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1 year ago

In a standard normal distribution, what z value corresponds to 17% of the data between the mean and the z value?

1 answer:

hjlf1 year ago

4 0

You're looking for a value $z$ such that

$\mathbb P(0$

Because the distribution is symmetric, the value of $z$ in either case will be the same.

Now, because the distribution is continuous, you have that

$0.17=\mathbb P(0$

The mean for the standard normal distribution is $0$ , and because the distribution is symmetric about its mean, it follows that $\mathbb P(Z$ .

$0.17=\mathbb P(Z$

You can consult a $z$ score table to find the corresponding score for this probability. It turns out to be $z\approx0.4399$ .

You might be interested in

Shelley receives supplies for her sno-cones business weekly. She usually works concession at four events a week and averages sal

My name is Ann [436]

Answer:

<u>Shelley did not budget enough. She will need additional US$ 16 for fulfilling the average sales of 760 sno-cones at the 4 events. With the budget she has, she just can supply 714 sno-cones (250 / 0.35).</u>

Step-by-step explanation:

1. Let's check all the information given for solving this question:

Cost of individual supply = US$ 0.35

Budget per week = US$ 250

Average sales of sno-cones per event = 190

Number of events per week = 4

2. Let's check if Shelley budgeted enough for the week events:

Total of sno-cones Shelley will sell = Average sales * Number of Events

Total of sno-cones Shelley will sell = 190 * 4 = 760

Cost of supplies for the week = Total of sno-cones * Cost of individual supply

Cost of supplies for the week = 760 * 0.35 = US$ 266

Budget per week = US$ 250

Budget per week - Cost of supplies for the week = 250 - 266 = - 16

4 0

2 years ago

Given that Ray E B bisects ∠CEA, which statements must be true? Select three options. m∠CEA = 90° m∠CEF = m∠CEA + m∠BEF m∠CEB =

FromTheMoon [43]

Answer:

Here is the question attached with.

$m\angle CEA =90 \ (deg)$

$m\angle BEF=135\ (deg)$

$\angle CEF$ is a straight line.

$\angle AEF$ is a right angled triangle.

Options $1,4,5,6$ are correct answers.

Step-by-step explanation:

⇒As $\ ray\ AE$ is ⊥ $FEC$ so it will forms right angled triangle then $m\angle CEA =90\ (deg)$ .

⇒Measure of $\angle BEF =135\ (deg)$ as $\angle BEF =\angle AEB +\angle AEF = (45+90)=135\ (deg)$ as $\angle AEB$ is the bisector of $\angle AEC$ ,meaning that $\angle AEB$ is half of $\angle AEC$ so $\angle AEB = 45\ (deg)$ .

⇒ $\angle CEF$ is a straight line as the angles measure over it is $180\ (deg)$ .

⇒Measure of $\angle AEF = 90\ (deg)$ from linear pair concept.

As $\angle CEA + \angle AEF = 180\ (deg)$ ,plugging the values of $m\angle CEA =90\ (deg)$ we have $\angle AEF = 90\ (deg)$ .

The other two options are false as:

$m\angle CEF=m\angle CEA + m\angle BEF = (90+135)=225$

it is exceeding $180\ (deg)$ whereas $\angle CEF$ is a

straight line.

And $m\angle CEB=2(m\angle CEA)$ is not true.

As $\angle CEA = 90\ (deg)$ and $\angle CEB=45\ (deg)$

So we have total $4$ answers.

The correct options are $1,4,5,6$ .

5 0

2 years ago

Read 2 more answers

To find the distance between (-2,-3) and (4,1), Peggy's teacher drew a diagram and marked blue lines to represent the legs of a

Igoryamba

Answer:

Ik this is late but the answer is A

3 0

1 year ago

Tire pressure monitoring systems (TPMS) warn the driver when the tire pressure of the vehicle is 26% below the target pressure.

ZanzabumX [31]

Answer:

a) 22.94 psi

b) $5.93\times10^{-5}$

Step-by-step explanation:

a)The pressure at which will trigger a warning is

31 - 31*0.26 = 22.94 psi

b) The probability that that the TPMS will trigger warning at 22.94 psi, given that tire pressure has a normal distribution with average of 31 psi and standard deviation of 2 psi

$f(x)={\frac {1}{\sigma {\sqrt {2\pi }}}}e^{-{\frac {1}{2}}\left({\frac {x-\mu }{\sigma }}\right)^{2}}$

where x = 22.94, $\mu = 31, \sigma = 2$

$f(22.94)={\frac {1}{2 {\sqrt {2\pi }}}}e^{-{\frac {1}{2}}\left({\frac {22.94-31}{2 }}\right)^{2}}$

$f(22.94)=0.2e^{-8.12} = 5.93\times10^{-5}$

6 0

2 years ago

A Climbing Gym charges $10 to climb each day. A pair of Climbing shoes cost $84. It cost $169 to buy 6 days of climbing, one pai

yaroslaw [1]

Cost of 6 days climbing = $10 * 6 = $60
Cost of one pair of shoes = $84
Total cost = $169

So, cost of one harness = $169 - $(84+60)
harness = $169 - $144 = $25

So, your final answer is $25

8 0

2 years ago