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Naily [24]
2 years ago
11

Ralph is paid twice per month. His work offers a flexible-spending account to be used for medical expenses. This plan allows Ral

ph to put a specific amount of money from each check into a savings fund so that he can pay for big bills a little at a time. If his son Billy needs new glasses that will cost $1,200, how much should Ralph have taken out of each check so the glasses can be paid for by the end of the year, with nothing left over in the account?
A.$50

B.$100

C.$30

D.$60
Mathematics
1 answer:
slava [35]2 years ago
6 0
In this question, we're assuming Ralph had 0 in his saving funds to start with.

The glasses cost 1200 dollars.

There are 12 months in a year.

Each month, Ralph is given his check two times, that means that Ralph receives his check 2(12), or 24, times per year.

Divide 1200 (the cost of the glasses) by 24 (the amount of times Ralph is given his check)

1200 / 24
Divide both numerator and denominator by 12
100 / 2
Simplify
50

Ralph should have put 50 dollars per pay check to pay for the glasses.

A is your answer.

Have an awesome day! :)
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1,2,4,5,10,20,25,50,100 are all the positive divisors of 100. However, rather than straight up multiplying them in random order, I will multiply the opposite ends with each other (100*1, 2*50, 4*25, 5*20) and then multiply 10. 
100*1=100
2*50=100
4*25=100
5*20=100
100*100*100*100*10= 1,000,000,000

 Answer: 1,000,000,000
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2 years ago
Three friends all live on the same street that runs west to east. Ben lives 7 blocks from Ann. Carol lives 2 from Ben. If the st
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Answer:

Just use your number line for help but you have to figure out if the numbers are positive or negative.

Step-by-step explanation:

If Ann lives at 0 and ben lives 7 blocks from Ann then you would say ben lives a number 7 on the number line and Carol lives 2 blocks from ben then carol would live at 9.

8 0
2 years ago
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alexandr402 [8]

Answer:

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5 0
2 years ago
A sociologist wants to determine if the life expectancy of people in africa is less than the life expectancy of people in asia.
Colt1911 [192]

Answer:

The sample statistics are attached.

First, we need to determine the hypothesis.

The null hypothesis should be: H_{o} : u_{africa} \geq u_{asia}.

The alternative hypothesis should be: H_{a}: u_{africa}

The next step is about calculating the<em> t statistics </em>based on the samples. This <em>t test </em>will give the probability value or p-value, which determines if there's enough to reject the null hypothesis. The formula we need to use to find the t-value is: t=\frac{x_{1}-x_{2}  }{\sqrt{\frac{s_{1} ^{2} }{n_{1} } +\frac{s_{2} ^{2} }{n_{2} } } }

Replacing all the values into the formula, we have:

t=\frac{52.4-58.1}{\sqrt{\frac{(7.4)^{2} }{45}+\frac{(8.8)^{2} }{35}  } } \\t=\frac{-5.7}{\sqrt{1.2+2.2} } =\frac{-5.7}{1.8} =-3.2

Therefore, the t-value is -3.2.

Now, we using a level of significance of 0.01, and a degree of freedom (df) of 34, we use the t-table to find the p-value for this results. (df = N -1; in this case, we take the smaller sample, which is 35, giving us 34 of df).

Therefore, according to the table attached, <em>the p-value is less than 0.01,</em> which is less than our level of significance. This result means that the null hypothesis is rejected. In other words, there's enough evidence to say that <em>the life expectancy of people in Africa is less than the life of expectancy of people in Asia.</em>

<em></em>

3 0
2 years ago
Jessa works at a potato chip factory and would like to estimate the mean weight in grams of the factory's potato
Svetlanka [38]

Answer:

The smallest sample size required to obtain the desired margin of error is 44.

Step-by-step explanation:

I think there was a small typing error, we have that \sigma = 60 is the standard deviation of these weighs.

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645

Now, find the margin of error M as such

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Which of these is the smallest approximate sample size required to obtain the desired margin of error?

This sample size is n.

n is found when M = 15

So

M = z*\frac{\sigma}{\sqrt{n}}

15 = 1.645*\frac{60}{\sqrt{n}}

15\sqrt{n} = 1.645*60

Simplifying by 15

\sqrt{n} = 1.645*4

(\sqrt{n})^{2} = (1.645*4)^{2}

n = 43.3

Rounding up

The smallest sample size required to obtain the desired margin of error is 44.

7 0
2 years ago
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