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aalyn [17]
2 years ago
6

If the egress rate for a stadium is 5,500 fans per hour and it takes fans about one-third less time for fans to exit a game as i

t does for them to enter and find their seats, what is the ingress rate? (Round up to a whole number.)
Mathematics
2 answers:
Mumz [18]2 years ago
8 0

Answer:

16,500\frac{fans}{hour}

Step-by-step explanation:

<h3>Givens:</h3>
  • Egress rate is 5,500 fans per hour.
  • Egress rate is one-third than ingress rate. In other words, the ingress rate is 3 times faster than the egress rate. This interpretation is what solves this problem. It's the needed relation to answer the question.

Now, we have to express this in math, to calculate:

Egress=5,500\frac{fans}{hour}

Egress=\frac{1}{3}Ingress

Now, we replace and solve for Ingress:

5,500\frac{fans}{hour}=\frac{1}{3}Ingress\\Ingress=3(5,500\frac{fans}{hour})\\Ingress=16,500\frac{fans}{hour}

Therefore, based on the givens, the ingress rate is 16,500\frac{fans}{hour}

Marina CMI [18]2 years ago
4 0

Answer:

1833 fans per hour

Step-by-step explanation:

Ingress is entering and Egress is exiting.

Since exiting time is 1/3rd less than entering time, we have 5500 people exiting, so ingessing would be 1/3rd that.

Thus,

Ingress Rate = 5500/3 = 1833.33

Rounding to whole number, we have 1833 fans per hour

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Answer: 30

Step-by-step explanation:

Given :The weight of a bag of golf balls varies directly as the number of golf balls in the bag.

Let x be the number of golf balls in a bag that weighs 1,110 grams.

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2 years ago
Three out of seven students in the cafeteria line are chosen to answer survey questions. How many different combinations of thre
Andreyy89

Answer:

The number of different combinations of three students that are possible is 35.

Step-by-step explanation:

Given that three out of seven students in the cafeteria line are chosen to answer a survey question.

The number of different combinations of three students that are possible is given as:

7C3 (read as 7 Combination 3)

xCy (x Combination y) is defines as

x!/(x-y)!y!

Where x! is read as x - factorial or factorial-x, and is defined as

x(x-1)(x-2)(x-3)...2×1.

Now,

7C3 = 7!/(7 - 3)!3!

= 7!/4!3!

= (7×6×5×4×3×2×1)/(4×3×2×1)(3×2×1)

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Therefore, the number of different combinations of three students that are possible is 35.

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