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meriva
2 years ago
9

The diagram shows JKL. Which term describes point M?

Mathematics
2 answers:
laiz [17]2 years ago
6 0

Answer:

A; Orthocenter

Step-by-step explanation:

dangina [55]2 years ago
4 0

orthogonal = perpendicular.

an altitude in a triangle is the perpendicular distance stemming from a vertex.

where all these orthogonal segments meet is the ORTHOcenter.

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A bag contains one red pen, four black pens, and three blue pens. two pens are randomly chosen from the bag and are not replaced
bagirrra123 [75]
8 total pens....4 are black

first pick, probability of being black is 4/8 
2nd pick. without replacing, probability is 3/7

probability of a black pen picked first and then another black pen picked again is : 4/8 * 3/7 = 12/56 = 0.21
8 0
2 years ago
Read 2 more answers
Together Mary, Jane, and Ruth received $30. Mary received $6, Jane received $9, and Ruth received $15. What percent of the $30 d
Likurg_2 [28]
Hey there! :D 

So, we know that Jane received $9 out of the $30. 

Divide 9 by 30. 

9/30= .3

Turn that into a percentage. 

.3= 30%

We can check this by finding the other percentages. 

Ruth= 15  15/30= .5 50% 

Mary= 6 6/30= .2 20%

30%+20%+50%= 100% <== this works

I hope this helps!
~kaikers 
8 0
2 years ago
Read 2 more answers
The true average diameter of ball bearings of a certain type is supposed to be 0.5 in. A one-sample t test will be carried out t
Naily [24]

Answer:

Option C - Do not reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in

Step-by-step explanation:

We are given;

n = 15

t-value = 1.66

Significance level;α = 0.05

So, DF = n - 1 = 15 - 1 = 14

From the one-sample t - table attached, we can see that the p - value of 0.06 at a t-value of 1.66 and a DF of 14

Now, since the P-value is 0.06,it is greater than the significance level of 0.05. Thus we do not reject the null hypothesis. We conclude that there is not sufficient evidence that the true diameter differs from 0.5 in.

8 0
1 year ago
A recent study found that 51 children who watched a commercial for Walker Crisps (potato chips) featuring a long-standing sports
hichkok12 [17]

Answer:

1

The claim is that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

2

The kind of test to use is a t -test because a t -test is used to check if there is a difference between means of a population

3

t  =  3.054

4

The p-value  is   p-value  =  P(Z >  3.054) = 0.0011291

5

The conclusion is  

There is sufficient evidence to conclude that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

The test statistics is  

Step-by-step explanation:

From the question we are told that

   The first sample size is  n_1  =  51

    The first sample  mean is \mu_1  =  36

    The second sample size is  n_2  =  41

    The second sample  size is  \mu_2  =  25

     The first standard deviation is  \sigma _1  =  21.4 \  g

    The second standard deviation is  \sigma _2  =  12.8 \  g

  The  level of significance is  \alpha =  0.05

The  null hypothesis is  H_o  :  \mu_1 = \mu_ 2

The  alternative hypothesis is  H_a :  \mu_1 > \mu_2

Generally the test statistics is mathematically represented as

    t  =  \frac{\= x_1 - \= x_2}{ \sqrt{ \frac{s_1^2}{n_1}  + \frac{s_2^2}{n_2}  } }

=>   t  =  \frac{ 36 - 25}{ \sqrt{ \frac{ 21.4^2}{51}  + \frac{ 12.8^2}{41}  } }

=> t  =  3.054

The  p-value is mathematically represented as

     p-value  =  P(Z >  3.054)

Generally from the z table  

             P(Z >  3.054) =  0.0011291

=>   p-value  =  P(Z >  3.054) = 0.0011291

From the values obtained  we see that p-value  < \alpha so  the null hypothesis is rejected

Thus the conclusion is  

  There is sufficient evidence to conclude that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

5 0
2 years ago
The student council has decided to have a raffle at the carnival. They came up with a table to show the relationship between the
elena-14-01-66 [18.8K]
Write an equation to find the number of each type of ticket they should sell.Let "x" be # of adult tickets; Let "y" be # of student tickets: Value Equation: 5x+3y=450-------------------------- b. Graph your equation.y = (-5/3)x+150
c. Use your graph to find two different combinations of tickets sold.I'll leave that to you.

6 0
2 years ago
Read 2 more answers
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