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lesantik [10]
2 years ago
8

Orlando invested $16,000 in an eight-year CD bearing 6.5% simple annual interest, but needed to withdraw $3,500 after five years

. If the CD’s penalty for early withdrawal was one year’s worth of interest on the amount withdrawn, when the CD reached maturity, how much less money did Orlando earn total than if he had not made his early withdrawal?
Mathematics
2 answers:
Alexxx [7]2 years ago
7 0

Answer:

The correct answer is C. $910.

Step-by-step explanation:


zhenek [66]2 years ago
5 0
If Orlando did not make the early withdrawal, the amount of money he supposed to have is,
                               F = $16,000 + 0.065($16,000)(8) = $24,320
While making the early withdrawal only earned him,
       F1 = (16,000) + (0.065)($16,000)(8) - $3,500 - ($3,500)(0.065) = $20,592.5
The difference of two amounts are $3727.5. 
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The batting Wang Xiu Ying uses to fill quilts has a thermal conductivity rate of 0.030.030, point, 03 watts (\text{W})(W)left pa
alexgriva [62]

Answer:

0.0003W/cm°C

Step-by-step explanation:

The question is not properly written. Here is the correct question.

The batting wang xiu ying uses to fill quilts has a thermal conductivity rate of 0.03 watts (W) per meter(m) per degree celsius. what is the batting thermal conductivity when w/cm•c

Given the thermal conductivity in W/m°C to be 0.03W/m°C

We are to rewrite the value in W/cm°C

The difference is the unit. The only thing we need to do is to simply convert the unit (metres) in W/m°C to centimeters (cm)

Since 100cm = 1m, 0.03W/m°C can be expressed as shown below;

= 0.03W/m°C

= 0.03 × W/1m×°C

Note that 1m = 100cm, substituting this conversion into the expression, it will become;

= 0.03 × W/100cm × °C

= 0.03/100 × W/cm°C

= 0.0003W/cm°C

Hence the battling thermal conductivity in W/cm°C is 0.0003W/cm°C

4 0
2 years ago
Sasha has 3.20 in U.S. coins. She has the same number of quarters and nickels. What is the greatest number of quarters she could
RSB [31]

Answer:

10 quarters = $2.50

10 nickels = $0.50

that leaves $0.20 for other coins (dimes / pennies)

Step-by-step explanation:

First, suppose she has only quarters and nickels and no other coins.  Then if C is the identical number of coins of each type, then 5C + 25C = 320, so 30C = 320 and 3C = 32, but there is no integer solution to this.  So she must have at least one other type of coin.

Assume she has only quarters, nickels, and dimes.  Then if D is the number of dimes, 5C +  25C + 10D = 320, which means 30C + 10D = 320, or 3C + D = 32.  The smallest D can be is 2, leaving 3C = 30 and thus C = 10.  So in this scenario she would have 10 quarters, 10 nickels, and two dimes to make $2.50 + $0.50 + $0.20 = $3.20.

This has to be the highest number, because if she had 11 quarters and 11 nickels, that alone would add up to 11(0.25) + 11(0.05) = $3.30, which would already be too much.

8 0
2 years ago
Read 2 more answers
A scientist looks at a bacterium and a virus in a lab. The bacterium has a diameter of mc020-1.jpg meters. The virus has a diame
Reil [10]
You can divide the two values A = diameter of bacterium B = diameter of virus A/B = (10^(-6))/(10^(-7)) A/B = 10^(-6-(-7)) A/B = 10^(-6+7) A/B = 10^(1) A/B = 10 Since the ratio of the two diameters is 10, this means that the diameter of the bacterium is 10 times greater than that of the virus. 
6 0
2 years ago
Tiffany ate 1/4 of a pizza. If there were 16 slices of pizza to begin with, how many slices did Tiffany eat?​
viktelen [127]

Answer:

Tiffany ate 4 slices of pizza

Step-by-step explanation:

1/4 of 16 is 4

6 0
2 years ago
Read 2 more answers
Consider the polynomial: StartFraction x Over 4 EndFraction – 2x5 + StartFraction x cubed Over 2 EndFraction + 1 Which polynomia
Phoenix [80]

Answer:

- 2x^5+ 0x^4 +  \frac{x^3}{2} +0x^2+\frac{x}{4}  + 1

Step-by-step explanation:

Given

\frac{x}{4} - 2x^5 + \frac{x^3}{2} + 1

Required

The standard form of the polynomial

The general form of a polynomial is

ax^n + bx^{n-1} + cx^{n-2} +........+ k

Where k is a constant and the terms are arranged from biggest to smallest exponents

We start by rearranging the given polynomial

- 2x^5+ \frac{x^3}{2} +\frac{x}{4}  + 1

Given that the highest exponent of x is 5;

Let n = 5

Then we fix in the missing terms in terms of n

- 2x^5+ 0x^{n-1} +  \frac{x^3}{2} +0x^{n-3}+\frac{x}{4}  + 1

Substitute 5 for n

- 2x^5+ 0x^{5-1} +  \frac{x^3}{2} +0x^{5-3}+\frac{x}{4}  + 1

- 2x^5+ 0x^{4} +  \frac{x^3}{2} +0x^{2}+\frac{x}{4}  + 1

Hence, the standard form of the given polynomial is - 2x^5+ 0x^4 +  \frac{x^3}{2} +0x^2+\frac{x}{4}  + 1

3 0
2 years ago
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