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lesantik [10]
2 years ago
8

Orlando invested $16,000 in an eight-year CD bearing 6.5% simple annual interest, but needed to withdraw $3,500 after five years

. If the CD’s penalty for early withdrawal was one year’s worth of interest on the amount withdrawn, when the CD reached maturity, how much less money did Orlando earn total than if he had not made his early withdrawal?
Mathematics
2 answers:
Alexxx [7]2 years ago
7 0

Answer:

The correct answer is C. $910.

Step-by-step explanation:


zhenek [66]2 years ago
5 0
If Orlando did not make the early withdrawal, the amount of money he supposed to have is,
                               F = $16,000 + 0.065($16,000)(8) = $24,320
While making the early withdrawal only earned him,
       F1 = (16,000) + (0.065)($16,000)(8) - $3,500 - ($3,500)(0.065) = $20,592.5
The difference of two amounts are $3727.5. 
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Answer:

298.7

Step-by-step explanation:

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1 year ago
Mr. Barth is painting an arrow on the school parking lot. He draws the edges between the following points on the coordinate plan
andreyandreev [35.5K]

Answer:

<u>70 square units</u>

Step-by-step explanation:

<em>I have plotted the points on the coordinate system and connected roughly using a red line. Image is attached. </em>

The arrow created, consists of a TRIANGLE and a RECTANGLE. The area of the arrow would be:

Area of Arrow = Area of Triangle + Area of Rectangle

Area of Triangle = 0.5 * base * height

Base is 12 units

Height is 7 units, so

Area of Triangle = 0.5 * 12 * 7 = 42

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Area of Rectangle = 7 * 4 = 28

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4 0
2 years ago
Students are going through a three-step process to obtain their ID cards. Each student will spend 2 minutes at the registration
kondaur [170]

Answer:

C. 160 minutes

Step-by-step explanation:

The calculation to be made will be to process 20 students

We have, according to the exercise, the following data:

For process 1: Registration table, Number of servers = 1, Time spent = 2 minutes

For process 2: cashier, number of servers = 3, time spent = 10 minutes

For process 3: ID processing station, number of servers = 4, time spent = 20 minutes

Demand rate = 0.125

To solve it, we will look for the capacity that the server has of the previously mentioned processes, calculating the following:

Capacity = Number of students served per minute

We can say that at the registration table we observe:

Time needed to serve 1 student = 2 minutes

Capacity = 0.5 students per minute

With the cashier we analyze the following:

Time needed to serve 1 student = 10 minutes

Number of servers = 3

Capacity = 0.3 students per minute

ID processing station

Time needed to serve 1 student = 20 minutes

Number of servers = 4

Capacity = 0.2 students per minute

When comparing the processes, it is definitely found that the bottleneck is the ID processing station, where it takes more time to serve a student, which leads us to infer that the capacity of the process is comparable to the capacity of the process bottleneck

Process capacity = 0.2 students per minute

Given, demand rate = 0.125 students per minute

We observe that the demand rate is less than the capacity of the process, therefore we can infer that the number of students served during each minute is the same as the demand rate.

In this way we find that:

Number of students served per minute = 0.125

Time needed to serve 1 student = 1 / 0.125 = 8 minutes

Time needed to serve 20 students = 8 x 20 = 160 minutes.

We conclude that the answer is that it will take 160 minutes to serve 20 students.

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6 0
2 years ago
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8 0
1 year ago
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Suppose that you want to estimate average income in a population. If the standard deviation of income in the population is $1,00
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Answer:

2401

Step-by-step explanation:

Given that we want to estimate average income in a population.

The standard deviation of income in the population is $1,000

We want confidence interval around our estimate to be +/- $40

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We know that margin of error = Std error * Z critical for 95%

i.e. 40 = 1.96 * std error

Std error = \frac{std dev}{\sqrt{n} } \\=\frac{1000}{\sqrt{n} }

Together we get

40=1.96(\frac{1000}{\sqrt{n} } )\\\sqrt{n} =\frac{1000*1.96}{40} \\=49\\n=2401\\

3 0
1 year ago
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