Ask question

Ask question

All categories

1 year ago

6

Josh works for a construction company that uses 150 pounds of gravel for each driveway they pour. He can buy a dump truck load w

ith 30,000 pounds of gravel or a pick-up truck load with 2,500 pounds. Which amount should he buy so that no gravel is left after all of the driveways are poured and why?

1 answer:

Pavlova-9 [17]1 year ago

5 0

Answer:

Josh should by the dump truck with 30,000 pounds of gravel in it

Step-by-step explanation:

the easiest way to find this out is divide 30,000 and 2,500 by 150 and if the answer is a whole number, then you know that is the correct answer.

30,000/150 = 200

2,500/150 = 16.6666666666666

May I have brainliest please? :)

You might be interested in

An object is moving at a speed of 95 kilometers every 7.5 weeks. Express this speed in

Aleksandr-060686 [28]

Answer:

<h2>5,936.76 feet/day</h2>

Step-by-step explanation:

Formula to use to get the speed is expressed as speed = Distance/Time

Given parameters

Distance = 94km

Time = 7.5weeks

Since we are to express the answer in feet per day, we will convert the distance to feet and time to days.

For the distance:

Given the conversion

1 km = 3280.84 feet

95km = (95*3280.84)feet

95km = 311,679.8 feet

For the time:

If 1 week = 7 days

7.5weeks = (7.5 * 7)

7.5weeks = 52.5 days

Speed In ft/day = 311,679.8 feet/ 52.5 days

Speed in ft/day = 5,936.76 feet/day

<em>Hence the speed in feet per day is 5,936.76 feet/day</em>

3 0

2 years ago

Evaluate the triple integral ∭ExydV where E is the solid tetrahedon with vertices (0,0,0),(5,0,0),(0,9,0),(0,0,4).

Elan Coil [88]

Answer: $\int\limits^a_E {\int\limits^a_E {\int\limits^a_E {xy} } \, dV$ = 1087.5

Step-by-step explanation: To evaluate the triple integral, first an equation of a plane is needed, since the tetrahedon is a geometric form that occupies a 3 dimensional plane. The region of the integral is in the attachment.

An equation of a plane is found with a point and a normal vector. <u>Normal</u> <u>vector</u> is a perpendicular vector on the plane.

Given the points, determine the vectors:

P = (5,0,0); Q = (0,9,0); R = (0,0,4)

vector PQ = (5,0,0) - (0,9,0) = (5,-9,0)

vector QR = (0,9,0) - (0,0,4) = (0,9,-4)

Knowing that cross product of two vectors will be perpendicular to these vectors, you can use the cross product as normal vector:

n = PQ × QR = $\left[\begin{array}{ccc}i&j&k\\5&-9&0\\0&9&-4\end{array}\right]$ $\left[\begin{array}{ccc}i&j\\5&-9\\0&9\end{array}\right]$

n = 36i + 0j + 45k - (0k + 0i - 20j)

n = 36i + 20j + 45k

Equation of a plane is generally given by:

$a(x-x_{0}) + b(y-y_{0}) + c(z-z_{0}) = 0$

Then, replacing with point P and normal vector n:

$36(x-5) + 20(y-0) + 45(z-0) = 0$

The equation is: 36x + 20y + 45z - 180 = 0

Second, in evaluating the triple integral, set limits:

In terms of z:

$z = \frac{180-36x-20y}{45}$

When z = 0:

$y = 9 + \frac{-9x}{5}$

When z=0 and y=0:

x = 5

Then, triple integral is:

$\int\limits^5_0 {\int\limits {\int\ {xy} \, dz } \, dy } \, dx$

Calculating:

$\int\limits^5_0 {\int\limits {\int\ {xyz} \, dy } \, dx$

$\int\limits^5_0 {\int\limits {\int\ {xy(\frac{180-36x-20y}{45} - 0 )} \, dy } \, dx$

$\frac{1}{45} \int\limits^5_0 {\int\ {180xy-36x^{2}y-20xy^{2}} \, dy } \, dx$

$\frac{1}{45} \int\limits^5_0 {90xy^{2}-18x^{2}y^{2}-\frac{20}{3} xy^{3} } \, dx$

$\frac{1}{45} \int\limits^5_0 {2430x-1458x^{2}+\frac{94770}{125} x^{3}-\frac{23490}{375}x^{4} } \, dx$

$\frac{1}{45} [30375-60750+118462.5-39150]$

$\int\limits^5_0 {\int\limits {\int\ {xyz} \, dy } \, dx$ = 1087.5

<u>The volume of the tetrahedon is 1087.5 cubic units.</u>

3 0

2 years ago

Large flower pots weigh 28 pounds each.

LiRa [457]

Answer:

The correct answer is: 980 pounds

Step-by-step explanation:

1 flower pot = 28 pounds

1 crate = 35 pots

∴ 1 crate = 35 pots × 28 pounds = 980 pounds

5 0

2 years ago

Read 2 more answers

Annual income of A is 10% more than of B whereas income of B is 20% more than that of C. If monthly income of C is $ 2000 then w

Vanyuwa [196]

Answer:

7040

Step-by-step explanation:

C= 2000

B = 20/100 x 2000 = 400 + 2000 = 2400

A= 10/100 x 2400 = 240+2400= 2640

2000 + 2400 + 2640 = 7040

3 0

1 year ago

Management is considering adopting a bonus system to increase production. One suggestion is to pay a bonus on the highest 5 perc

Olegator [25]

Answer:

The bonus will be paid on at least 4099 units.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the percentile of this measure.

In this problem, we have that:

The highest 5 percent is the 95th percentile.

Past records indicate that, on the average, 4,000 units of a small assembly are produced during a week. The distribution of the weekly production is approximately normally distributed with a standard deviation of 60 units. This means that $\mu = 4000, \sigma = 60$ .

If the bonus is paid on the upper 5 percent of production, the bonus will be paid on how many units or more?

The least units that the bonus will be paid is X when Z has a pvalue of 0.95.

Z has a pvalue of 0.95 between 1.64 and 1.65. So we use $Z = 1.645$

$Z = \frac{X - \mu}{\sigma}$

$1.645 = \frac{X - 4000}{60}$

$X - 4000 = 60*1.645$

$X = 4098.7$

The number of units is discrete, this means that the bonus will be paid on at least 4099 units.

5 0

2 years ago