Let the no. Of boys=x and that of girls=y.
The total no. Of students = x+y .
As given by statement the no. Of boys=x={(x+y)/3} + 5
This implies that
X=(x+y+15)/3
Also we know that x/y = 2/3 therefore
From this equation we get x=2y/3 and y=3x/2
By method of substitution we get
X=(x+3x/2+15)/3
•x=(15x+90)/2
•2x=15x+90
•-13x=90
X= -90/13
Now. Y= 3x/2=-270/26
Therefore total
no. Of students= -270/26+(-90/13)
•no. Of students= -450/26
According to me this is an imaginary question i mean how can their be a negative person
Answer:
The numbers of doors that will have no blemishes will be about 6065 doors
Step-by-step explanation:
Let the number of counts by the worker of each blemishes on the door be (X)
The distribution of blemishes followed the Poisson distribution with parameter 
/ door
The probability mass function on of a poisson distribution Is:
The probability that no blemishes occur is :
P(X=0) = 0.6065
Assume the number of paints on the door by q = 10000
Hence; the number of doors that have no blemishes is = qp
=10,000(0.6065)
= 6065
The third table
Explanation:
6/4 = 1.5 , 9/6 = 1.5 , 12/8 = 1.5
Answer:Answer:a) Area=f(x)= 24x-x^2
b) f(x) ranges from 0 to 144
c) Area max = 144 ft^2
Step-by-step explanation: shown in the attachment
Answer:
The probability that they are both male is 0.424 (3 d.p.)
Step-by-step explanation:
The first step is to find the probability of the first selection being male. This is calculated as number of male mice divided by total number of mice in the litter
Prob (1st male) = 8 ÷ 12 = 0.667
Next is to find the probability of the second selection also being male. Note that the question states that the first mice was selected without replacement. This means the first mouse taken results in a reduction in both the number of male mice and total number of mice in the litter.
Prob (2nd male) = (8 - 1) ÷ (12 - 1) = 7/11 = 0.636
Therefore,
Prob (1st male & 2nd male) = 0.667 × 0.636 = 0.424
