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liubo4ka [24]
1 year ago
9

Pediatric asthma survey, n = 50. suppose that asthma affects 1 in 20 children in a population. you take an srs of 50 children fr

om this population. can the normal approximation to the binomial be applied under these conditions? if not, what probability model can be used to describe the sampling variability of the number of asthmatics?
Mathematics
1 answer:
zaharov [31]1 year ago
8 0
In this situation, 
n=50, p=1/20, q=(1-p)=19/20, and npq=19/8=2.4

We would like np and npq to be a large number, at least greater than 10.
The normal approximation can always be applied, but the result will be very approximate, depending on the values of np and npq.

Situations are favourable for the normal approximation when p is around 0.5, say between 0.3 and 0.7, and n>30.

"Normal approximation" is using normal probability distribution to approximate the binomial distribution, when n is large (greater than 70) or exceeds the capacity of most hand-held calculators.  The binomial distribution can be used if the following conditions are met:
1. Bernoulli trials, i.e. exactly two possible outcomes.2. Number of trials is known before and constant throughout the experiment, i.e. independent of outcomes.3. All trials are independent of each other.4. Probability of success is known, and remain constant throughout trials.
If all criteria are satisfied, we can model with binomial distribution, where the probability of x successes out of N trials each with probability of success p is given byP(x)=C(N,x)(p^x)(1-p)^(N-x)and,C(N,x) is number of combinations of selecting x objects out of N.
The mean is np, and variance is npq.

For the given situation, np=2.5, npq=2.375, so standard deviation=sqrt(2.375)=1.54.

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In arithmetic, variables look like _____.
yuradex [85]

The right answer is letters

Arithmetic is a branch of mathematics that studies the numbers and the properties with them. The main properties are addition, subtraction, multiplication and division. Variables are non-constant values, so we use letters to assign a number to a variable and the operator that allows us to do this is =. For instance, if we have the variable x, we can say that this variable is equal to 4. Then:


x=4


Suppose the value of the variable changes to 5, then the new value of it is given by:


x=5


6 0
2 years ago
I have to build a box for my scouting project with a volume of 36 cubic centimeters. The base of the box is 6 cm long and 2 cm w
Yakvenalex [24]
You should build your box 3 centimeters high. 

Volume =  Length x Width x Heigh

36 = 6 . 2 . X
36/6 = 2X
6= 2X
6/2 = X
3 = X

8 0
2 years ago
12. If a manufacturer conducted a survey among randomly selected target market households and wanted to be 95% confident that th
atroni [7]

Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11  

And rounded up we have that n=1068

Step-by-step explanation:

We have the following info given:

Confidence= 0.95 the confidence level desired

ME =0.03 represent the margin of error desired

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

The confidence level is 95% or 0.95, the significance is \alpha=0.05 and the critical value for this case using the normal standard distribution would be z_{\alpha/2}=1.96

Since we don't have prior information we can use \hat p= 0.5 as an unbiased estimator

Also we know that ME =\pm 0.03 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11  

And rounded up we have that n=1068

6 0
2 years ago
10 x 3 tens - unit form and standard form
vfiekz [6]
<span>10X3 tens in unit form is written:
10*3 tens = 30 tens = 300 units

10X3 tens in standard form:
10 x 3 tens = 10 x 30 = 300</span>
6 0
2 years ago
Read 2 more answers
In two or more complete sentences, describe the transformation(s) that take place on the parent function, f(x) = log(x), to achi
lubasha [3.4K]

Answer:

Shift 2 unit left

Flip the graph about y-axis

Stretch horizontally by factor 2

Shift vertically up by 2 units

Step-by-step explanation:

Given:

Parent function: f(x)=\log x

Transformation function: f(x)=\log(-2x-4)+2

Take -2 common from transform function f(x)

f(x)=\log[-2(x+2)]+2

Now we see the step-by-step translation

f(x)=\log x

Shift 2 unit left ( x → x+2 )

f(x)=\log(x+2)

Flip the graph about y-axis ( (x+2)  → - (x+2) )

f(x)=\log[-(x+2)]

Stretch horizontally by factor 2 [ -x(x+2) → -2(x+2) ]

f(x)=\log[-2(x+2)]

Shift vertically up by 2 units [ f(x) → f(x) + 2 ]

f(x)=\log[-2(x+2)]+2

Simplify the function:

f(x)=\log(-2x-4)+2

Hence, Using four step of transformation to get new function f(x)=\log(-2x-4)+2

3 0
2 years ago
Read 2 more answers
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