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2 years ago

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the weight of a bag of golf balls varies directly as the number of golf balls in the bag.If a bag of 69 gold balls weighs 2,553

grams how many golf balls are in a bag that weighs 1,110 grams?

1 answer:

seropon [69]2 years ago

4 0

Answer: 30

Step-by-step explanation:

Given :The weight of a bag of golf balls varies directly as the number of golf balls in the bag.

Let x be the number of golf balls in a bag that weighs 1,110 grams.

Then we have the following direct variation equation,

$\dfrac{x}{1110}=\dfrac{69}{2553}$

Multiply 1110 both sides , we get

$x=\dfrac{69}{2553}\times1110=30$

Hence, there are 30 balls in the bag.

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The two-way frequency table below shows data on student behavior and the use of positive phone calls home as an incentive for go

dusya [7]

Answer:

From the frequency table, let's calculate the row total.

Row total for phone call = 19 + 9 = 28

Row total for no phone call = 8 +6 = 14

To calculate their respective row relative frequencies, let's use:

Row relative freq = $\frac{freq.}{Row total}$

Now, the two-way frequency table will be computed as:

For phone call:

Desirable behavior = $\frac{19}{28} = 0.67857$ ≈0.69

Undesirable behaviour = $\frac{9}{28} = 0.3214$ ≈0.32

No phone call:

Desirable behaviour = $\frac{8}{14} = 0.5714$ ≈ 0.57

Undesirable behaviour = $\frac{6}{14} = 0.4286$ ≈ 0.43

The complete two-way table is attached.

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2 years ago

Beck finished 30% of his homework in 12 minutes. How many minutes will it take him to complete all of his homework?

arlik [135]

The correct answer is choice D. If you put choice D into words, it is saying 30% (0.3) of the total is 12 minutes.

To solve this, use inverse operations.

<span><u>0.3m</u> = <u>12</u>
</span>0.3 0.3
m = 40

It will take Beck 40 minutes.

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1 year ago

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Carla can choose two of her three pairs of sneakers to take to a track meet. If the pairs of sneakers are called A, B, and C, wh

Semenov [28]

Number of ways of choosing two pair of sneakers from three pairs named A, B, C is given by 3C2 (3 combination 2) = 3! / 2!(3 - 2)! = 3! / (2! x 1!) = (3 x 2) / (2 x 1) = 3.

Therefore, the sample space is given by S = {AB, AC, BC}

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Select the coordinates of two points on the line y= 8

notsponge [240]

The answer for this is (0,8) and (8,0)

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2 years ago

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n 2019, approximately 97.4% of all the runners who started the Boston Marathon (in Boston, Massachusetts, USA) were able to comp

Zarrin [17]

Answer:

0.1199 = 11.99% probability that at least 5 of them did not finish the marathon

Step-by-step explanation:

For each runner, there are only two possible outcomes. Either they finished the marathon, or they did not. The probability of a runner completing the marathon is independent of any other runner. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

97.4% finished:

This means that 100 - 97.4 = 2.6% = 0.026 did not finish, which means that $p = 0.026$

100 runners are chosen at random

This means that $n = 100$

Find the probability that at least 5 of them did not finish the marathon

This is:

$P(X \geq 5) = 1 - P(X < 5)$

In which

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{100,0}.(0.026)^{0}.(0.974)^{100} = 0.0718$

$P(X = 1) = C_{100,1}.(0.026)^{1}.(0.974)^{99} = 0.1916$

$P(X = 2) = C_{100,2}.(0.026)^{2}.(0.974)^{98} = 0.2531$

$P(X = 3) = C_{100,3}.(0.026)^{3}.(0.974)^{97} = 0.2207$

$P(X = 4) = C_{100,4}.(0.026)^{4}.(0.974)^{96} = 0.1429$

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0718 + 0.1916 + 0.2531 + 0.2207 + 0.1429 = 0.8801$

$P(X \geq 5) = 1 - P(X < 5) = 1 - 0.8801 = 0.1199$

0.1199 = 11.99% probability that at least 5 of them did not finish the marathon

4 0

1 year ago