We will use the law of cosines
<span>side a² = b² + c² -2bc • cos(A)
</span><span>side a² = 729 + 196 -2*27*14 * cos (46)
</span><span>side a² = 925 -(756 * 0.69466)
</span>side a² = <span><span>399.83704
</span>
side a = </span><span><span><span>19.995925585
</span>
</span>
</span>
We could round that to 20
a = 20 b = 27 c =14
We can calculate a triangle's area when we know all 3 sides by using Heron's Formula
<span>area = square root (s • (s - a) • (s - b) • (s - c))
where s is the semi-perimeter </span>
semi-perimeter<span> = (side a + side b + side c) ÷ 2</span>
s = (20 + 27 + 14) / 2
s = 30.5
Now we use Heron's Formula
area = square root (s • (s - a) • (s - b) • (s - c))
area = square root (30.5 • (<span>30.5 - 20) • (</span><span>30.5 - 27) • (</span><span>30.5 - 14))</span>
area = square root (30.5 • (10.5) • (3.5) • (<span>16.5))</span>
<span>area = square root (18494.4375)
</span>
<span><span><span>area = 135.9942553934
</span>
</span>
</span>which rounds to
136 square feet
Source:
http://www.1728.org/triang.htm
⭐Solución de problemas: Cada encomiendo tiene un peso de 2 kilogramos. En fracción esto representa 1/4 de la masa total.
Y
¿por qué? Usted tiene una masa total entre los 4 encomiendos de 8 kilogramos, por lo que en orden
para expresar el peso de cada uno de ellos, tenemos
la siguiente expresión: Masa total de encomiendas (kg)/Número de encomiendas (unidad)Sustituimos:
8 kg/4 s
2 kg por encomiendaOfertamos la fracción que representa cada una en el total:
kg por encomienda/total de kg
2/8 x 1/4
It is given in the question that,
Line QS bisects angle PQR. Solve for x and find the measure of angle PQR.
And
Since QS bisects angle PQR, therefore
Substituting the values, we will get
Answer:
The probability that the next failure will not occur before 30 months have elapsed is 0.0454
Step-by-step explanation:
Using Poisson distribution where
t= number of units of time
x= number of occurrences in t units of time
λ= average number of occurrences per unit of time
P(x;λt) = e raise to power (-λt) multiplied by λtˣ divided by x!
here λt = 25
x= 30
P(x= 30) = 25³⁰e⁻²⁵/ 30!
P (x= 30) = 8.67 E41 * 1.3887 E-11/30! (where E= exponent)
P (x=30) = 1.204 E31/30!
Solving it with a statistical calculator would give
P (x=30) = 0.0454
The probability that the next failure will not occur before 30 months have elapsed is 0.0454
W^2=80
W SQRT80
W=8.94 ANS.FOR THE WIDTH
L=3*8.94=26.83 ANS.FOR THE LENGTH
PROOF:
240=8.94*26.83
240=240
