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disa [49]
2 years ago
15

Determine the 20th derivative of y = sin(2x).

Mathematics
1 answer:
snow_lady [41]2 years ago
4 0
1st derivative = 2 cos (2x) 2nd derivative = -4sin(2x) 3rd = -8 cos(2x) . . . 20th derivative= 2^20 sin(2x)
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If 25^x+1 = 125/5^x find the value of x
storchak [24]
  • Answer:

<em>x =1/3</em>

  • Step-by-step explanation:

<em>25ˣ⁺¹ = 125/5ˣ</em>

<em>5²⁽ˣ⁺¹⁾ = 5³/5ˣ</em>

<em>5²⁽ˣ⁺¹⁾ = 5³ : 5ˣ</em>

<em>5²⁽ˣ⁺¹⁾ = 5³⁻ˣ</em>

<em>2(x + 1) = 3 - x</em>

<em>2x + 2 = 3 - x</em>

<em>2x + x = 3 - 2</em>

<em>3x = 1</em>

<em>x = 1/3</em>

8 0
2 years ago
What is the answer for this question (What does the equation 100+0.05p=0.25p represent?)
spin [16.1K]

Answer:

100+0.30p

hope this helps

have a good day :)

Step-by-step explanation:

7 0
1 year ago
Parabola Skate Rental rents skate boards for $4.50 per hour with a rental fee of $35. Arc of Hawk Skate Rental rents skate board
NNADVOKAT [17]

Answer: \bold{13\dfrac{1}{3}\ \text{hours}}

<u>Step-by-step explanation:</u>

Parabola Skate Rental:   4.50x + 35

Arc Hawk Skate Rental:  5.25x + 25


If you want to know when their cost will be the same, set the equations equal to each other.

5.25x + 25 = 4.50x + 35

0.75x + 25 = 35          <em>subtracted 4.50x from both sides</em>

0.75x = 10           <em>subtracted 25 from both sides</em>          

     x=\dfrac{1000}{75}        <em>divided both sides by 0.75</em>

     x = 13\dfrac{1}{3}        <em>simplified the fraction</em>


8 0
2 years ago
Rate at which risk of down syndrome is changing is approximated by function r(x) = 0.004641x2 − 0.3012x + 4.9 (20 ≤ x ≤ 45) wher
romanna [79]
The rate of change of the risk of down syndrome (in percentage of births per year) is
r(x) = 0.004641x² - 0.3012x + 4.9,   20≤ x ≤ 45
where
x = maternal age at delivery.

The function giving risk as a percentage of births when maternal age is x is the integral of r(x). That is,
f(x) = 0.001547x³ - 0.1506x² +4.9x + c

When x = 30, f = 0.14%. Therefore
0.001547(30³) - 0.1506(30²) + 4.9(30) + c = 0.14 
41.769 - 135.54 + 147 + c = 0.14
c = -53.089

Answer:
f(x) = 0.001547x³ - 0.1506x² + 4.9x - 53.089,   20 ≤ x ≤ 45

The function is graphed as shown below.

7 0
2 years ago
The temperature reading from a thermocouple placed in a constant-temperature medium is normally distributed with mean μ, the act
stealth61 [152]

Answer:  0.2551

Step-by-step explanation:

Given : The temperature reading from a thermocouple placed in a constant-temperature medium is normally distributed with mean μ, the actual temperature of the medium, and standard deviation σ.

Significance level : \alpha=1-0.95=0.05

The critical z-value for 95% confidence : z_{\alpha/2}=1.960 (1)

Since , z=\dfrac{x-\mu}{\sigma} (where x be any random variable that represents the temperature reading from a thermocouple.)

Then, from (1)

\dfrac{x-\mu}{\sigma}=1.96\\\\ x-\mu=1.96\sigma     (2)

Also,  all readings are within 0.5° of μ,

i.e. x-\mu

i.e. 1.96\sigma   [From (2)]

i.e. \sigma  

i.e. \sigma\approx0.2551

The required standard deviation : \sigma=0.2551

3 0
2 years ago
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