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RideAnS [48]
2 years ago
15

The linear function graphed below represents the value of a comic book since Lucy purchased it. What was the value of the comic

book when Lucy bought it?

Mathematics
2 answers:
zhuklara [117]2 years ago
8 0

Answer:

C. $25

Step-by-step explanation:

We will find,

The slope of the function using \frac{y_{2}-y_{1}}{x_{2}-x_{1}}.

Taking the points (1,40) and (2,55).

Slope = \frac{55-40}{2-1}

i.e. Slope = \frac{15}{1}

i.e. Slope = 15

Substituting the slope and point (1,40) in the equation y=mx+b,

We have, 40=15\times 1+b

i.e. b=40-15

i.e. b= 25

Thus, the equation of the linear function is y=15x+25.

<em>This linear function represents the cost of the comic book since Lucy purchased it, where x= years.</em>

So, the initial value of the comic book is when x= 0.

So, y=15\times 0+25 i.e. y= 25

Hence, the cost of the book when Lucy purchased it was $25.

tatyana61 [14]2 years ago
4 0

Answer:

The answer be 25

Step-by-step explanation:

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A running coach wants to know if participating in weekly running clubs significantly improves the time to run a mile. The runnin
patriot [66]

Answer:

Option B is correct.

Use the difference in sample means (10 and 8) in a hypothesis test for a difference in two population means.

Step-by-step Explanation:

The clear, complete table For this question is presented in the attached image to this solution.

It should be noted that For this question, the running coach wants to test if participating in weekly running clubs significantly improves the time to run a mile.

In the data setup, the mean time to run a mile in January for those that participate in weekly running clubs and those that do not was provided.

The mean time to run a mile in June too is provided for those that participate in weekly running clubs and those that do not.

Then the difference in the mean time to run a mile in January and June for the two classes (those that participate in weekly running clubs and those that do not) is also provided.

Since, the aim of the running coach is to test if participating in weekly running clubs significantly improves the time to run a mile, so, it is logical that it is the improvements in running times for the two groups that should be compared.

Hence, we should use the difference in sample means (10 and 8) in a hypothesis test for a difference in two population means.

Hope this Helps!!!

7 0
2 years ago
Marlene rides her bike at a rate of 16 miles per hour. The time in hours that she rides is represented by the variable t, and th
White raven [17]

Let

t--------> the time in hours

d-------> the distance in miles

we know that

d=16t

this is a linear equation that represent the scenario

in this equation the independent variable is the time t and the dependent variable is the distance d

The distance's equation in function notation is equal to

f(t)=16t

Using a graph tool

see the attached figure

The domain of the function is the interval----------> [0,∞)

t\geq0

The range of the function is the interval------->  [0,∞)

f(t)\geq0

<u>Statements</u>

<u>a) The independent variable, the input, is the variable d, representing distance</u>

The statement is false

Because the  independent variable is the variable t

<u>b) The distance traveled depends on the amount of time Marlene rides her bike</u>

The statement is true

Because the distance's equation in function notation is equal to

f(t)=16t

<u>c) The initial value of the scenario is 16 miles per hour</u>

The statement is false

Because 16 represent the rate or  the slope of the linear equation

<u>d) The equation t = d + 16 represents the scenario</u>

The statement is false

Because, the scenario is represented by the function f(t)=16t

<u>e) The function f(t) = 16t represents the scenario</u>

The statement is true

8 0
2 years ago
Read 2 more answers
Jordan had the following scores on her math tests last quarter: 96, 89, 79, 85, 87, 94,
Lisa [10]

Answer:

a) 5.5

b) None

Step-by-step explanation:

The given data set is {96,89,79,85,87,94,96,98}

First we must find the mean.

\bar X=\frac{96+89+79+85+87+94+96+98}{8}=\frac{724}{8}=90.5

We now find the absolute value of the distance of each value from the mean.

This is called the absolute deviation

{|96-90.5|,|89-90.5|,|79-90.5|,|85-90.5|,|87-90.5|,|94-90.5|,|96-90.5|,|98-90.5|}

{5.5,1.5,11.5,5.5,3.5,3.5,5.5,7.5}

We now find the mean of the absolute deviations

MAD=\frac{5.5+1.5+11.5+5.5+3.5+3.5+5.5+7.5}{8} =\frac{44}{8} =5.5

The least absolute deviation is 1.5. This is not within one absolute deviation.

Therefore none of the data set is closer than one mean absolute deviation away from  the mean.

5 0
2 years ago
Sheryl creates a scatter plot to analyze how an increase in the outside temperature above 52°F affects the sale of hot chocolate
lora16 [44]

Answer:

1 and 2

Step-by-step explanation:

3 0
2 years ago
Line JM intersects line GK at point N. Which statements are true about the figure? Check all that apply.
ki77a [65]
See attached image

First, we must know this: Complementary angles are two angles whose sum is equal to 90°, while supplementary angles are two angles whose sum is equal to 180°. That been said, the only statement which is true is the second statement, <span>MNL is complementary to KNL

Reasons why others are False
</span>GNJ is supplementary to JNK, not complementary
MNG is supplementary to GNJ, not complementary
LNJ (not KNJ) <span>is supplementary to MNL
</span>GNM is equal to JNK, not supplementary

8 0
2 years ago
Read 2 more answers
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