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natita [175]
1 year ago
13

A gift box has dimensions of: 8 1 2 inches, 5 1 2 inches, and 2 1 2 inches, respectively. how many cubes with side lengths of 1

2 inches would be needed to fill the gift box?
Mathematics
1 answer:
Mariulka [41]1 year ago
7 0
Number of 1/2-inch cubes length-wise = 8 1/2 ÷ 1/2 = 17
Number of 1/2-inch cubes width-wise = 5 1/2 ÷ 1/2 = 11
Number of 1/2-inch cubes height-wise = 2 1/2 ÷ 1/2 = 5

Number of 1/2-inch cubes = 17 x 11 x 5 = 935

------------------------------------------------------------
Answer: 935 1/2-inch cubes are needed.
------------------------------------------------------------

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If f(x) = 53 - 2x, then f(-3) =
zheka24 [161]
Substitute -3 for x in the expression

f(x)= 53 - 2x

f(-3)= 53 - 2(-3)
multiply -2 * -3

f(-3)= 53 + 6
add

f(-3)= 59


ANSWER: f(-3)= 59

Hope this helps! :)
4 0
2 years ago
Ray feeds his dog 0.12 kilogram of dry dog food each
Julli [10]

Answer:

The smallest bag that has enough food to feed his bag for one month

 = 3.6 kilogram

Step-by-step explanation:

The quantity of dry food Ray feeds his dog = 0.12 kilogram

So the quantity of food he feeds his dog in one month

    = 0.12 × 30              ∵ since 1 month = 30 days

    =  3.6 kilogram

The smallest bag that has enough food to feed his bag for one month

 = 3.6 kilogram

3 0
2 years ago
Trevon made 24of the 40 free throws he attempted last season. What percent of his attempted free throws did Trevon make?
I am Lyosha [343]

Answer: 60%

Step-by-step explanation: 24/40 = .6 x 100 = 60

6 0
2 years ago
The thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters. Determine the foll
Mrrafil [7]

Answer

given,

thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters.

X = U[0.95,1.05]           0.95≤ x ≤ 1.05

the cumulative distribution function of flange

F(x) = P{X≤ x}=\dfrac{x-0.95}{1.05-0.95}

                     =\dfrac{x-0.95}{0.1}

b) P(X>1.02)= 1 - P(X≤1.02)

                   = 1- \dfrac{1.02-0.95}{0.1}

                   = 0.3

c) The thickness greater than 0.96 exceeded by 90% of the flanges.

d) mean = \dfrac{0.95+1.05}{2}

              = 1

   variance = \dfrac{(1.05-0.95)^2}{12}

                  = 0.000833

4 0
2 years ago
Jacob has a bag of his favorite marbles. It has 3 red marbles, 4 blue, and 10 of his most favorite color, neon orange. What is t
drek231 [11]

Answer:

P(1\ and\ 2) = 0.3309

Step-by-step explanation:

Given

Red = 3

Blue = 4

Orange=10

Required

Probability of selecting 2 orange marbles

The total number of marbles is:

Total = Red + Blue + Orange

Total = 3 + 4 + 10

Total = 17

The probability that the first selection is orange is:

P(1) = \frac{10}{17}

Because it is a selection without replacement, the number of orange marbles and the total number of marbles would decrease by 1, respectively.

So, the probability that the selection is orange is:

P(2) = \frac{10-1}{17-1}

P(2) = \frac{9}{16}

The required probability is:

P(1\ and\ 2) = P(1) * P(2)

P(1\ and\ 2) = \frac{10}{17} * \frac{9}{16}

P(1\ and\ 2) = \frac{10*9}{17*16}

P(1\ and\ 2) = \frac{90}{272}

P(1\ and\ 2) = 0.3309

7 0
1 year ago
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