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Taya2010 [7]
2 years ago
6

A cylinder has its height doubled and its radius cut to 1/3. What is the ratio of the volumes of the modified cylinder to the or

iginal cylinder
Mathematics
2 answers:
bearhunter [10]2 years ago
7 0
Let height of a cylinder is h and radius be r
volume of cylinder = πr*r*h
if height is doubled then height becomes =2h
radius becomes one third= 1/3 r
volume of cylinder becomes= π*1/3r*1/3r*2h =2/9πr*r*h
ratio of original cylinder to new one = 9/2
STALIN [3.7K]2 years ago
6 0
1 is to 4.5; the original cylinder was 3.14 and the modified cylinder was .698
(I ignored units)
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50 people consume an average of 110 kg of rice in a week. If 20 more people join this group, how many kilograms of rice will be
Alisiya [41]
110/50=2.2 (each person consumes 2.2 kg of rice)

50+20 (the people who join)=70 total of people

70X2.2= 154 kg of rice.
5 0
2 years ago
One coin is randomly selected from a jar containing 20 pennies, 15 nickels, 3 dimes, and 12 quarters. What is the odds of a valu
Aliun [14]
Total coins in the jar = 50. Number of coins with a value less than $0.05 = 20 (the pennies). ... Probability of picking a penny = 20/50 = 40%. ... 'Odds' = 3 to 2 against it.
6 0
2 years ago
Solve x2 = 12x – 15 by completing the square. Which is the solution set of the equation? (negative 6 minus StartRoot 51 EndRoot
Amanda [17]

Answer:

LAST OPTION: (6-\sqrt{21},6+\sqrt{21})

Step-by-step explanation:

1. Subtract 12x from both sides of the equation:

x^2-12x= 12x- 15-12x\\\\x^2-12x=-15

2. Since b=12:

(\frac{b}{2})^2=(\frac{12}{2})^2=(6)^2

3. Now can complete the square. Add (6)^2 to both sides of the equation:

x^2-12x+6^2=-15+6^2

4. Simplifying:

(x-6)^2=21

5. Solve for "x":

\sqrt{(x-6)^2}=\±\sqrt{21}\\\\x-6=\±\sqrt{21}\\\\x=6\±\sqrt{21}\\\\x_1=6+\sqrt{21}\\\\x_2=6-\sqrt{21}

6. The solution set is:

(6-\sqrt{21},6+\sqrt{21})

3 0
2 years ago
Read 2 more answers
The grade appeal process at a university requires that a jury be structured by selecting individuals randomly from a pool of stu
tatiyna

Correct question is ;

The grade appeal process at a university requires that a jury be structured by selecting eight individuals randomly from a pool of nine students and eleven faculty.​ (a) What is the probability of selecting a jury of all​ students? (b) What is the probability of selecting a jury of all​ faculty? (c) What is the probability of selecting a jury of six students and two ​faculty?

Answer:

A) 7.144 × 10^(-5)

B) 0.00131

C) 0.0367

Step-by-step explanation:

We are given;

Number of students = 9

Number of faculty members = 11

A) Now, the number of ways we can select eight students from 9 =

C(9, 8) = 9!/(8! × 1!) = 9

Also, number of ways of selecting 8 individuals out of the total of 20 = C(20,8) = 20!/(8! × 12!) = 125970

Thus, probability of selecting a jury of all​ students = 9/125970 = 7.144 × 10^(-5)

B) P(selecting a jury of all faculty) = (number of ways to choose 8 faculty out of 11 faculty)/(Total number of ways to choose 8 individuals out of 20 individuals) = [C(11,8)]/[C(20,8)] = (11!/(8! × 3!))/125970 = 0.00131

C) P(selecting a jury of six students and two faculty) = ((number of ways to choose 6 students out of 9 students) × (number of ways to choose 2 faculty out of 11 faculty))/(Total number of ways to choose 8 individuals out of 20 individuals) = [(C(9,6) × C(11,2)]/125970

This gives;

(84 × 55)/125970 = 0.0367

4 0
2 years ago
Help me pleaseeee!!!!!
Julli [10]

Because she needs 3 blankets and it takes 15 day per blanket(rate is given), she needs 3x15 or 45 days. She has 60 days so she can volunteer at most 15 days.

answer: s≤15

4 0
2 years ago
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