.673 + 4 = 0×t + 0.5×32.2×t²
2.21673 = t²
t = 1.49 s
Therefore the total time of the discus flight = 1.403 + 1.49 = 2.892 s
Which means, the total time it will take for the discus to reach the ground = 2.892 s.
