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Elenna [48]
2 years ago
12

Suppose in the next year, 2007, College D's expenses and enrollment remain about the same, but in addition to their current reve

nues, they receive an additional $50,000,000 grant. This would allow them to reduce average tuition by how much?
Mathematics
1 answer:
Olin [163]2 years ago
7 0

This question is incomplete, here is the complete question:

Suppose in the next year, 2007, College D's expenses and enrollment remain about the same, but in addition to their current revenues, they receive an additional $50,000,000 grant. This would allow them to reduce average tuition by how much?

A) $1388.89

B) $3571.43

C) $5555.56

D) $9500.00

E) $25888.89

number of students = 36,000

Answer: A) $

1388.89

Step-by-step explanation:

the college received additional grant which is $50,000,000

and the number of students is 36,000,

and we also know that expenses and enrollment remained the same.

So if we have more money (grants) and nothing changed (expenses remain the same)

dividing the grant by the number of students will show just how much the average tuition fee would be reduced

therefore R = G/n

R = 50,000,000 / 36000

R = 1,388.888 ≈  $1388.89

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A consulting firm has received 2 Super Bowl playoff tickets from one of its clients. To be fair, the firm is randomly selecting
Soloha48 [4]

Answer:

Therefore the only statement that is not true is b.)

Step-by-step explanation:

There employees are 6 secretaries, 5 consultants and 4 partners in the firm.

a.) The probability that a secretary wins in the first draw

= \frac{number \hspace{0.1cm} of \hspace{0.1cm} secreataries}{total \hspace{0.1cm} number \hspace{0.1cm} of \hspace{0.1cm} employees}  = \frac{6}{15}

b.) The probability that a secretary wins a ticket on second draw.  It has been given that a ticket was won on the first draw by a consultant.

p(secretary wins on second draw | consultant  wins on first draw)

=\frac{p((consultant \hspace{0.1cm} wins \hspace{0.1cm} on \hspace{0.1cm} first \hspace{0.1cm}draw)\cap( secretary\hspace{0.1cm} wins\hspace{0.1cm} on second \hspace{0.1cm}draw))}{p(consultant \hspace{0.1cm} wins \hspace{0.1cm} on \hspace{0.1cm} first \hspace{0.1cm}draw)}

= \frac{\frac{5}{15}  \times \frac{6}{14}}{\frac{5}{15} }  = \frac{6}{14}  .

The probability that  a ticket was won on the first draw by a consultant a secretary wins a ticket on second draw  = \frac{6}{15} is not true.

The probability that a secretary wins on the second draw  = \frac{number \hspace{0.1cm} of  \hspace{0.1cm} secretaries  \hspace{0.1cm} remaining } { number  \hspace{0.1cm} of  \hspace{0.1cm} employees  \hspace{0.1cm} remaining}  = \frac{6 - 1}{15 - 1}  = \frac{5}{14}

c.) The probability that a consultant wins on the first draw  =

\frac{number \hspace{0.1cm} of  \hspace{0.1cm} consultants  \hspace{0.1cm}  } { number  \hspace{0.1cm} of  \hspace{0.1cm} employees  \hspace{0.1cm} }  = \frac{5 }{15}  = \frac{1}{3}

d.) The probability of two secretaries winning both tickets

= (probability of a secretary winning in the first draw) × (The probability that a secretary wins on the second draw)

= \frac{6}{15}  \times \frac{5}{14}  = \frac{1}{7}

Therefore the only statement that is not true is b.)

5 0
2 years ago
The weight of trucks traveling on a particular section of I-475 have a population mean of 15.8 tons and a population standard de
Ray Of Light [21]

Answer: 0.0062

Step-by-step explanation:

Given : The weight of trucks traveling on a particular section of I-475 have a population mean of \mu=15.8 tons and a population standard deviation of \sigma=4.2 tons.

Sample size : n=49

Let x be the random variable that represents the weight of trucks .

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For x= 14.3 tons

z=\dfrac{14.3-15.8}{\dfrac{4.2}{\sqrt{49}}}\approx-2.5

Now, the probability a state highway inspector could select a sample of 49 trucks and find the sample mean to be 14.3 tons or less will be :-

P(X\leq14.3)=P(z

Hence, the probability a state highway inspector could select a sample of 49 trucks and find the sample mean to be 14.3 tons or less =0.0062

8 0
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Carla's fixed cot will be given by:
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Since the temperature dropping, the slope of 4 is negative.

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2 years ago
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