Answer:
1st: consistent and dependent
2nd: (-2,0). Simply put the called and check.
P = It is a weekend
Q = I will exercise
If "It is a weekend", then "I will exercise"
But "It is NOT a weekend"
Therefore, "I will NOT exercise"
Using P and Q our statement would look like this,
If P, then Q
But not P
Therefore not Q
Or symbolically like this:
P -> Q
~P

~Q
I'm sorry that this doesn't match up with the options you posted.
Maybe they didn't paste correctly.
C
.) The - 3 at the end of the function means the function is shifted down 3 units. This also shifts the asymptote down 3 units.
Answer:
7.1 weeks to 68.4 weeks
Step-by-step explanation:
Chebyshev's Theorem states that:
75% of the measures are within 2 standard deviations of the mean.
89% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 38.1
Standard deviation = 10.1
Between what two search times does Chebyshev's Theorem guarantee that we will find at least 89% of the graduates
Between 3 standard deviations of the mean.
So from 38.1 - 3*10.1 = 7.8 weeks to 38.1 + 3*10.1 = 68.4 weeks