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PSYCHO15rus [73]
2 years ago
5

An epidemiologist found five cases of "big toe cancer" in the Yukon Territory. Because there were only a few cases, the epidemio

logist decided to conduct a matched case-control study to determine whether shoe size larger than 9 is a risk factor for big toe cancer. Cases were individually matched to one control for daily activity, history of athlete’s foot, and history of ingrown toenails. The following data were gathered:
Shoe size > 9
Pair Case Control
1 Yes No
2 No No
3 No Yes
4 Yes Yes
5 No Yes
Compute the proper measure of association.
Interpret your results.
If you were to investigate a rare cancer in Lynchburg, where might you look for data?
What would be necessary legally and ethically to be able to utilize this data set(s)?
Submit your thread by 11:59 p.m. (ET) on Thursday of Module/Week 3, and submit your replies by 11:59 p.m. (ET) on Sunday of the same module/week.
Mathematics
1 answer:
bulgar [2K]2 years ago
6 0

Answer:

Step-by-step explanation:

Given that:

An epidemiologist found five cases of "big toe cancer" in the Yukon Territory.

Therefore, shoe size > 9

1) From the required data given below

                       <u>Case       Control       Total</u>

Yes                2(a)             3(b)            5

No                  3(c)             2(d)            5

Total               5                 5                10

∴ odds ratio = ad/bc

= 4/9

=0.444

2) From the less than 1.0 mean that the odds of cancer among case is lower than the odds of cancer among controls

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J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
2 years ago
Mr. Gonzales has only $42.50 to spend at a clothing store. He wants to buy a shirt that costs $29, including tax, and some brace
lisabon 2012 [21]

Answer: The equation is $29 + x*$4.50 = $42.50, and the solution is x = 3

Step-by-step explanation:

The data we have is:

Gonzales has $42.50

He wants to buy:

a shirt that costs $29

some bracelets that cost $4.50 each.

The equation that we need to solve is:

Total cost = money that Gonzales has.

The cost is $29 + x*$4.50

where x is the number of bracelets he can buy.

The equation that we need to solve is:

$29 + x*$4.50 = $42.50

to solve it we must isolate x:

x*$4.50 = $42.50 - $29 = $13.50

x = 13.50/4.50 = 3

So we have that Mr. Gonzales can buy a total of 3 bracelets.

8 0
2 years ago
Read 2 more answers
Byron has 1 7/10 kilograms of black pepper. He uses 7/8 of the black pepper and splits between 7 pepper shakers. How much pepper
IrinaVladis [17]
Amount of black pepper = 1 7/10 kg = 17/10 kg.
Amount used is
(7/8)*(17/10) = 119/80 kg

This amount is split between 7 shakers. Each shaker has
(119/80)/7 = 17/80 kg = 0.2125 kg

Answer: 17/80 kg (or  0.2125 kg)
4 0
2 years ago
The pilot in a helicopter tossed a life float down to a swimmer in the water. The height, h, of the float after time t seconds i
MissTica

Answer:

1.95secs

Step-by-step explanation:

Given the height of the float expressed as h(t) = -16t2 - 3t + 55.

The floats reach the swimmer at h(t) = 0

Substitute

0 = -16t^2 - 3t + 55.

16t^2 + 3t - 55 = 0

Using the general formula;

t = -3±√3²-4(16)(-55)/2(16)

t = 3±√9+3520/32

t = 3±√3529/32

t = 3+59.41/32

t = 62.41/32

t = 1.95

Hence it will take 1.95secs

4 0
1 year ago
If f Superscript negative 1 Baseline (x) = negative one-fifth x, what is f Superscript negative 1 Baseline (x) = one-fifth x?
Artyom0805 [142]

Answer:

  a different inverse function

Step-by-step explanation:

If f^{-1}(x)=-\frac{1}{5}x then f^{-1}(x)=\frac{1}{5}x is a different inverse function.

__

The second (inverse) function is the first reflected over the y-axis.

5 0
2 years ago
Read 2 more answers
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