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Naily [24]
2 years ago
11

() and () are inverses of one another and drawn on the same graph with the same scale on both the horizontal and vertical axis.

Which of the following would be true?
A.
By reflecting the entire coordinate grid over the line =, () would land on ().

B.
() is the same as (), translated up 3 units.

C.
By rotating () 90° clockwise around the origin you would get ().

D.
By rotating () 180° clockwise around the origin you would get ().
Mathematics
1 answer:
Gelneren [198K]2 years ago
6 0

Answer: Option A.

Step-by-step explanation:

We have the functions f(x) and g(x), that are inverses between them.

This means that if:

f(x) = y

then:

g(y) = x.

now, remember that:

When we have a point (x, y), and we reflect it over the line y = x, our new point will be (y, x).

So before we whe had:

f(x) = y.

and now in that same place, we have:

g(y) = x.

So the old graph of f(x) now coincides with the graph of g(x). (And the old graph of g(x) now coincides with the graph of f(x) )

So A is true.

B) This depends on the function:

if we have f(x) = x  + 1.5

then f(0) = 1.5

now we want that:

g(1.5) = 0, then we can write:

g(x) = x - 1.5

Now f(x) and g(x) are inverses, and we would have that:

f(x) = g(x) + 3.

So f(x) is g(x) translated up by 3 units, but this is a particular case, not a general one, so B is not always true.

C and D) When we do rotations of 90° or 180°, we are effectively changing the quadrant of our point. so rotations will cause not only changes as the reflection over the x = y line, those will also cause changes in the sign of our variables, so, while for some functions f(x) and g(x) we can have that the rotations will map one into the other, this is not the general case.

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saw5 [17]

Proof: We know that angle CBA is congruent to angle FBA and that angle CAB is congruent to angle FAB because the corresponding angles have the same measure in degrees (as evidenced in the given equation). We see that angle BCA is congruent to angle BFA by the reflexive property of congruence (More accurately Third Angle Theorem). Therefore, we can conclude that triangle BCA is congruent to triangle BFA because a pair of corresponding angles and the included side are equal, since the two triangles share a line segment (AB).

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2 years ago
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Miss Croft made snack bags for the picnic that contain three types of snacks: packages of crackers, packages of cookies, and can
jek_recluse [69]

Answer: $1.25

Step-by-step explanation:

Let the cost of cracker be a.

Let the cost of cookies be b.

Let the cost of candy bars be c.

From the question,

6a + 6b + 6c = $21

8a + 5b + 10c = $26

5a + 4b + 7c = $18.50

To solve this, we first pick any two pairs of equation. This will be:

6a + 6b + 6c = $21 ....... i

8a + 5b + 10c = $26 ....... ii

Multiply equation i by 8

Multiply equation ii by 6

48a + 48b + 48c = $168 ....... iii

48a + 30b + 60c = $156 ....... iv

Subtract equation iv from iii

18b - 12c = 12

We then pick another two pairs

8a + 5b + 10c = $26

5a + 4b + 7c = $18.50

Multiply equation i by 5

Multiply equation ii by 8

40a + 25b + 50c = $130

40a + 32b + 56c = $148

Subtract the equations

-7b - 6c = -18

Then, solve the new equations formed

18b - 12c = 12 ....... v

-7b - 6c = -18 ....... vi

Multiply equation i by -7

Multiply equation ii by 18

-126b + 84c = -84

-126b - 108c = -324

Subtract the equations

192c = 240

c = 240/129

c = $1.25

From equation v, put the value of c

18b - 12c = 12

18b - 12($1.25) = 12

18b - $15 = $12

18b = $27

b = $27/18

b = $1.5

Since,

6a + 6b + 6c = $21

6a + 6($1.5) + 6($1.25) = $21

6a + $9 + $7.5 = $21

6a + $16.5 = $21

6a = $21 - $16.5

6a = $4.5

a = $4.5/6

a = $0.75

One candy bar cost $1.25

6 0
2 years ago
A grocery sold 5kg of wheat flour at Rs30 per kg and gained 20%. If he had sold it at Rs27 per kg, what would be his gain or los
maria [59]

Answer:

His gain percent would have been 8%

Step-by-step explanation:

The key to answering this question is to first calculate the price at which the wheat flour was bought.

Mathematically;

% profit = (selling price-cost price)/cost price * 100%

Let the cost price be $x

Thus;

% profit = (30-x)/x * 100

20 = 100(30-x)/x

20x = 3000-100x

100x + 20x = 3000

120x = 3000

x = 3000/120

x = Rs 25

So let’s assume he sold at Rs 27

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His gain or loss percentage would’ve been;

2/25 * 100/1 = 200/25 = 8% (gain, since selling price is greater than the cost price)

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A log splitter uses a pump with hydraulic oil to push a piston, attached to which is a chisel. The pump can generate a pressure
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we are given

The pump can generate a pressure of 2.3x107 pa

so,

p=2.3*10^7

a radius of 0.041 m

so,

r=0.041m

a stroke lasting 29 s, the piston moves 0.57 m

so,

h=0.57m

t=29s

Firstly, we will find area

A=\pi r^2

A=\pi (0.041)^2

A=0.00528

now, we can use power formula

P=\frac{W}{t}

F=pA

W=Fh

so, W=pAh

we can plug it

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2 years ago
Sarah can bicycle a loop around the north part of Lake Washington in 2 hours and 30 minutes. If she could increase her average s
netineya [11]

Answer:

The length of the loop is approximately 49.58 km.

Step-by-step explanation:

Given:

Time required to ride bicycle in loop = 2 hours and 30 mins

Now we know that;

60 mins = 1 hour

30 mins =0.5 hour

so 2 hour and 30 mins = 2+0.5 = 2.5\ hrs

∴ Time required to ride bicycle in loop = 2.5 hrs

Let the speed at which she is riding the bicycle be 's'.

and let Total distance of the loop be 'd'

Now we know that;

Distance is given by speed multiplied by time.

framing in equation form we get;

d =2.5s \ \ \ \ equation \ 1

Now Given:

If she increase the speed by 1 km/hr, it would reduce her time around the loop by 7 minutes.

Hence we can say;

Speed =s+1

Also time will be reduce to 7 mins.

7 mins  =0.12 hrs

Now time = 2.5-0.12 =2.38

Again Distance is given by speed multiplied by time.

framing in equation form we get;

d =2.38(s+1) \ \ \ \ equation \ 2

Now distance is same for both so we will calculate the speed by equating the equations.

2.5s = 2.38(s+1)\\\\2.5s=2.38s+2.38\\\\2.5s-2.38s =2.38\\\\0.12s= 2.38\\\\s =\frac{2.38}{0.12} \approx 19.83\ km/hr

Now Speed = 19.83 km/hr

Length of the loop (d) = 19.83\times 2.5 = 49.58 \ km

Hence the length of the loop is approximately 49.58 km.

7 0
2 years ago
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