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Neko [114]
1 year ago
8

A house has a large window made of 15 equal-sized pieces of glass, each the same size and shape. There are 3 pieces of glass tha

t are cracked. If a rock thrown by a lawn mower hits the window, what is the probability that the rock hits a piece of glass that is cracked?
Mathematics
1 answer:
melamori03 [73]1 year ago
6 0
<span>The chance or probability that the lawn mower will hit a piece of glass that is already cracked is calculated by dividing the number of glasses that are cracked by the total number of glasses. In this item, the unknown can be calculated by 3/15. The answer is therefore, 1/5 or 0.20. </span>
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Lori bought a shirt and a hat at a half off sale. If she spent a total of $21 on the two items, what was the original price of t
Bad White [126]
Do 21 divided by 2 and you’ll get 10.5 so the original price was $10 and 50 cents
6 0
1 year ago
What is the simplified form of StartRoot StartFraction 72 x Superscript 16 Baseline Over 50 x Superscript 36 Baseline EndFractio
aalyn [17]

Answer:

  StartFraction 6 Over 5 x Superscript 10 Baseline EndFraction

Step-by-step explanation:

Apparently you want to simplify ...

  \sqrt{\dfrac{72x^{16}}{50x^{36}}}

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  1/a^b = a^-b

  (a^b)^c = a^(bc)

__

So the expression simplifies as ...

  \sqrt{\dfrac{72x^{16}}{50x^{36}}}=\sqrt{\dfrac{36}{25x^{36-16}}}=\sqrt{\dfrac{36}{25x^{20}}}\\\\\sqrt{\left(\dfrac{6}{5x^{10}}\right)^2}=\boxed{\dfrac{6}{5x^{10}}}

9 0
1 year ago
The lengths of a particular snake are approximately normally distributed with a given mean Mu = 15 in. and standard deviation Si
Liula [17]

Answer: 5%

Step-by-step explanation:

Let see that the snakes that are longer than 16.6 in are lomger than mean at 16.6-15=1.6 in

1.6:Sigma=1.6: 0.8=2 that means that all other snakes but longer than 16.6 in are inside +-2 Sigma. It is known that for normal distribution 95.4% of all snakes are inside +-2 Sigma

That means that 100%-95.4%=4.6% or about 5% of the snakes are longer than 16.6 in

7 0
1 year ago
Read 2 more answers
Throughout the 2016 Presidential election primaries, Millennials (those aged 20 t 36 years) consistently supported Senator Berni
Dmitrij [34]

Answer:

The 90% confidence interval for the support of Sanders by millenials is between 53% and 57%.

0.53 \leq p \leq 0.57

Step-by-step explanation:

In this question we have to calculate a confidence interval (90% CI) on the proportion of millenials that had a favorable opinion on Sanders.

The sample size is n=1,754.

The p-hat, taken from the poll, is

\hat{p}=0.55

The estimated standard deviation is equal to:

\sigma_p=\sqrt{\frac{p(1-p)}{N}}=\sqrt{\frac{0.55*0.45}{1754}}=0.012

For a 90% CI, the z-value is z=1.645.

Then, the confidence interval is

\hat{p}-z*\sigma_p\leq p\leq\hat{p}-z*\sigma_p\\\\0.55-1.645*0.012\leq p\leq 0.55-1.645*0.012\\\\0.55-0.02 \leq p \leq 0.55+0.02\\\\0.53 \leq p \leq 0.57

6 0
2 years ago
Ryan conducted a 6-day study observing the effects of an organic plant food on the growth of his sprouting bean plant. He tracke
Zarrin [17]

Answer:

The relationship is a function because only one amount of plant food remains each day

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
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