Answer:
Step-by-step explanation:
The conic form of the equation for a sideways parabola is
(y - k)² = 4p(x - h)
The focus is at (h + p, k)
The equation of Samara's parabola is
(y - 3)² = 8(x - 4)
h = 4
p = 8/4 = 2
k = 3
h + p = 6
So, the focus point of the satellite dish is at
No, not possible to tell that the the two triangles, ΔBAC and ΔCED
are similar ⇒ answer D
Step-by-step explanation:
Let us revise the cases of similarity
1. AAA similarity : two triangles are similar if all three angles in the first
triangle equal the corresponding angle in the second triangle
2. AA similarity : If two angles of one triangle are equal to the
corresponding angles of the other triangle, then the two triangles
are similar.
3. SSS similarity : If the corresponding sides of the two triangles are
proportional, then the two triangles are similar.
4. SAS similarity : In two triangles, if two sets of corresponding sides
are proportional and the included angles are equal then the two
triangles are similar.
In the two triangles BAC and CED
∵ m∠BAC = 17°
∵ m∠CED = 17°
∴ m∠BAC = m∠CED
But we need another pair of angles to prove that the two triangles are
similar by AA similarity criterion
<em>OR </em>
The lengths of sides BA , CA and CE , DE to show that
= constant ratio and prove that the
two triangles are similar by SAS similarity criterion
So it is not possible to prove that the two triangles are similar
No, not possible to tell that the the two triangles, ΔBAC and ΔCED
are similar
Learn more:
You can learn more about triangles in brainly.com/question/4354581
#LearnwithBrainly
Answer:
(3/4)a
Step-by-step explanation:
The angle at K is 120°, so the angle at L is its supplement: 60°. That makes triangle FKL an equilateral triangle with a base of FL = a. The vertex at K is centered over the base, so is a/2 from G.
The midsegement length is the average of GK and FL, so is ...
midsegment = (GK +FL)/2 = (a/2 +a)/2
midsegment = (3/4)a
