What is the pattern in the numbers? Rule: add 15, subtract 10 First term:4

1 answer:

8 0

Keep adding 5 to the first term as many times as you need. 15-10=5. So if you add 15 then subtract 10, you are really just adding 5 to 4 first =9,14,19, etc

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There are several ways you might think you could enter numbers in WebAssign, that would not be interpreted as numbers. N.B. Ther

Viefleur [7K]

Answer:

-4.99

1.9435

3.25E4

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Step-by-step explanation:

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2 years ago

hree TAs are grading a final exam. There are a total of 60 exams to grade. (a) How many ways are there to distribute the exams a

nalin [4]

Answer:

a. 205320

b. 34220

c. 60! / (35)! (25)! + 60!/ (40)!(20)! + 60!/ (45)! (15)!

Step-by-step explanation:

a) The number of ways to dustribute exams among the TA's is:

n / (n - r)!

n= number of things to choose from

r= Choosing r number

60P3= 60! / (60 - 3)!

(60)(59)(58)(57)! / (57)!

=205320

B) The number of ways to dustribute the exams among the TA's is:

n! /(n - r)! r!

60C3= 60! /(60 - 3)! 3!

= 60!/ 57! 3!

= 60 × 59 × 58 / 3 × 2 × 1

= 34220

C) The required number of ways is:

60C25 + 60C20 + 60C15

= 60! / (35)! (25)! + 60!/ (40)!(20)! + 60!/ (45)! (15)!

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2 years ago

Alejandro surveyed his classmates to determine who has ever gone surfing and who has ever gone snowboarding. Let A be the event

Gekata [30.6K]

Answer:

$\text{A and B are independent events}, P(A|B)=P(A)=0.16$

Step-by-step explanation:

First of all we need to know when does two events become independent:

For the two events to be independent, $P(A|B)=P(A)$ that is if condition on one does not effect the probability of other event.

Here, in our case the only option that satisfies the condition for the events to be independent is $P(A|B)=P(A)=0.16$ . Rest are not in accordance with the definition of independent events.