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2 years ago

Write an expression for the sequence of operations described below.

1 answer:

8 0

Quotient refers to division:

(8/v)² ⇒ (8/v)(8/v) = 8*8 / v*v = 64/v²

When you raise a fraction to a power, you multiply the fraction by itself according to the power raised.

Then, do the usual steps of multiplying fractions.
1) multiply numerators.
2) multiply denominators
3) simplify fraction produced.

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A 2-column table with 6 rows. The first column is labeled miles driven with entries 27, 65, 83, 109, 142, 175. The second column

Helen [10]

Answer:

1) The linear regression model is y = -0.0348·x + 13.989

2) The correlation coefficient is -0.0725

3) The strength of the model is strong - association

Step-by-step explanation:

X Y XY X²

27 13 351 729

65 12 780 4225

83 11 913 6889

109 10 1090 11881

142 9 1278 20164

175 8 1400 30625

∑ 601 63 5812 74513

From y = ax + b, we have

$a = \frac{n\sum xy - \sum x\sum y }{n\sum x^{2}-\left (\sum x \right )^{2}} = \frac{6 \times 5812 - 601 \times 63}{6 \times 74513-601^{2}} = - 0.0348$

b = 1/n(∑y -a∑x) = 1/6(63 - (0.0348)×601) = 13.989

Therefore, the linear regression model is y = -0.0348·x + 13.989

$r = \frac{n\sum xy - \sum x\sum y }{\sqrt{[n\sum x^{2}-\left (\sum x \right )^{2}] [n\sum y^{2}-\left (\sum y \right )^{2}]}} = \frac{6 \times 5812 - 601 \times 63}{\sqrt{[6 \times 74513-601^{2}] [6 \times 3969 - 63^2]} } = - 0.0725$

3) The strength is - association.

5 0

2 years ago

Read 2 more answers

In math class, Sam correctly multiplied 3.625×10-8 by 500, then reported his product in scientific notation.

Minchanka [31]

<h3><u>Question:</u></h3>

In math class, Sam correctly multiplied 3.625×10-8 by 500, then reported his product in scientific notation. What was the exponent in Sam’s product? A -16 B -10 C -7 D -5

<h3><u>Answer:</u></h3>

OPTION D

The exponent in Sam’s product is -5

<h3><u>Solution:</u></h3>

Given that,

In math class, Sam correctly multiplied $3.625 \times 10^{-8}$ by 500, then reported his product in scientific notation.

<em><u>To find: exponent in Sam’s product</u></em>

Let us first multiply 500 with $3.625 \times 10^{-8}$

$3.625 \times 10^{-8} \times 500 = 1812.5 \times 10^{-8}$

Then Sam has reported this answer in scientific notation

Lets understand what is scientific notation of any number.

Scientific notation is a way of representing number between 1 and 10 incluing 1 and excluding 10 multiplied by appropriate power of 10.

Let us rewrite the Sam's answer in scientific notation

<em><u>The format for writing a number in scientific notation is:</u></em>

(first digit of the number) followed by (the decimal point) and then (all the rest of the digits of the number), times (10 to an appropriate power).

In $1812.5 \times 10^{-8}$ , we move the decimal 3 times to left side

Since the decimal is moved left side, we multiply by $10^3$

$1812.5 \times 10^{-8} = 1.8125 \times 10^3 \times 10^{-8} \\\\1812.5 \times 10^{-8} = 1.8125 \times 10^{-5}$

Exponent is a quantity representing the power to which a given number or expression is to be raised

So in $1.8125 \times 10^{-5}$ exponent is -5

5 0

2 years ago

The accompanying data are lengths (inches) of bears. Find the percentile corresponding to 65.5 in.

Jlenok [28]

Complete question is missing, so i have attached it.

Answer:

Percentile is 74th percentile

Step-by-step explanation:

All the lengths given are;

Bear Lengths 36.5 37.5 39.5 40.5 41.5 42.5 43.0 46.0 46.5 46.5 48.5 48.5 48.5 49.5 51.5 52.5 53.0 53.0 54.5 56.8 57.5 58.5 58.5 58.5 59.0 60.5 60.5 61.0 61.0 61.5 62.0 62.5 63.5 63.5 63.5 64.0 64.0 64.5 64.5 65.5 66.5 67.0 67.5 69.0 69.5 70.5 72.0 72.5 72.5 72.5 72.5 73.0 76.0 77.5

The number of lengths (inches) of bears given are 54 in number.

We are looking for the percentile corresponding to 65.5 in.

Looking at the lengths given, since they are already arranged from smallest to highest, let's locate the position of 65.5 in.

The position of 65.5 in is the 40th among 54 lengths given.

If the percentile is P, then;

P% x 54 = 40

P = (40 × 100)/54

P ≈ 74

3 0

2 years ago

Find a single expression that represents the area of the outer ring of the circle if the area of the whole circle is represented

sp2606 [1]

Answer: The answer is $A_o=2\pi\sqrt{\dfrac{7}{22}(25x^2-12x-9)}.$

Step-by-step explanation: Given that the area of the whole circle is represented by the expression

$A_c=25x^2-12x-9.$

We are to find the area of the outer ring of the circle, i.e., to find the circumference of the circle.

Now, if 'r' represents the radius of the circle, then we have

$A_c=\pi r^2\\\\\Rightarrow \dfrac{22}{7}r^2=25x^2-12x-9\\\\ \Rightarrow r^2=\dfrac{7}{22}(25x^2-12x-9)\\\\\Rightarrow r=\sqrt{\dfrac{7}{22}(25x^2-12x-9)}.$

Thus, the area of the outer ring is

$A_o=2\pi r=2\pi\sqrt{\dfrac{7}{22}(25x^2-12x-9)}.$

5 0

2 years ago

Sixty-five campers arrive. Nine go home early. If 8 people sleep in 1 tent, how many tents will the campers need?

allsm [11]

65-9=56

56 divided by 8 is 7

So they will need 7 tents

4 0

2 years ago