Syd chooses two different primes, both of which are greater than $10,$ and multiplies them. The resulting product is less than $
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First box = 14 pounds
Second box = 2x = 28 pounds
Third Box = x+2= 16 pounds
Fourth box = x/2 = 7 pounds
<u>Step-by-step explanation:</u>
Here we have , Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box. The third box contained two more pounds than the first box. The last box contained one-fourth the amount in the second box. We need to find How much candy was in each box. Let's find out:
We have a total of 65 pounds of candy ! Let in first box we have x pounds so , second box contained twice the amount of the first box i.e.
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The third box contained two more pounds than the first box i.e.
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The last box contained one-fourth the amount in the second box i.e.
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Therefore , Sum of pounds of candy are :
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Therefore , Candy in each box is :
First box = 14 pounds
Second box = 2x = 28 pounds
Third Box = x+2= 16 pounds
Fourth box = x/2 = 7 pounds
f(x)=x^2+12x+26
Vertex form of f(x) = a(x-h)^2 +k
We change f(x) into vertex form using completing the square method
We take half of square of middle term
middle term is 12
Half of square of 12 is then 6^2 = 36
Add and subtract 36 to complete the square
The vertex form