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slega [8]
2 years ago
7

Let X be the total medical expenses (in 1000s of dollars) incurred by a particular individual during a given year. Although X is

a discrete random variable, suppose its distribution is quite well approximated by a continuous distribution with pdf f(x) = k 1 + x 2.5 −7 for x ≥ 0.a. What is the value of k?b. Graph the pdf of X.c. What are the expected value and standard deviation of total medical expenses?d. This individual is covered by an insurance plan that entails a $500 deductible provision (so the first $500 worth of expenses are paid by the individual). Then the plan will pay 80% of any additional expenses exceeding $500, and the maximum payment by the individual (including the deductible amount) is $2500. Let Y denote the amount of this individual’s medical expenses paid by the insurance company. What is the expected value of Y? [Hint: First figure out what value of corresponds to the maximum out-of-pocket expense of $2500. Then write an expression for as a function of (which involves several different pieces) and calculate the expected value of this function.]

Mathematics
1 answer:
alexandr402 [8]2 years ago
5 0

Answer:

a) due to non availability of some equation i am attaching part a solution see the solution

b) see the attached graph

c) due to non availability of some equation i am attaching part a solution see the solution

d) due to non availability of some equation i am attaching part a solution see the solution

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Two well-known aviation training schools are being compared using random samples of their graduates. It is found that 70 of 140
egoroff_w [7]

Answer:

Step-by-step explanation:

Given that two well-known aviation training schools are being compared using random samples of their graduates

Fly more academy 70 of 140

Blue Yonder   104 of 260

Combined pass = (70+104) out of (140+260)

a) Pooled proportion=\frac{174}{400} \\=0.435

b) H0: p1 = p2

Ha: p1 ≠p2

(two tailed test)

p difference= \frac{70}{140} -\frac{104}{260} =0.10

std error for difference (using pooled proportion) = \sqrt{\frac{0.435*0.565}{400} } \\=0.0248

Test statistic = p difff/std error = 4.034

c) Critical value for 0.05 is 1.96

d) p value is < 0.005

Since p < 0.05 our significant level we reject H0

There is significant difference between the two proportions.

8 0
2 years ago
Hospital sends an invoice to a patient. The patient schedules a payment plan in which she makes an initial payment of $1,451 the
Korvikt [17]
First month she payed 1451 dollars

Second month she payed 1/3 of that, which is:
1451/3 = 483.66

Third month she payed 1/3 of 483.66 because as text says, every next month she pays 1/3 of previous month payed amount.

483.66/3 = 161.22

Forth month she payed

161.22/3 = 53.74

In total she payed:

$2149.62 - B.

hope this helps :)
3 0
2 years ago
Read 2 more answers
11. The sales tax rate is 6.9%
Norma-Jean [14]

Answer:

40.1%

Step-by-step explanation:

I am assuming that 192 is in 100%.

100% = 192

I then represent the value that we are looking for with x.

x% = 77

By dividing both equations (100% = 192 and x% = 77) and remembering that both left hand sides of BOTH equations have the percentage unit (%).

\frac{100}{x} = \frac{77}{192}

Now, of course, we take the reciprocal, or inverse, of both sides:

\frac{x}{100} = \frac{7}{192}

x = 40.1%

Thus making the answer: 40.1% of 192 is 77.

7 0
2 years ago
Water is poured into a conical paper cup at the rate of 3/2 in3/sec (similar to Example 4 in Section 3.7). If the cup is 6 inche
aliya0001 [1]

Answer:

The water level rising when the water is 4 inches deep is \frac{3}{8\times \pi} inch/s.

Step-by-step explanation:

Rate of water pouring out in the cone = R=\frac{3}{2} inch^3/s

Height of the cup = h = 6 inches

Radius of the cup = r = 3 inches

\frac{r}{h}=\frac{3 inch}{6 inch}=\frac{1}{2}

r = h/2

Volume of the cone = V=\frac{1}{3}\pi r^2h

V=\frac{1}{3}\pi r^2h

\frac{dV}{dt}=\frac{d(\frac{1}{3}\pi r^2h)}{dt}

\frac{dV}{dt}=\frac{d(\frac{1}{3}\pi (\frac{h}{2})^2h)}{dt}

\frac{dV}{dt}=\frac{1}{3\times 4}\pi \times \frac{d(h^3)}{dt}

\frac{dV}{dt}=\frac{1\pi }{12}\times 3h^2\times \frac{dh}{dt}

\frac{3}{2} inch^3/s=\frac{1\pi }{12}\times 3h^2\times \frac{dh}{dt}

h = 4 inches

\frac{3}{2} inch^3/s=\frac{1\pi }{12}\times 3\times (4inches )^2\times \frac{dh}{dt}

\frac{3}{2} inch^3/s=\pi\times 4\times \frac{dh}{dt} inches^2

\frac{dh}{dt}=\frac{3}{8\times \pi} inch/s

The water level rising when the water is 4 inches deep is \frac{3}{8\times \pi} inch/s.

6 0
2 years ago
Which expression is the result of solving the equation ax - b = cy for 2? (For a + 0)
Masja [62]
I would say cy hopes this help
6 0
2 years ago
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