Answer:
Methods of obtaining a sample of 600 employees from the 4,700 workforce:
Part A: The type of sampling method proposed by the CEO is Convenience Sampling.
Part B: When there are equal number of participants in both campuses, stratification by campus would give a more precise approximation of the proportion of employees who are satisfied with the cleanliness of the breakrooms than stratification by gender. Another method to ensure that stratification by campus gives a more precise approximation of the proportion of employees who are satisfied with the cleanliness of the breakrooms than stratification by gender is to ensure that the sample is proportional to the proportion of each campus to the whole population or workforce.
Step-by-step explanation:
A Convenience Sampling technique is a non-probability (non-random) sampling method and the participants are selected based on availability (early attendees). The early attendees might be different from the late attendees in characteristics such as age, sex, etc. Therefore, sampling biases are present. All non-probability sampling methods are prone to volunteer bias.
Stratified sampling is more accurate and representative of the population. It reduces sampling bias. The difficulty arises in choosing the characteristic to stratify by.
Answer:
The required equation is
d = 4c
where d represents the cost of cookies in dollar and c represents the number of boxes of cookies.
Step-by-step explanation:
Given that, the cost of each box of cookies is $4.
It means,
The cost of 1 box of cookies is $4.
The cost of 2 boxes of cookies is $(4+4) =$(2×4)
The cost of 3 boxes of cookies is $(4+4+4) =$(3×4)
The cost of cookies
=(Number of boxes × 4)
The required equation is
d = 4c
where d represents the cost of cookies in dollar and c represents the number of boxes of cookies.
Answer:
a = 0.25
Step-by-step explanation:
Our strategy to solve this problem will be to use the information given in the table to obtain first the value of c in the quadratic equation which has the form ax^2 + bx + c and then form a system of 2 linear equations and solve for the coefficients a and b as follow:
from x=0 and y=-3 a*0 + b* 0 + c = - 3
c = -3
from x=1 and y= -3.75
a*(1) + *(1) + (-3) = -3.75
a + b = -3.75 + 3 = -0.75
from x= 2 and y = -4
a* (2)^2 + b*(2) + (-3) = -4
4a + 2b = -4 +1
4a + 2b = -1
Now we can solve the system f equations by elimination:
a + b = -0.75
4a + 2b = -1
multiply first equation by -2 and add to the second and get
-2a - 2b = +1.50
4a + 2b = -1
2a = 0.50 and substituting into any of the equations get b = -1
so the quadratic equation has a= 0.25 b= -1 c= -3
we can even plug the any of the other values for x given in the table and check the answer.
Correct question:
Which reaction describes a beta emission? 2659Fe→ 2759Co + −10e, 88226Ra→ 86222Rn + 24He, 94239Pu + 24He→ 96242Cm + 01n, 54118Xe→ 53118I + +10e
Answer:
2659Fe→ 2759Co + 1e
Step-by-step explanation:
General equation for beta decay is given as;
where;
A is the atomic mass of the element
z is atomic number of the element
X is the parent atom
Y is the daughter element
β is beta emission
In beta emission, there is loss of one electron and zero proton, the will cause the daughter element to gain on electron in order to balance the reaction.
Based on beta decay equation above, we select the reaction that describes beta emission.
2659Fe→ 2759Co + 1e
Here;
A = 59
z = 26
z + 1 = 27
