Assuming that the topping order is not important, you need to use the combination to solve this question. The number of toppings is 12 and then added 2, so the number will become: 12+2= 14 toppings
From 14 toppings, ian need to choose 3. The possible ways would be:
14C3= 14!/(14-3)!3!= 14*13*12/ 3*2= 364 possible ways
Answer:
a different inverse function
Step-by-step explanation:
If
then
is a different inverse function.
__
The second (inverse) function is the first reflected over the y-axis.
Answer:
<h2>The answer is 0.23(approx).</h2>
Step-by-step explanation:
The given die is a three sided die, hence, there are only three possibilities of getting the outcomes.
We need to find the probability of getting exactly 3s as the result.
From the sequence of 6 independent rolls, 2 rolls can be chosen in
ways.
The probability of getting two 3 as outcome is
.
In the rest of the 4 sequences, will not be any 3 as outcome.
Probability of not getting a outcome rather than 3 is
.
Hence, the required probability is
≅0.2966 or, 0.23.
Answer:
P(working product) = .99*.99*.96*.96 = .0.903
Step-by-step explanation:
For the product to work, all four probabilities must come to pass, so that
P(Part-1)*P(Part-2)*P(Part-3)*P(Part-4)
where
P(Part-1) = 0.96
P(Part-2) = 0.96
P(Part-3) = 0.99
P(Part-4) = 0.99
As all parts are independent, so the formula is P(A∩B) = P(A)*P(B)
P (Working Product) = P(Part-1)*P(Part-2)*P(Part-3)*P(Part-4)
P (Working Product) = 0.96*0.96*0.96*0.99*0.99
P(Working Product) = 0.903