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Keith_Richards [23]
2 years ago
11

a triangle has an area of 38.4cm.the height of the triangle is 12.8cm.what is the length of the base of the triangle​

Mathematics
1 answer:
Solnce55 [7]2 years ago
4 0

Answer: 6  cm

Step-by-step explanation:

Use equation for area of triangle

A=a*h/2

a*h=2A

a=2A/h

where a  represents base of triangle

h represents height of triangle.

h=12.8 cm

A=38.4 cm²

a=2A/h=2*38.4 cm²/12.8 cm=76.8cm²/12.8cm= 6 cm

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Answer:

The total weight of the three fishes is 8lb and 13oz

Step-by-step explanation:

2lb 4oz + 1lb 11oz + 4lb + 14 = 7lb 29oz

Remember, there are 16 ounces (oz) in a pound (lb).

So 29oz - 16 oz would be 13oz and the answer would be 8lb and 13 oz.

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In 2013 the median monthly rent for one bedroom apartment in San Francisco was $2,750.the equation below models the median month
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2 years ago
What are the possible polynomial expression for dimensions of the cuboid whose volume is 12y2 + 8y -20
bogdanovich [222]

Answer:

The answer is below

Step-by-step explanation:

The volume of a cuboid is the product of its length, height and breadth. It is given by:

Volume = length × breadth × height

Since the volume is given by the expression 12y² + 8y - 20. That is:

Volume = 12y² + 8y - 20 = 4(3y² + 2y - 5) = 4(3y² + 5y - 3y -5) = 4[y(3y + 5) -1(3y + 5)]

Volume = 4(y-1)(3y+5)

Or

Volume = 12y² + 8y - 20 = 2(6y² +4y - 10) = 2(6y² + 10y - 6y -10) = 2[y(6y + 10) -1(6y + 10)]

Volume = 2(y-1)(6y+10)

Therefore the dimensions of the cuboid are either 4, y-1 and 3y+5 or 2, y-1 and 6y+10

3 0
2 years ago
Read 2 more answers
M2/n2 is equivalent to _____.
tankabanditka [31]

Answer:

\frac{m^2}{n^2} is equivalent to m^2 \cdot n^{-2}

Step-by-step explanation:

Using exponent rules:

a^{-n}=\frac{1}{a^n}

Given the expression:

\frac{m^2}{n^2}

⇒\frac{m^2}{n^2} = m^2 \cdot \frac{1}{n^2}

Apply the exponent rule, we have;

m^2 \cdot n^{-2}

Therefore, the given expression \frac{m^2}{n^2} is equivalent to m^2 \cdot n^{-2}

8 0
2 years ago
Suppose you are an expert on the fashion industry and wish to gather information to compare the amount earned per month by model
Ann [662]

Answer:

(1) The degrees of freedom for unequal variance test is (14, 11).

(2) The decision rule for the 0.01 significance level is;

  • If the value of our test statistics is less than the critical values of F at 0.01 level of significance, then we have insufficient evidence to reject our null hypothesis.      
  • If the value of our test statistics is more than the critical values of F at 0.01 level of significance, then we have sufficient evidence to reject our null hypothesis.  

(3) The value of the test statistic is 0.3796.

Step-by-step explanation:

We are given that you are an expert on the fashion industry and wish to gather information to compare the amount earned per month by models featuring Liz Claiborne's attire with those of Calvin Klein.

The following is the amount ($000) earned per month by a sample of 15 Claiborne models;

$3.5, $5.1, $5.2, $3.6, $5.0, $3.4, $5.3, $6.5, $4.8, $6.3, $5.8, $4.5, $6.3, $4.9, $4.2 .

The following is the amount ($000) earned by a sample of 12 Klein models;

$4.1, $2.5, $1.2, $3.5, $5.1, $2.3, $6.1, $1.2, $1.5, $1.3, $1.8, $2.1.

(1) As we know that for the unequal variance test, we use F-test. The degrees of freedom for the F-test is given by;

\text{F}_(_n__1-1, n_2-1_)

Here, n_1 = sample of 15 Claiborne models

         n_2 = sample of 12 Klein models

So, the degrees of freedom = (n_1-1, n_2-1) = (15 - 1, 12 - 1) = (14, 11)

(2) The decision rule for 0.01 significance level is given by;

  • If the value of our test statistics is less than the critical values of F at 0.01 level of significance, then we have insufficient evidence to reject our null hypothesis.      
  • If the value of our test statistics is more than the critical values of F at 0.01 level of significance, then we have sufficient evidence to reject our null hypothesis.  

(3) The test statistics that will be used here is F-test which is given by;

                          T.S. = \frac{s_1^{2} }{s_2^{2} } \times \frac{\sigma_2^{2} }{\sigma_1^{2} }  ~ \text{F}_(_n__1-1, n_2-1_)

where, s_1^{2} = sample variance of the Claiborne models data = \frac{\sum (X_i-\bar X)^{2} }{n_1-1} = 1.007

s_2^{2} = sample variance of the Klein models data = \frac{\sum (X_i-\bar X)^{2} }{n_2-1} = 2.653    

So, the test statistics =  \frac{1.007}{2.653 } \times 1  ~ \text{F}_(_1_4,_1_1_)

                                   = 0.3796

Hence, the value of the test statistic is 0.3796.

3 0
2 years ago
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