Let:
x = hours of travel
y = velocity
slope= rise/run slope=(y2-y1)/(x2-x1)
(x1,y1) = (2,50) (x2,y2) = (6,54)
sub values back into the equation m = (54-50)/(6-2) m = 1
POINT SLOPE FORMy-y1 = m(x-x1) y-50= 1(x-2) y = x -2 +50
y = x + 48
B)
the graph within the first seven hours can be obtained at point B
x = 7
y = 7+48 = 55
B(7,55)
Given parameters:
Bearing of the tree from the house = 295°
Unknown:
Bearing of the house from the tree = ?
Solution:
This is whole circle bearing problem(wcb). There are different ways of representing directions from one place to another. In whole circle bearing, the value of the bearing varies from 0° to 360° in the clockwise direction.
To find the back bearing in this regard, simple deduct the forward bearing from 360°;
Backward bearing = 360° -295°
= 65°
The bearing from house to the tree is 65°
Answer:
D is the correct answer.
Step-by-step explanation:
We have been given two polynomials 
Let us first multiply these polynomials.
Now, we know that polynomials follows closure property of multiplication.
It means that when we multiply two polynomials, the result will be a polynomial.
Since, when we multiplied the given polynomials, we got 
which is a polynomial.
Therefore, the correct option is
The result is a polynomial.
I just had this test and got it right, the answer is 1 term with a degree of 5. Option 4
