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Natalija [7]
2 years ago
5

If the product of two consecutive integers is decreased by 20 times the greater integer, the result is 442. find the integers

Mathematics
1 answer:
Contact [7]2 years ago
8 0
Let the first integer be x.  Then the next consecutive integer is x+1.

Translating the word problem into symbols, x(x+1)-20(x+1) = 442.

Then x^2 + x - 20x - 20 = 442

or      x^2 - 19x - 462 = 0

Solve by completing the square:

          x^2 - 19x + 90.25 - 90.25 - 462 = 0

           (x-9.5)^2 - 552.25 = 0

Taking the positive square root of both sides, we get x-9.5 = 23.5, or
                                                                                    x        = 33

The two consecutive integers are 33 and 34.

Check:  (33)(34)-20(34) = 442 (as expected).

            
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Answer:Obtain a systematic sample by selecting every 20th vehicle that passes (in any lane and going in any direction).

Step-by-step explanation:

8 0
2 years ago
The Taieri Plain in New Zealand is 6 feet below sea level (or –6 feet). If you are standing 3 feet above sea level, is your elev
Anna11 [10]
You would be 3ft above the sea level, if you are -6ft under the sea level and if you are standing 3ft “above” you would have to clime back up 9ft to get back to the positive’s which is “positive 3” so yes, your elevation will be opposite of the “plain” since you went to a -6 to a positive 3, with different numbers.
8 0
1 year ago
Which expression represents the product of 3 and (5/4n + 1.8)
SashulF [63]
Answer: D


you have to distribute
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3 0
1 year ago
Among all monthly bills from a certain credit card company, the mean amount billed was $465 and the standard deviation was $300.
Fynjy0 [20]

Answer:

0.02% probability that the average amount billed on the sample bills is greater than $500.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 465, \sigma = 300, n = 900, s = \frac{300}{\sqrt{900}} = 10.

What is the probability that the average amount billed on the sample bills is greater than $500?

This probability is 1 subtracted by the pvalue of Z when X = 500. So

Z = \frac{X - \mu}{s}

Z = \frac{500 - 465}{10}

Z = 3.5

Z = 3.5 has a pvalue of 0.9998.

So there is a 1-0.9998 = 0.0002 = 0.02% probability that the average amount billed on the sample bills is greater than $500.

8 0
2 years ago
Marie saved $3,000 dollars last year. She saved $600 in the month of January. What percent of the money she saved last year was
Archy [21]

Answer:

20% of the money was saved from January.

Here is the way to find percentage.

First: work out the difference (increase) between the two numbers you are comparing.

Increase = New Number - Original Number

Then:  divide the increase by the original number and multiply the answer by 100.

% increase = Increase ÷ Original Number × 100.

<u>Step-by-step explanation:</u>


5 0
2 years ago
Read 2 more answers
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