Answer:
N + D = 175
.05N + .10D = $13.30
Step-by-step explanation:
You need a system of equations to get the correct answer that applies to both constraints.
Answer:
11 boxed lunches
Step-by-step explanation:
Full question
Janie ordered boxed lunches for a student advisory committee meeting. Each lunch cost 4.25. The total cost of the lunches is 53.75, including a 7$ delivery fee. Write and solve an equation to find x the number of boxed lunches Janie ordered
First of all subtract the delivery feesince it was inckuded in the total cost, this will now be the total cost of all the noxed lunches ordered by Janie, then divide the balance of the total cost by the cost of one boxed lunch to get thd total boxed kunches
X= 53.75-7/4.25
X= 53.75-7= 46.75/4.25
X=11
Answer:
9 teams
Step-by-step explanation:
If the total games played was 36 and no team played each other twice, we need to ensure there isn't any double counting.
36 = (n-1) + (n-2) + (n-3) ... + (n-(n-1))
using this knowledge, we can then count up:
1+2+3+4+5+6+7+8 = 36
If our highest number is 8, then we know there must be 9 teams, because no team can play themselves.
Answer:
There were 3 adults
Step-by-step explanation:
Step 1: Derive the first expression
a+c=10...equation 1
where;
a=number of adults
c=number of children
And total number of people=10
Step 2: Derive the second expression;
Total cost of tickets=(price per child ticket×number of children)+(price per adult ticket×number of adults)
where;
Total cost of tickets=$186.50
price per child ticket=$15.95
price per adult ticket=$24.95
number of children=c
number of adults=a
replacing;
(15.95×c)+(24.95×a)=186.5
24.95 a+15.95 c=186.5....equation 2
Step 3: Combine equation 1 and 2 and solve simultaneously
24.95 a+15.95 c=186.5
-
24.95(a+c=10)
(24.95 a-24.95 a)+(15.95 c-24.95 c)=186.5-(24.95×10)
-9 c=-63
c=-63/-9
c=7
replace the value for c in equation 1
a+c=10
a+7=10
a=10-7
a=3
There were 3 adults
