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Bumek [7]
2 years ago
9

Shelley is self-employed in Texas and recently attended a two-day business conference in New Jersey. After Shelley attended the

conference, she had dinner with an old friend who lived nearby. Shelley documented her expenditures (described below). What amount can Shelley deduct?
Mathematics
1 answer:
MaRussiya [10]2 years ago
7 0

Answer:

The amount deductible by Shelley is $2,929

Step-by-step explanation:

Using the table below as the missing information:

Airfare to New Jersey $ 2,180

Meals $238

Lodging in New Jersey $432

Rental car $198

All the above expenses are fully deductible by Shelley except the meal which is half deductible.

Half of the meal expenses is:

= 238 / 2 = $119

So the amount deductible by Shelley is:

2180 + 119 + 432 + 198

= 2929

Therefore, the amount deductible by Shelley is $2,929

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Terry made a plastic birdhouse with the dimensions shown below. How many square inches
xxMikexx [17]

Answer:

376 squared inches for the hole bird house, 60 for the side with the whole.

Step-by-step explanation:

1 side is 60 inches squared, another is 48 inches squared, and another is 80 inches squared, and there are two of each side so you get 120+96+160= 376.

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2 years ago
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5% of people receiving your email opened it. 1% of people receiving your email click a link. Of those who opened the email, what
zubka84 [21]
1% of people click the link

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2 years ago
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Using the technique in the model above, find the missing segments in this 30°-60°-90° right triangle. AB = 8 BC = 4 CD =
zimovet [89]
For a 30-60-90 triangle the sides always have the same relationship
Short leg = a
Long leg = a√3
Hypotenuse = 2a

BC is the short leg of ∆ABC

Given BC = 2
BC = a
Therefor
a = 2
AB = 2a = 4
AC = a√3 = 2√3

For ∆ACD
As above AC = 2√3
Since AC is the hypotenuse of ∆ACD
2a = 2√3
a = √3

CD = a = √3
AD = a√3 = 3

For ∆BCD
As above
BC = 2
CD = √3
Since BC is the hypotenuse of ∆BCD
2a = 2
a = 1

DB = a = 1
6 0
2 years ago
Read 2 more answers
A carpool service has 2,000 daily riders. A one-way ticket costs $5.00. The service estimates that for each $1.00 increase to th
solmaris [256]

Answer:

Total number of riders that ride on carpool daily = 2000

Total Cost of one way ticket = $ 5.00

Total Amount earned if 2000 passengers rides daily on carpool = 2000 × 5

                                                                                                            = $10,000

If fare increases by $ 1.00

New fare = $5 + $1    

               = $6

Number of passengers riding on carpool = 2,000 - 100 = 1,900

If 1,900 passengers rides on carpool daily , total amount earned ,if cost of each ticket is $ 6 = 1900 × $6 = $11400

As we have to find the inequality which represents the values of x that would allow the carpool service to have revenue of at least $12,000.

For $ 1 increase in fare = (2,000 - 1 × 100) passengers

For $ x increase in fare, number of passengers = 2,000 - 100·x

                                                         = (2,000 - 100·x) passengers

New fare = 5 + x

New Fare × Final Number of passengers ≥ 12,000

(5+x)·(2,000 - 100 x) ≥ 12,000

5 (2,000 - 100 x) + x(2,000 - 100 x) ≥ 12,000

10,000 - 500 x + 2,000 x - 100 x² ≥ 12,000

100 - 5 x + 20 x - x² ≥ 120

- x² + 15 x +100 - 120 ≥ 0

-x² + 15 x -20 ≥ 0

x² - 15 x + 20 ≤ 0

⇒ x = 1.495

x ≥ $ 1.495, that is if we increase the fare by this amount or more than this the revenue will be at least 12,000 or more .

Also, f'(x) = 0 gives x = 7.5

⇒ The price of a one-way ticket that will maximize revenue is $7.50

7 0
2 years ago
According to the Rational Root Theorem, what are all the potential rational roots of f(x) = 15x11 – 6x8 + x3 – 4x + 3?
scoundrel [369]

we have

f(x) = 15x^{11} -6x^{8} + x^{3} - 4x + 3

we know that

<u>The Rational Root Theorem</u> states that when a root 'x' is written as a fraction in lowest terms

x=\frac{p}{q}

p is an integer factor of the constant term, and q is an integer factor of the coefficient of the first monomial.

So

in this problem

the constant term is equal to 3

and the first monomial is equal to 15x^{11} -----> coefficient is 15

So

possible values of p are 1, and\ 3

possible values of q are 1, 3, 5, and\ 15

therefore

<u>the answer is</u>

The all potential rational roots of f(x) are

(+/-)\frac{1}{15},(+/-)\frac{1}{5},(+/-)\frac{1}{3},(+/-)\frac{3}{5},(+/-)1,(+/-)3


3 0
2 years ago
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