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Dovator [93]
2 years ago
15

Five and nine tenths in expanded form and standard

Mathematics
1 answer:
nika2105 [10]2 years ago
3 0

Answer:

  • 5×1 +9×0.1
  • 5.9

Step-by-step explanation:

The verbiage "five and nine tenths" can refer to the mixed number 5 9/10, or to the decimal in standard form, 5.9. Simply converting the phrase to a decimal gets you the standard form.

The expanded form can be written a number of ways, depending on how you like to show the place value multipliers. The simplest expanded form is simply the sum of the digits:

  5 + 0.9

You can show the multipliers in standard form:

  5×1 + 9×0.1

Or, you can show the multipliers in exponential form:

  5×10⁰ +9×10⁻¹

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brian filled 72 glasses with apple juice for a school party if each glass holds 1 cup of juice how many quarts of apple juice di
GaryK [48]
4 cups in a quart so you would have 72 cups divided by 4 and get 18
5 0
2 years ago
A sample of 2,000 licensed drivers revealed the following number of speeding violations. Number of Violations Number of Drivers
Arturiano [62]

Answer:

The probability that a particular driver had exactly two speeding violations is 0.009.

Step-by-step explanation:

We are given that a sample of 2,000 licensed drivers revealed the following number of speeding violations;

           <u>Number of Violations</u>               <u>Number of Drivers</u>

                         0                                              1,910

                          1                                                46

                         2                                                 18

                         3                                                 12

                         4                                                  9

                         5 or more                             <u>       5      </u>

                        <u>Total</u>                                      <u>    2000  </u>

<u />

Now, the data means that 1,910 drivers had 0 speeding violations and so on.

Now, we have to find the probability that a particular driver had exactly two speeding violations, that means;

Number of drivers having exactly two speeding violations = 18

 Total numbers of drivers = 2000

So, the required probability  =  \frac{\text{No. of drivers having two speeding violations}}{\text{Total no. of drivers}}

                                               =  \frac{18}{2000}  =  <u>0.009</u>

6 0
1 year ago
Fill in the gaps in the arithmetic sequence -3, _ ,_ , _, _, _ 12
lord [1]

Answer:

  -0.5, 2, 4.5, 7, 9.5

Step-by-step explanation:

The given terms are 6 apart, so the common difference is 1/6 of their difference:

  d = (12 -(-3))/6 = 15/6 = 5/2 = 2.5

Add 2.5 to each term to get the next one. Then the sequence is ...

  -3, <u>-0.5</u>, <u>2.0</u>, <u>4.5</u>, <u>7.0</u>, <u>9.5</u>, 12

8 0
2 years ago
The number of flaws in a fiber optic cable follows a Poisson distribution. It is known that the mean number of flaws in 50m of c
boyakko [2]

Answer:

(a) The probability of exactly three flaws in 150 m of cable is 0.21246

(b) The probability of at least two flaws in 100m of cable is 0.69155

(c) The probability of exactly one flaw in the first 50 m of cable, and exactly one flaw in the second 50 m of cable is 0.13063

Step-by-step explanation:

A random variable X has a Poisson distribution and it is referred to as Poisson random variable if and only if its probability distribution is given by

p(x;\lambda)=\frac{\lambda e^{-\lambda}}{x!} for x = 0, 1, 2, ...

where \lambda, the mean number of successes.

(a) To find the probability of exactly three flaws in 150 m of cable, we first need to find the mean number of flaws in 150 m, we know that the mean number of flaws in 50 m of cable is 1.2, so the mean number of flaws in 150 m of cable is 1.2 \cdot 3 =3.6

The probability of exactly three flaws in 150 m of cable is

P(X=3)=p(3;3.6)=\frac{3.6^3e^{-3.6}}{3!} \approx 0.21246

(b) The probability of at least two flaws in 100m of cable is,

we know that the mean number of flaws in 50 m of cable is 1.2, so the mean number of flaws in 100 m of cable is 1.2 \cdot 2 =2.4

P(X\geq 2)=1-P(X

P(X\geq 2)=1-p(0;2.4)-p(1;2.4)\\\\P(X\geq 2)=1-\frac{2.4^0e^{-2.4}}{0!}-\frac{2.4^1e^{-2.4}}{1!}\\\\P(X\geq 2)\approx 0.69155

(c) The probability of exactly one flaw in the first 50 m of cable, and exactly one flaw in the second 50 m of cable is

P(X=1)=p(1;1.2)=\frac{1.2^1e^{-1.2}}{1!}\\P(X=1)\approx 0.36143

The occurrence of flaws in the first and second 50 m of cable are independent events. Therefore the probability of exactly one flaw in the first 50 m and exactly one flaw in the second 50 m is

(0.36143)(0.36143) = 0.13063

4 0
2 years ago
Jerry makes $40,000 a year working at a nearby factory. He gets two weeks paid vacation per year, plus five other paid holidays.
JulijaS [17]

Answer:

Vacation pays are not included in salaries. Therefore, Jerry's calculation is wrong.

Step-by-step explanation:

Given is :

Jerry makes $40,000 a year working at a nearby factory.

He gets two weeks paid vacation per year, plus five other paid holidays.

So total paid holidays become = 14+5=19 days

Subtracting 19 from 365 days and assuming that Jerry works for 365 days a year.

We get = 365-19=346 days

So, his per day salary will be = \frac{40000}{346}= 115.60

Vacation pays are not included in salaries. Therefore, Jerry's calculation is wrong.

4 0
2 years ago
Read 2 more answers
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