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1 year ago

triangle JKL is rotated 270 degrees counterclockwise about the origin to form triangle jkl what is the y-coordinate of point j

Mathematics

1 answer:

IRINA_888 [86]1 year ago

5 0

The y-coordinate of point j' in the image triangle J'K'L' is -x coordinate of point j in the initial triangle JKL.

Step-by-step explanation:

The rule to apply here is that of 90° clockwise about the origin.

This is to say that: rotation 270° counterclockwise about the origin applies the same rule as rotation 90° clockwise about the origin.

In this case, If point j has coordinates (x,y) then after the rotation j' will have coordinates (y,-x)

So the y-coordinate of point j' in the image triangle J'K'L' is -x coordinate of point j in the initial triangle JKL.

Learn more

Rotation about the origin 270°:brainly.com/question/3382538

Keywords : triangle, rotated, origin, counterclockwise,y-coordinate

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4. Hydrocarbons in the cab of an automobile were measured during trips on the New Jersey Turnpike and trips through the Lincoln

pochemuha

Answer:

No these these result do not differ at 95% confidence level

Step-by-step explanation:

From the question we are told that

The first concentrations is $c _1= 30.0 \ g/m^3$

The second concentrations is $c _2 = 52.9 \ g/m^3$

The first sample size is $n_1 = 32$

The second sample size is $n_2 = 32$

The first standard deviation is $\sigma_1 = 30.0$

The first standard deviation is $\sigma_1 = 29.0$

The mean for Turnpike is $\= x _1 = \frac{c_1}{n} = \frac{31.4}{32} = 0.98125$

The mean for Tunnel is $\= x _2 = \frac{c_2}{n} = \frac{52.9}{32} = 1.6531$

The null hypothesis is $H_o : \mu _1 - \mu_2 = 0$

The alternative hypothesis is $H_a : \mu _1 - \mu_2 \ne 0$

Generally the test statistics is mathematically represented as

$t = \frac{\= x_1 - \= x_2}{ \sqrt{\frac{\sigma_1^2}{n_1} +\frac{\sigma_2^2}{n_2} }}$

$t = \frac{0.98125 - 1.6531}{ \sqrt{\frac{30^2}{32} +\frac{29^2}{32} }}$

$t = - 0.0899$

Generally the degree of freedom is mathematically represented as

$df = 32+ 32 - 2$

$df = 62$

The significance $\alpha$ is evaluated as

$\alpha = (C - 100 )\%$

=> $\alpha = (95 - 100 )\%$

=> $\alpha =0.05$

The critical value is evaluated as

$t_c = 2 * t_{0.05 , 62}$

From the student t- distribution table

$t_{0.05, 62} = 1.67$

$t_c = 2 * 1.67$

=> $t_c = 3.34$

given that

$t_c > t$ we fail to reject the null hypothesis so this mean that the result do not differ

6 0

1 year ago

Consider all seven-digit numbers that can be created from the digits 0-9 where the first and last digits must be odd and no digi

Natali [406]

Answer:

Considering all seven-digit numbers that can be created from the digits 0-9 I could deduce that you can make 100 , 700, 800 even infinite numbers

6 0

1 year ago

A three-digit number ends in number 7. If you put the number 7 in the first position, the number will increase by 324. Find the

liq [111]

Answer:

The original three-digit number is 417

Step-by-step explanation:

Let's find out the solution to this problem, this way:

x = the two digits that are not 7

Original number = 10x+7

The value of the shifted number = 700 + x

Difference between the shifted number and the original number = 324

Therefore, we have:

324 = (700 + x) - (10x + 7)

324 = 700 + x - 10x - 7

9x = 693 - 324 (Like terms)

9x = 369

x = 369/9

x = 41

The original three-digit number is 417

5 0

1 year ago

Paul is going to have the exterior of his home painted. Painting USA charges $75.00 to come out and evaluate the house plus $25.

murzikaleks [220]

CP - the cost of painting the house for Painting USA company [$]
cP = 75 + 25 * 25 = 75 + 625 = 700 [$]
cU - the cost of painting the house for Upscale Home Painting company [$]
cU = 0 + 40 * 25 = 1000 [$]

cP < cU
The most cost effective is Painting USA company.

n - number of houres required to paint the house if the same cost for both companies
75 + 25 * n = 40 * n
40 n - 25n = 75
15n = 75 /:15
n = 5
The cost of paining the house is the same for both companies if the number of houres required to paint the house is 5.

6 0

2 years ago

Davison Electronics manufactures two LCD television monitors, identified as model A andmodel B. Each model has its lowest possib

shtirl [24]

The question is incomplete. The complete question is :

Davison Electronics manufactures two LCD television monitors, identified as model A and model B. Each model has its lowest possible production cost when produced on Davison’s new production line. However, the new production line does not have the capacity to handle the total production of both models. As a result, at least some of the production must be routed to a higher-cost, old production line. The following table shows the minimum production requirements for next month, the production line capacities in units per month, and the production cost per unit for each production line:

Production per unit Minimum production

Model New Line Old Line requirements

A $30 $50 50,000

B $25 $40 70,000

Production 80000 60000

line capacity.

Let

AN- Units of model A produced on the new production line

AO Units of model A produced on the old production line

BN Units of model B produced on the new production line

BO Units of model B produced on the old production line

Davison's objective is to determine the minimum cost production plan. The computer solution is shown in Figure 3.21.

a. Formulate the linear programming model for this problem using the following four constraints:

Constraint 1: Minimum production for model A

Constraint 2: Minimum production for model B

Constraint 3: Capacity of the new production line

Constraint 4: Capacity of the old production line

Solution :

Linear programming model:

Linear programming is defined as a mathematical model where the linear function is either minimize or maximize when they are subjected to some constraints.

The linear programming model is determined as follows :

Minimum : 30 AN + 50 AO + 25 BN + 40 BO

This is subject to the constraints as :

$AN+AO \geq 60,000$