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Nonamiya [84]
1 year ago
10

A study investigated the job satisfaction of teachers allowed to choose supplementary curriculum for their classes versus teache

rs who were assigned all curricular resources for use in their classes. The authors of the study wanted to know if the two groups of teachers had different levels of job satisfaction. They will use a significance level of 5% for their test. Upper-Tail Values a 5% 2.5% 1% Critical z-values 1.65 1.96 2.58 What is (are) the critical value(s) for z in this study?
Mathematics
1 answer:
Nina [5.8K]1 year ago
6 0
We are given with
5% significance level
Upper-tail values:
5%, 2.5%, and 1%
Critical z-values:
1.65, 1.96, and 2.58

For a 5% significance level, the normal critical z-value is
1.96

Among the choices, for an upper tail value of 5%, the critical z-value is 1.96
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In USA Today (Sept. 5, 1996), the results of a survey involving the use of sleepwear while traveling were listed as follows: Mal
Wewaii [24]

Answers:

a) 0.018.

b) 0.614.

c) 0.166.

d) 0.479

Explanations:

1) Table

----------------------Male ----------- Female ---------- Total

Underwear ----- 0.220 ---------- 0.024 ---------- 0.244

Nightgown ----- 0.002 ---------- 0.180 ------------ 0.182

Nothing --------- 0.160 ----------- 0.018 ------------ 0.178

Pajamas --------- 0.102 ---------- 0.073 ----------- 0.175

T-shirt ------------ 0.046 --------- 0.088 ------------ 0.134

Other --------------0.084 --------- 0.003 ------------ 0.087

2) Check that it is a table of relative frequencies:

total = 0.244 + 0.182 + 0.178 + 0.175 + 0.134 + 0.087 = 1 ⇒ indeed this is a table of relative frequencies.

That means that each data is a probabiilty.

3) Soluitions:

(a) What is the probability that a traveler is a female who sleeps in the nothing?

relative frequency of females that use nothing = 0.018

(b) What is the probability that a traveler is male?

Probability that a traveler is a male = relative frequency of males = 0.220 + 0.002 + 0.160 + 0.102 + 0.046 + 0.084 = 0.614

(c) Assuming the traveler is male, what is the probability that he sleeps in pajamas?

It is the relative frequency of the males that sleep in pajamas divided by the relative frequency of males = 0.102 / 0.614 = 0.166

(d) What is the probability that a traveler is male if the traveler sleeps in pajamas or a T-shirt?

It is the relative frequency of males that sleep in pajamas plus that of the males that sleep in T-shirt, divided the total relative frequency of travelers that sleep in pajamas or T-shirt

i) relative frequency of males that sleeps in pajamas plus that of the males that sleeps in T-shirt = 0.102 + 0.046 = 0.148

ii) relative frequency of travelers that sleep in pajamas or T-shirt = 0.102 + 0.046 + 0.073 + 0.088 = 0.309

iii) quotient = 0.148 / 0.309 = 0.479

5 0
2 years ago
Read 2 more answers
Pedro works as a newspaper deliverer. He receives a base pay plus an additional amount per newspaper delivered. Last week, Pedro
guapka [62]
Answer is

<span>g(x) = 2.5x + 25

</span>5 newspapers, 2.5(5) + 25 = 12.5 + 25 = 37.5
20 newspapers, 2.5(20) + 25 = 50 + 25 = 75
9 0
1 year ago
Read 2 more answers
Jerry makes $40,000 a year working at a nearby factory. He gets two weeks paid vacation per year, plus five other paid holidays.
JulijaS [17]

Answer:

Vacation pays are not included in salaries. Therefore, Jerry's calculation is wrong.

Step-by-step explanation:

Given is :

Jerry makes $40,000 a year working at a nearby factory.

He gets two weeks paid vacation per year, plus five other paid holidays.

So total paid holidays become = 14+5=19 days

Subtracting 19 from 365 days and assuming that Jerry works for 365 days a year.

We get = 365-19=346 days

So, his per day salary will be = \frac{40000}{346}= 115.60

Vacation pays are not included in salaries. Therefore, Jerry's calculation is wrong.

4 0
2 years ago
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Tim was given a large bag of sweets and ate one third of the sweets before stopping as he was feeling sick. The next day he ate
mars1129 [50]

Answer: In the beginning he was given 27 sweets.

Step-by-step explanation: The most logical thing to do is to solve it backwards, that is, from what he had at the end of the third day up till the beginning of the first day.

On the third day he ate one-third and had 8 sweets left over. To determine how many he started with on the third day, let the total on day three be called a. If one-third of a is eaten, then the left over which is two-thirds is 8. That is;

8/a = 2/3

By cross multiplication we now have

8 x 3 = 2a

24/2 = a

a = 12

Let the number of sweets he had on day two be called b. If he ate one-third of b and he had 12 left over, then the two-thirds left over is 12 and we now have;

12/b = 2/3

By cross multiplication we now have

12 x 3 = 2b

36 = 2b

36/2 = b

b = 18

Let the number of sweets he had on day one be called x. If he ate one-third of x and he had 18 left over, then the two-thirds left over is 18, and we now have;

18/x = 2/3

By cross multiplication we now have

18 x 3 = 2x

54 = 2x

x = 27

Therefore Tim was given 27 sweets at the beginning.

3 0
2 years ago
Gina has 5 2/6 feet of silver ribbon and 2 4/6 of gold ribbon. how much more silver ribbon does gina have than golden ribbon?
MrRissso [65]
To answer the question above, we are simply to subtract the length of the gold ribbon which is 2 4/6 ft from the length of the silver ribbon, 5 2/6 feet. Mathematically,
                                5 2/6 feet - 2 4/6 feet = 8/3 feet 
Therefore, Gina has 8/3 feet more of the silver ribbon than the golden ribbon. 
8 0
1 year ago
Read 2 more answers
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