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avanturin [10]
2 years ago
11

Two well-known aviation training schools are being compared using random samples of their graduates. It is found that 70 of 140

graduates of Fly-More Academy passed their FAA exams on the first try, compared with 104 of 260 graduates of Blue Yonder Institute.
a. To compare the pass rates, what would be the pooled proportion?

b. What is the test statistic?

c. Find the critical value for a right-tailed test at ? = .05.

d. Find the p-value.

d. What is your decision regarding the null hypothesis?
Mathematics
1 answer:
egoroff_w [7]2 years ago
8 0

Answer:

Step-by-step explanation:

Given that two well-known aviation training schools are being compared using random samples of their graduates

Fly more academy 70 of 140

Blue Yonder   104 of 260

Combined pass = (70+104) out of (140+260)

a) Pooled proportion=\frac{174}{400} \\=0.435

b) H0: p1 = p2

Ha: p1 ≠p2

(two tailed test)

p difference= \frac{70}{140} -\frac{104}{260} =0.10

std error for difference (using pooled proportion) = \sqrt{\frac{0.435*0.565}{400} } \\=0.0248

Test statistic = p difff/std error = 4.034

c) Critical value for 0.05 is 1.96

d) p value is < 0.005

Since p < 0.05 our significant level we reject H0

There is significant difference between the two proportions.

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Crank

Answer:

P=0.075,          P=7.5\%

Step-by-step explanation:

We look for the probability that the player fails the first attempt and also fails the second attempt.

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P(2|1) = 0.15

Then the probability of failure of both attempts is:

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P(1\ and\ 2)=P(1)*P(2|1)

P(1\ and\ 2)=0.5*0.15

P(1\ and\ 2)=0.075

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Legalization of marijuana, Part I. The 2010 General Social Survey asked 1,578 US res- idents: \Do you think the use of marijuana
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Answer:

Step-by-step explanation:

a) Sample statistics are used to estimate population value. Since 48% is a sample proportion, therefore, it is a sample statistic.

b) For 95% confidence level, z* = 1.96.

\hat{p}\pm z^* \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}= 0.61\pm 0.61\sqrt{\frac{0.61(1-0.61)}{1578}}=0.61\pm 0.024 \ or (0.586, 0.634).

We are 95% confident that the true proportion of US residents who think marijuana should be made legal lies between 58.6% and 63.4%.

c)

\\np=1578(0.61)=962.58

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Since both np and n(1-p), are at least 10, the normal model is a good approximation for these data.

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Which of the following completes the proof?
mihalych1998 [28]

Answer:

c

Step-by-step explanation:

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Segment GI is congruent to Segment JL and Segment GH is congruent to Segment KL. I have to prove Segment HI is congruent to Segm
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Answer:

See explanation

Step-by-step explanation:

1 step: \overline{GI}\cong \overline {JL} - given

2 step: \overline{GI}\cong \overline{GH}+\overline{HI} - Segments Addition Postulate

3 step: \overline{GH}+\overline{HI}\cong \overline {JL} - Substitution Property

4 step: \overline {JL}\cong \overline {JK}+\overline {KL} - Segments Addition Postulate

5 step: \overline{GH}+\overline{HI}\cong \overline {JK}+\overline {KL} - Substitution Property

6 step: \overline{GH}\cong \overline {KL} - given

7 step: \overline{GH}+\overline{HI}\cong \overline {JK}+\overline {GH} - Substitution Property of Equality

8 step: \overline{HI}\cong \overline {JK} - Subtraction Property of Equality

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