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Effectus [21]
1 year ago
8

Mr. Adkins teaches a Current Events course and is known for making his final exam very thorough. He thinks that with the technol

ogy present today,
his students should be able to stay current with all possible news. The only way to ensure yourself a good grade is to dedicate many hours reading
newspapers, watching 24 hour news outlets, and scanning the internet, and even that may not give you the desired test score. Adkins' students
kept track of the hours that they studied the week previous to the test. Here is a breakdown of the hours that they studied and the score they
received on the test.

Mathematics
1 answer:
umka2103 [35]1 year ago
3 0

Answer:

Part 1:

Make a scatterplot that represents this data. You may use a program such as Excel, or make the scatterplot by hand and scan it.

Part 2:

Does this data have a positive correlation, negative correlation, or no correlation?

Part 3:

Without the use of technology, find the equation of the line of best fit for the data. Tell which points that you used and show the steps you used to get the equation. Refer to the first 4 steps on page 2 of the lesson titled "Linear Regression - Line of Best Fit" to use as a guide.

Part 4:

Use the equation found in part 3 to predict the scores for two people who studied for 15 hours and 9 hours. Refer to the last step on page 2 of the lesson titled "Linear Regression - Line of Best Fit" to use as a guide.

Compile the results from parts 1 through 4 and put them in a Word document. Submit the document to your teacher.

Step-by-step explanation: help

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Triangle S R Q is shown. Angle S R Q is a right angle. An altitude is drawn from point R to point T on side S Q to form a right
Jet001 [13]

Answer:

Option B.

Step-by-step explanation:

It is given that ΔSRQ is a right angle triangle, ∠SRQ is right angle.

RT is altitude on side SQ, ST=9, TQ=16 and SR=x.

In ΔSRQ and ΔSTR,

m\angle S=m\angle S           (Reflexive property)

m\angle R=m\angle T           (Right angle)

By AA property of similarity,

\triangle SRQ\sim \triangle STR

Corresponding parts of similar triangles are proportional.

\dfrac{SR}{SQ}=\dfrac{ST}{SR}

Substitute the given values.

\dfrac{x}{9+16}=\dfrac{9}{x}

\dfrac{x}{25}=\dfrac{9}{x}

On cross multiplication we get

x^2=25\times 9

x^2=225

Taking square root on both sides.

x=\sqrt{225}

x=15

The value of x is 15. Therefore, the correct option is B.

7 0
2 years ago
Read 2 more answers
Determine the area (in units2) of the region between the two curves by integrating over the x-axis. y = x2 − 24 and y = 1
astra-53 [7]

Answer:

The area of the region between the two curves by integration over the x-axis is 9.9 square units.

Step-by-step explanation:

This case represents a definite integral, in which lower and upper limits are needed, which corresponds to the points where both intersect each other. That is:

x^{2} - 24 = 1

Given that resulting expression is a second order polynomial of the form x^{2} - a^{2}, there are two real and distinct solutions. Roots of the expression are:

x_{1} = -5 and x_{2} = 5.

Now, it is also required to determine which part of the interval (x_{1}, x_{2}) is equal to a number greater than zero (positive). That is:

x^{2} - 24 > 0

x^{2} > 24

x < -4.899 and x > 4.899.

Therefore, exists two sub-intervals: [-5, -4.899] and \left[4.899,5\right]. Besides, x^{2} - 24 > y = 1 in each sub-interval. The definite integral of the region between the two curves over the x-axis is:

A = \int\limits^{-4.899}_{-5} [{1 - (x^{2}-24)]} \, dx + \int\limits^{4.899}_{-4.899} \, dx + \int\limits^{5}_{4.899} [{1 - (x^{2}-24)]} \, dx

A = \int\limits^{-4.899}_{-5} {25-x^{2}} \, dx + \int\limits^{4.899}_{-4.899} \, dx + \int\limits^{5}_{4.899} {25-x^{2}} \, dx

A = 25\cdot x \right \left|\limits_{-5}^{-4.899} -\frac{1}{3}\cdot x^{3}\left|\limits_{-5}^{-4.899} + x\left|\limits_{-4.899}^{4.899} + 25\cdot x \right \left|\limits_{4.899}^{5} -\frac{1}{3}\cdot x^{3}\left|\limits_{4.899}^{5}

A = 2.525 -2.474+9.798 + 2.525 - 2.474

A = 9.9\,units^{2}

The area of the region between the two curves by integration over the x-axis is 9.9 square units.

4 0
1 year ago
Suppose two different methods are available for eye surgery. The probability that the eye has not recovered in a month is 0.002
umka21 [38]

Answer:

0.4007

Step-by-step explanation:

Let's define the following events:

A: method A is used

B: method B is used

NR: the eye has not recovered in a month

R: the eye is recovered in a month

The probability that the eye has not recovered in a month is 0.002 if method A is used, i.e., P(NR|A) = 0.002, so P(R|A) = 0.998.

When method B is used, the probability that the eye has not recovered in a month is 0.005, i.e., P(NR|B) = 0.005, so P(R|B) = 0.995.

40% of eye surgeries are done with method A, i.e., P(A) = 0.4

60% of eye surgeries are done with method B, i.e., P(B) = 0.6

If an eye is recovered in a month after surgery is done in the hospital, what is the probability that method A was performed? We are looking for P(A|R), then, by Bayes' Formula

P(A|R) = P(R|A)P(A)/(P(R|A)P(A) + P(R|B)P(B)) = 0.998*0.4/(0.998*0.4 + 0.995*0.6) = 0.4007

4 0
2 years ago
If 2x – 3 ≤ 5, what is the greatest possible value of 2x + 3 ? a.4 b.8 c.10 d.11
harina [27]

Answer:

Hope it is correct :) :)

8 0
2 years ago
Which function has the domain x&gt;or= -11
iogann1982 [59]
I'm assuming this is multiple choice and you forgot to post the answers. I'll take a guess and say it probably looks something like this:
y = \sqrt{x + 11}
Because you can't take the square root of a negative number without getting an imaginary result, resulting in the function having a closed domain limit.
6 0
2 years ago
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