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Nonamiya [84]
2 years ago
10

A study investigated the job satisfaction of teachers allowed to choose supplementary curriculum for their classes versus teache

rs who were assigned all curricular resources for use in their classes. The authors of the study wanted to know if the two groups of teachers had different levels of job satisfaction. They will use a significance level of 5% for their test. Upper-Tail Values a 5% 2.5% 1% Critical z-values 1.65 1.96 2.58 What is (are) the critical value(s) for z in this study?
Mathematics
1 answer:
Nina [5.8K]2 years ago
6 0
We are given with
5% significance level
Upper-tail values:
5%, 2.5%, and 1%
Critical z-values:
1.65, 1.96, and 2.58

For a 5% significance level, the normal critical z-value is
1.96

Among the choices, for an upper tail value of 5%, the critical z-value is 1.96
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Helen is putting a fence around her flower garden, which is in the shape of half of a circle and a rectangle. if the semicircle
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2 years ago
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A hole is drilled in a sheet-metal component, and then a shaft is inserted through the hole. The shaft clearance is equal to dif
VashaNatasha [74]

Answer:

(A)

P(X \geq 0.8) = \int\limits_{0.8}^{\infty} f(x) \, dx  = \int\limits_{0.8}^{1} 1.25(1-x^4) \, dx = 0.08192

(B)

Then the cumulative function would be

CF(x) = 1.25x - 0.25x^5       if   0<x<1

0 otherwise.

Step-by-step explanation:

(A)

We are looking for the probability that the random variable X is greater than 0.8.

P(X \geq 0.8) = \int\limits_{0.8}^{\infty} f(x) \, dx  = \int\limits_{0.8}^{1} 1.25(1-x^4) \, dx = 0.08192

(B)

For any  x you are looking for the probability P(X \geq x)  which is

P(X \geq x)  = \int\limits_{-\infty}^{x}  1.25(1-t^4) dt = \int\limits_{0}^{x}  1.25(1-t^4) dt = 1.25x - 0.25x^2

Then the cumulative function would be

CF(x) = 1.25x - 0.25x^5       if   0<x<1

0 otherwise.

5 0
2 years ago
the population at Saint Maria High increased from 1800 students ten years ago to 1926 students last year. What was the percent i
Ket [755]
It’s a 7% increase. When you want to find percent increase/decrease, you want to subtract the numbers of the before and after. In this case, subtract 1926 and 1800, which will equal 126. Then, percent over 100 would be the first fraction, but since you don’t know the percent, put x. The second fraction is the amount of change over the original number. In this case, the amount of change will be 126 and the original is 1800. x/100=126/1800 now you just cross multiply and solve. You will end up with 7
3 0
2 years ago
Read 2 more answers
Tan 235° = 2tan20°+ tan215°​
Mariulka [41]

Given :  tan 235 = 2 tan 20 + tan 215

To Find : prove that

Solution:

tan 235 = 2 tan 20 + tan 215

Tan x = Tan (180 + x)

tan 235 = tan ( 180 + 55) = tan55

tan 215 = tan (180 + 35) = tan 35

=> tan 55 = 2tan 20 + tan 35

55 = 20 + 35

=> 20  = 55 - 35

taking Tan both sides

=> Tan 20 = Tan ( 55 - 35)

=> Tan 20  = (Tan55 - Tan35) /(1 + Tan55 . Tan35)

Tan35 = Cot55 = 1/tan55 => Tan55 . Tan35 =1

=> Tan 20  = (Tan 55 - Tan 35) /(1 + 1)

=> Tan 20  = (Tan 55 - Tan 35) /2

=> 2 Tan 20  = Tan 55 - Tan 35

=> 2 Tan 20 +  Tan 35 = Tan 55

=>  tan 55 = 2tan 20 + tan 35

=>  tan 235 = 2tan 20 + tan 215

QED

Hence Proved

5 0
2 years ago
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