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nikklg [1K]
2 years ago
9

A university surveyed recent graduates of the English department for their starting salaries. Four hundred graduates returned th

e survey. The average salary was $25,000. The population standard deviation was $2,500. What is the 95% confidence interval for the mean salary of all graduates from the English department
Mathematics
1 answer:
NeX [460]2 years ago
3 0

Answer:

Step-by-step explanation:

We want to determine a 95% confidence interval for the mean salary of all graduates from the English department.

Number of sample, n = 400

Mean, u = $25,000

Standard deviation, s = $2,500

For a confidence level of 95%, the corresponding z value is 1.96. This is determined from the normal distribution table.

We will apply the formula

Confidence interval

= mean ± z × standard deviation/√n

It becomes

25000 ± 1.96 × 2500/√400

= 25000 ± 1.96 × 125

= 25000 ± 245

The lower end of the confidence interval is 25000 - 245 =24755

The upper end of the confidence interval is 25000 + 245 = 25245

Therefore, with 95% confidence interval, the mean salary of all graduates from the English department is between $24755 and $25245

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Option D) ∠B ≅ ∠D

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1 year ago
1. Lisa and Tomas Lopez are buying a new minivan that has a base
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The question is incomplete:

Lisa and Tomas Lopez are buying a new minivan that has a base price of $22,510.the options total $8,062 and destination charge is $770. The dealer's cost is estimated to be 91% of the base price and 88% of the options.

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Answer:

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