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steposvetlana [31]
2 years ago
5

Brian is solving the equation x2-3/4x=5. What value must be added to both sides of the equation to make the left side a perfect-

square trinomial?
Mathematics
2 answers:
Andrei [34K]2 years ago
6 0

we have

x^{2} -\frac{3}{4}x=5

Divide the term  \frac{3}{4} by 2 and then square it

(\frac{(3/4)}{2})^{2}= \frac{9}{64}

Add to both sides

x^{2} -\frac{3}{4}x+\frac{9}{64}=5+\frac{9}{64}

Rewrite as perfect square

(x-\frac{3}{8})^{2}=\frac{329}{64}

therefore

<u>the answer is</u>

\frac{9}{64}

Kitty [74]2 years ago
4 0
Divide 3/4 by 2 and then square it. 3/4/2=3/8 squared which is 9/64.
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Answer:

The true statements are:

The rule for the translation can be written as T-3, 1(x, y). ⇒ 1st

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Step-by-step explanation:

Let us revise the rule of the translation:

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  • If the point (x , y) translated vertically down by k units  then its image is (x , y - k)

The vertices of trapezoid ABCD are:

A (-1 , -2) , B (1 , -2) , C (2 , -5) , D (-2 , -5)

The vertices Of trapezoid A'B'C'D' are:

A' (-4 , -1) , B' (-2 , -1) , C' (-1 , -4) , D' (-5 , -4)

Trapezoid ABCD is translated to form Trapezoid A'B'C'D'

By using the rules of translation above:

∵ A = (-1 , -2) and A' = (-4 , -1)

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∵ x = -1 and x + h = -4

∴ -1 + h = -4

- Add 1 to both sides

∴ h = -3

∵ y = -2 and y + k = -1

∴ -2 + k = -1

- Add 2 to both sides

∴ k = 1

The rule of translation is (x , y) → (x - 3 , y + 1)

The trapezoid ABCD has been translated 3 units to the left and 1 unit  up

You can check your answer by doing the same steps with the other 3 vertices you will have the same values of h and k

The true statements are:

The rule for the translation can be written as T-3, 1(x, y).

The rule for the translation can be written as  (x, y) → (x - 3, y + 1)

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