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2 years ago

triangle JKL is rotated 270 degrees counterclockwise about the origin to form triangle jkl what is the y-coordinate of point j

Mathematics

1 answer:

IRINA_888 [86]2 years ago

5 0

The y-coordinate of point j' in the image triangle J'K'L' is -x coordinate of point j in the initial triangle JKL.

Step-by-step explanation:

The rule to apply here is that of 90° clockwise about the origin.

This is to say that: rotation 270° counterclockwise about the origin applies the same rule as rotation 90° clockwise about the origin.

In this case, If point j has coordinates (x,y) then after the rotation j' will have coordinates (y,-x)

So the y-coordinate of point j' in the image triangle J'K'L' is -x coordinate of point j in the initial triangle JKL.

Learn more

Rotation about the origin 270°:brainly.com/question/3382538

Keywords : triangle, rotated, origin, counterclockwise,y-coordinate

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A set of speakers costs $22 and songs cost $1.25 each. The sales tax rate is 7.5%. The expression 0.075(22 + 1.25s) can be used

kykrilka [37]

Answer:

1.65 + 0.09s

Step-by-step explanation:

Given that :

Cost of speaker = $22

Cost per song = $1.25

Sales tax rate = 7.5%

Expression to obtain the amount of sales tax on entire purchase : 0.075(22 + 1.25s)

Expanding the expression :

0.075(22 + 1.25s)

(0.075 * 22) + (0.075 * 1.25s)

1.65 + 0.09375s

Rounding to the nearest hundredth :

Sales tax on entire purchase :

1.65 + 0.09s

4 0

1 year ago

Point F is on circle C. What is the length of line segment GF? 12.5 units 15.0 units 17.5 units 20.0 units

geniusboy [140]

The answer:
According to the image, <span>the length of line segment GF can be found with
</span>GF= GC +CF
CF is one the radius, so CF=7.5
to find GC, we can apply Pythagorean theorem on the right triangle GEC
it is
GC² =GE² + EC² = 10² +7.5² =156.25, and then GC= sqrt(156.25)=12.5

therefore, GF= GC +CF=12.5+7.5=20

so the answer is <span>20.0 units</span>

7 0

2 years ago

Sal's Sandwich Shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2 and the profit

kifflom [539]

This is a very long question. I'm not going to write all of it out but I will give you a starting point. Find your x by making y in the formula equal to 0.

2x + 3y = 1470

2x + 3(0) = 1470

2x = 1470

x = 735

Your furthest point on the x axis is (735,0).

Do the same for y.

2x + 3y = 1470.

2(0) + 3y = 1470

3y= 1470

y= 490

Your highest point is (0,490).

Now that both are plotted, draw a straight line connecting the two points. There's your graph.

Check

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2 years ago

The results of a mathematics placement exam at two different campuses of Mercy College follow: Campus Sample Size Sample Mean Po

Leona [35]

Answer:

$z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37$

$p_v =P(Z>3.37)=1-P(Z$

Comparing the p value with a significance level for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.

Step-by-step explanation:

Data given

Campus Sample size Mean Population deviation

1 330 33 8

2 310 31 7

$\bar X_{1}=33$ represent the mean for sample 1

$\bar X_{2}=31$ represent the mean for sample 2

$\sigma_{1}=8$ represent the population standard deviation for 1

$\sigma_{2}=7$ represent the population standard deviation for 2

$n_{1}=330$ sample size for the group 1

$n_{2}=310$ sample size for the group 2

$\alpha$ Significance level provided

z would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the mean for Campus 1 is higher than the mean for Campus 2, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}\leq 0$

Alternative hypothesis: $\mu_{1} - \mu_{2}> 0$

We have the population standard deviation's, and the sample sizes are large enough we can apply a z test to compare means, and the statistic is given by:

$z=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:

$z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37$

P value

Since is a one right tailed test the p value would be:

$p_v =P(Z>3.37)=1-P(Z$

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2 years ago

HELP MEEEEEEEEEE Package A contains 3 birthday cards and 2 thank-you notes and costs $9.60. Package B contains 8 birthday cards

hodyreva [135]

Answer:

Each birthday card costs $2.2 ⇒ answer c

Step-by-step explanation:

* Lets explain how to solve the problem

- Package A contains 3 birthday cards and 2 thank-you notes

- It costs $9.60

- Package B contains 8 birthday cards and 6 thank-you notes

- It costs $26.60

- x represents the cost of birthday card and y represents the cost of

thank-you note

* Lets change these information to two equations

∵ x represents the cost of each birthday cards

∵ y represents the cost of each thank-you notes

∵ Bag A contains 3 birthday cards and 2 thank-you notes

∵ Bag A costs $9.60

∴ 3x + 2y = 9.60 ⇒ (1)

∵ Bag B contains 8 birthday cards and 6 thank-you notes

∵ Bag B costs $26.60

∴ 8x + 6y = 26.60 ⇒ (2)

* Lets solve this system of equations to find x and y

- Multiply equation (1) by -3 to eliminate y

∵ -3(3x) + -3(2y) = -3(9.60)

∴ -9x - 6y = -28.8 ⇒ (3)

- Add equations (2) and (3)

∴ -x = -2.2

- Multiply both sides by -1

∴ x = 2.2

∵ x represents the cost of each birthday cards

∴ The cost of each birthday card is $2.2

* Each birthday card costs $2.2

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2 years ago

Read 2 more answers