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aalyn [17]
2 years ago
6

If the egress rate for a stadium is 5,500 fans per hour and it takes fans about one-third less time for fans to exit a game as i

t does for them to enter and find their seats, what is the ingress rate? (Round up to a whole number.)
Mathematics
2 answers:
Mumz [18]2 years ago
8 0

Answer:

16,500\frac{fans}{hour}

Step-by-step explanation:

<h3>Givens:</h3>
  • Egress rate is 5,500 fans per hour.
  • Egress rate is one-third than ingress rate. In other words, the ingress rate is 3 times faster than the egress rate. This interpretation is what solves this problem. It's the needed relation to answer the question.

Now, we have to express this in math, to calculate:

Egress=5,500\frac{fans}{hour}

Egress=\frac{1}{3}Ingress

Now, we replace and solve for Ingress:

5,500\frac{fans}{hour}=\frac{1}{3}Ingress\\Ingress=3(5,500\frac{fans}{hour})\\Ingress=16,500\frac{fans}{hour}

Therefore, based on the givens, the ingress rate is 16,500\frac{fans}{hour}

Marina CMI [18]2 years ago
4 0

Answer:

1833 fans per hour

Step-by-step explanation:

Ingress is entering and Egress is exiting.

Since exiting time is 1/3rd less than entering time, we have 5500 people exiting, so ingessing would be 1/3rd that.

Thus,

Ingress Rate = 5500/3 = 1833.33

Rounding to whole number, we have 1833 fans per hour

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denis23 [38]

Answer:

i) 60°

ii) 14.7 cm

Step-by-step explanation:

length of Arc BA = 8.4 cm

length of radius = 8 cm

angle AOC = 45°

BO = AO = CO = 8 cm

<u>i) What is the measure of Angle BOA </u>

= length of Arc BA  / Radius

= 8.4 / 8  = 1.05 radians = 60.16° ≈ 60°

<u>ii) what is the length of arc BAC</u>

= radius * angle BAC  * \pi /180

angle BAC = angle AOC + angle BOA

                  = 45° + 60° = 105°

hence length of arc BAC

= 8 * 105 * \pi /180

≈ 14.7 cm

3 0
2 years ago
Read 2 more answers
Henri has $24,000 invested in stocks and bonds. The amount in stocks is $6,000 more than three times the amount in bonds. How mu
kotykmax [81]

Answer:

<u>The amount of investment in bonds is US$ 4,500 and the amount of investment in stocks is US$ 19,500</u>

Step-by-step explanation:

Total investment in stocks and bonds = US$ 24,000

Amount of investment in bonds = x

Amount of investment in stocks = 3x + 6,000 (amount in stocks is $6,000 more than three times the amount in bonds)

For finding the value of x (amount of investment in bonds), we use this equation:

x + 3x + 6,000 = 24,000

x + 3x = 24,000 - 6,000

4x = 18,000

x = 4,500 (dividing by 4)

<u>The amount of investment in bonds is US$ 4,500</u>

Now let's find the amount of investment in stocks:

3x + 6,000 = 3 (4,500) + 6,000 = 13,500 + 6,000 = 19,500

<u>The amount of investment in stocks is US$ 19,500</u>

5 0
2 years ago
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The manager at Jessica's Furniture Store is trying to figure out how much to charge for a couch that just arrived. The couch was
arlik [135]
Answer: $163.85

Explanation:

1) Data:

Purchase price: $ 113.00

mark up: 45%

2) Formula

selling price = purchase price + mark up

mark up = % * purchase price

3) Solution

mark up = 45% * $ 113.00 = 0.45 * $ 113.00 = $50.85

selling price = $ 113.00 + $ 50.85 = $ 163.85

Answer: $ 163.85
5 0
2 years ago
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the weight of a bag of golf balls varies directly as the number of golf balls in the bag.If a bag of 69 gold balls weighs 2,553
seropon [69]

Answer: 30

Step-by-step explanation:

Given :The weight of a bag of golf balls varies directly as the number of golf balls in the bag.

Let x be the number of golf balls in a bag that weighs 1,110 grams.

Then we have the following direct variation equation,

\dfrac{x}{1110}=\dfrac{69}{2553}

Multiply 1110 both sides , we get

x=\dfrac{69}{2553}\times1110=30

Hence, there are 30 balls in the bag.

4 0
2 years ago
A candy manufacturer makes two types of special candy, say A and B. Candy A consists of equal parts of dark chocolate and carame
Sphinxa [80]
If we let x as candy A
y as candy B
a as dark chocolate in candy a
b as dark chocolate in candy b
c as caramel
d as walnut
P as profit
we have the equations:
a + c = x
2b + d = y
a + 2b ≤ 360
c ≤ 430
d ≤ 210
P = 285x + 260y

This is an optimization problem which involves linear programming. It can be solved by graphical method or by algebraic solution.
P = 285(a + c) + 260(2b +d)
If we assume a = b
Then a = 120, 2b = 240
P = 285(120 + 120) + 260(240 + 120)
P = 162000
candy A should be = 240
candy B should be = 360
6 0
2 years ago
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