Answer:
1.95secs
Step-by-step explanation:
Given the height of the float expressed as h(t) = -16t2 - 3t + 55.
The floats reach the swimmer at h(t) = 0
Substitute
0 = -16t^2 - 3t + 55.
16t^2 + 3t - 55 = 0
Using the general formula;
t = -3±√3²-4(16)(-55)/2(16)
t = 3±√9+3520/32
t = 3±√3529/32
t = 3+59.41/32
t = 62.41/32
t = 1.95
Hence it will take 1.95secs
Answer:
a) Null and alternative hypotheses are:
: mu=183 days
: mu>183 days
b) If the true mean is 190 days, Type II error can be made.
Step-by-step explanation:
Let mu be the mean life of the batteries of the company when it is used in a wireless mouse
Null and alternative hypotheses are:
: mu=183 days
: mu>183 days
Type II error happens if we fail to reject the null hypothesis, when actually the alternative hypothesis is true.
That is if we conclude that mean life of the batteries of the company when it is used in a wireless mouse is at most 183 days, but actually mean life is 190 hours, we make a Type II error.
Find 25% of 52 first:
0.25 * 52 = 13
Now add this to the original amount:
52 + 13 = 65
So there are 65 companies after the increase.
Answer:
A sinusoidal model would be used
The kind of function that have consistency in the periodic rate of change is the Average rate of changes
Step-by-step explanation:
The type of model that would be used is sinusoidal model and this is because there is periodic change in the values given ( i.e the rate of changes given )
For percentage rate of changes :
starting from 0.9% there is an increase to 1.3% then a decrease to 1.1% and a further decrease to 1% before an increase to 1.3% and another decrease to 1%
For Average rate of changes:
starting from 2.9 there is a decrease to 2.4, then an increase to 3.7 and another decrease to 3.1 followed by an increase to 3.6 and a decrease back to 3.2
This relation ( sinusoidal model ) is best suited for a linear model because there is a periodic rate of change in the functions
The kind of function that have consistency in the period rate of change is the Average rate of changes
The answer is c. a selection of 80 students in the school
