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2 years ago

What is the quotient (x3 8) ÷ (x 2)?

2 answers:

8 0

If you would like to solve (x^3 + 8) / (x + 2), you can do this using the following steps:

x^3 + 8 = (x + 2) * (x^2 - 2x + 4)

(x^3 + 8) / (x + 2) = (x + 2) * (x^2 - 2x + 4) / (x + 2) = <span>x^2 - 2x + 4
</span>
The correct result would be <span>x^2 - 2x + 4.</span>

Musya8 [376]2 years ago

7 0

As the Question is not clear

But there are two possibilities

1. $\frac{x^3+8}{x+2}=\frac{(x+2)(x^2-2 x+4)}{x+2}=x^2-2 x+4$ →→Cancelling x+2 from numerator and denominator

→→ Using the formula (a³ + b³) =(a+b)(a² - ab + b²)

Or if

$\frac{x^3-8}{x-2}=\frac{(x-2)(x^2+2x+4)}{x-2}=x^2+ 2 x +4$ →→Cancelling x-2 from numerator and denominator

Using the formula (a³ - b³) =(a-b)(a² + ab + b²)

Statement (1) appears true.

So, correct option is x²- 2 x + 4 or x² + 2 x + 4

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The number of hurricanes hitting the coast of Florida annually has a Poisson distribution with a mean of 0.8. Answer the followi

slava [35]

Answer:

a) $P(X>2)= 1-P(X \leq 2) = 1-[P(X=0)+P(X=1)+P(X=2)]$

And we can find the individual probabilities like this:

$P(X=0) = \frac{e^{-0.8} 0.8^0}{0!}= 0.4493$

$P(X=1) = \frac{e^{-0.8} 0.8^1}{1!}= 0.3595$

$P(X=2) = \frac{e^{-0.8} 0.8^2}{2!}= 0.1438$

And replacing we got:

$P(X>2)= 1-P(X \leq 2) = 1-[0.4493+0.3595+0.1438]=0.0474$

b) $P(X=1) = \frac{e^{-0.8} 0.8^1}{1!}= 0.3595$

Step-by-step explanation:

Let X the random variable that represent the number of hurricanes hitting the coast of Florida annualle. We know that $X \sim Poisson(\lambda=0.8)$

The probability mass function for the random variable is given by:

$f(x)=\frac{e^{-\lambda} \lambda^x}{x!} , x=0,1,2,3,4,...$

And f(x)=0 for other case.

For this distribution the expected value is the same parameter $\lambda=0.8$

$E(X)=\mu =\lambda=0.8$

Part a

For this case we want this probability: $P(X>2)$

And for this case we can use the complement rule like this:

$P(X>2)= 1-P(X \leq 2) = 1-[P(X=0)+P(X=1)+P(X=2)]$

And we can find the individual probabilities like this:

$P(X=0) = \frac{e^{-0.8} 0.8^0}{0!}= 0.4493$

$P(X=1) = \frac{e^{-0.8} 0.8^1}{1!}= 0.3595$

$P(X=2) = \frac{e^{-0.8} 0.8^2}{2!}= 0.1438$

And replacing we got:

$P(X>2)= 1-P(X \leq 2) = 1-[0.4493+0.3595+0.1438]=0.0474$

Part b

Using the probability mass function we have:

$P(X=1) = \frac{e^{-0.8} 0.8^1}{1!}= 0.3595$

3 0

2 years ago

What is equal to x in x - 8pi = pi?

pochemuha

Add 8π to both sides of the equation to get:

$x - 8\pi + 8\pi = \pi + 8 \pi$

$\boxed{x = 9 \pi}$

We have found that x = 9π. Remember that in solving problems like these with pi that it can often be helpful to treat pi as a variable.

8 0

2 years ago

The angle measurements in the diagram are represented by the following expressions

Klio2033 [76]

8x-10=3x+90
5x=100
X=20
B=3(20)+90=150

5 0

1 year ago

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Write a paragraph that has an inverted triangle shape. The topic sentence should be, “Trees are helpful.” Include at least three

yaroslaw [1]

Why trees are helpful........................................
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............................................................
.....................................................
..............................................
..................................
Very easy just state facts about trees in a format like this. Google why trees are helpful and some facts should pop up. A good paragraph should have at least five (5) good strong sentences.

4 0

1 year ago

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What is the least common denominator (LCD) of 1/3 and 3/4

ollegr [7]

Answer:

LCD: 12

3:3, 6, 9, 12

4: 4, 8, 12

8 0

1 year ago

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