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12345 [234]
2 years ago
6

As the number of pages in a photo book increases, the price of the book also increases. There is an additional shipping charge o

f 15%. The price of a book can be modeled by the equation below, where P = the price of the book, 20 is the printing charge, 0.5 is the charge per page, and x = the number of pages: (2 points)
P = (20 + 0.5x) + 0.15(20 + 0.5x)

Jennifer wants to purchase a book but only has $62.10 to spend. What is the maximum number of pages she can have in her book?
Mathematics
1 answer:
wlad13 [49]2 years ago
4 0

Answer:

22

Step-by-step explanation:

Solve the inequality  (20 + 0.5x) + 0.15(20 + 0.5x)   ≤ $62.10 for x:

20 + .5x + 3 + 0.75x ≤ 62.10

Combining the x terms, we get:

20 + 3 + 1.25x ≤ 62.10.

Combining the constants on the left:

23 + 1.75x ≤ 62.10

Combining the constants:

1.75x = 39.10

Solving for x:  39.10/1.75 = 22.34

Thus, the max number of whole pages she can have in her book is 22.

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satela [25.4K]

The <em><u>correct answer</u></em> is:

To graph each of these equations, we will find the x- and y-intercept of each. To find the x-intercept, we replace y with 0 and solve. To find the y-intercept, replace x with 0 and solve.

For 2x-4y=8:

x-intercept:

2x-4(0)=8; 2x-0=8; 2x=8; x=4

y-intercept:

2(0)-4y=8; 0-4y=8; -4y=8; y=-2

Plot these intercepts and draw a line between them.

For 2x+8y=-64:

x-intercept:

2x+8(0)=-64; 2x+0=-64; 2x=-64; x=-32

y-intercept:

2(0)+8y=-64; 0+8y=-64; 8y=-64; y=-8

Plot the intercepts and draw a line between them.

For -2x+4y=8:

x-intercept:

-2x+4(0)=8; -2x+0=8; -2x=8; x=-4

y-intercept:

-2(0)+4y=8; 0+4y=8; 4y=8; y=2

Plot the intercepts and draw a line between them.

For 3x+5y=-15:

x-intercept:

3x+5(0)=-15; 3x+0=-15; 3x=-15; x=-5

y-intercept:

3(0)+5y=-15; 0+5y=-15; 5y=-15; y=-3

Plot the intercepts and draw a line between them.

For 12x-3y=3:

x-intercept:

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y-intercept:

12(0)-3y=3; 0-3y=3; -3y=3; y=-1

Plot the intercepts and draw a line between them.

For y=-8, draw a straight horizontal line at -8.

For x+3y=18:

x-intercept:

x+3(0)=18; x+0=18; x=18

0+3y=18; 3y=18; y=6

Plot the intercepts and draw a line between them.

For -4x+6y=-54:

x-intercept:

-4x+6(0)=-54; -4x+0=-54; -4x=-54; x=13.5

y-intercept:

-4(0)+6y=-54; 0+6y=-54; 6y=-54; y=-9

Plot the intercepts and draw a line between them.

For 4x-y=-8:

x-intercept:

4x-0=-8; 4x=-8; x=-2

y-intercept:

4(0)-y=-8; 0-y=-8; -y=-8; y=8

Plot the intercepts and draw a line between them.

For 2x-10y=20:

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y-intercept:

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Plot the intercepts and draw a line between them.

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x-intercept:

6x+9(0)=9; 6x+0=9; 6x=9; x=1.5

y-intercept:

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Plot the intercepts and draw a line betwen them.

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Plot the intercepts and draw a line between them.

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On a certain​ route, an airline carries 7000 passengers per​ month, each paying ​$30. A market survey indicates that for each​ $
KengaRu [80]

Answer:

The ticket price that maximizes revenue is $50.

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Step-by-step explanation:

We have to write a function that describes the revenue of the airline.

We know one point of this function: when the price is $30, the amount of passengers is 7000.

We also know that for an increase of $1 in the ticket price, the amount of passengers will decrease by 100.

Then, we can write the revenue as the multiplication of price and passengers:

R=p\cdot N=(30+x)(7000-x)

where x is the variation in the price of the ticket.

Then, if we derive R in function of x, and equal to 0, we will have the value of x that maximizes the revenue.

R(x)=(30+x)(7000-100x)=30\cdot7000-30\cdot100x+7000x-100x^2\\\\R(x)=-100x^2+(7000-3000)x+210000\\\\R(x)=-100x^2+4000x+210000\\\\\\\dfrac{dR}{dx}=100(-2x)+4000=0\\\\\\200x=4000\\\\x=4000/200=20

We know that the increment in price (from the $30 level) that maximizes the revenue is $20, so the price should be:

p=30+x=30+20=50

The maximum monthly revenue is:

R(x)=(30+x)(7000-100x)\\\\R(20)=(30+20)(7000-100\cdot20)\\\\R(20)=50\cdot5000\\\\R(20)=250000

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2 years ago
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earnstyle [38]

Answer:

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Shawn:

h = 270 ft

d = √(3 * 270/2) = √405 = √(81 * 5) = √81 * √5 = 9√5 mi

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2 years ago
Which of the following proportions can be used to prove AE || DK in the proof below? Select all that apply.
Galina-37 [17]

Answer: DA:FA=KE:EF, DF:DA=KF:KE and FA:DA=EF:KE are correct.

Explanation: Since, \triangle EFA and \triangle KFD are similar triangles.

Because, \angle FAE= \angle FDK and \angle FEA= \angle FKD (because EA and KD are parallels. And, \angle F is common angle for these triangles.

Therefore, according to the property of similar triangles.

FE:EK= FA:AD, FE:FK=FA:FD and DF:DA=KF:KE .

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1 year ago
Read 2 more answers
The population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard dev
Vladimir [108]

Answer:

Probability that the average length of a sheet is between 30.25 and 30.35 inches long is 0.0214 .

Step-by-step explanation:

We are given that the population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard deviation of 0.2 inches.

Also, a sample of four metal sheets is randomly selected from a batch.

Let X bar = Average length of a sheet

The z score probability distribution for average length is given by;

                Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean = 30.05 inches

           \sigma   = standard deviation = 0.2 inches

             n = sample of sheets = 4

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P(30.25 inches < X bar < 30.35 inches)  = P(X bar < 30.35) - P(X bar <= 30.25)

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Therefore, P(30.25 inches < X bar < 30.35 inches)  = 0.99865 - 0.97725

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