Hey
So my brother posted this on Yahoo
Draw a line from the center of the circle to one of the ends of the chord (water surface) and another to the point at greatest depth. A right-angled triangle is formed. Length of side to the water-surface is 5 cm, the hypot is 7 cm.
<span>What you do now is the following: </span>
<span>Calculate the angle θ in the corner of the right-angled triangle by: cos θ = 5/7 ⇒ θ = cos ˉ¹ (5/7) </span>
<span>So θ is approx 44.4°, so the angle subtended at the center of the circle by the water surface is roughly 88.8° </span>
<span>The area shaded will then be the area of the sector minus the area of the triangle above the water in your diagram. </span>
<span>Shaded area ≃ 88.8/360*area of circle - ½*7*7*sin88.8° </span>
<span>= 88.8/360*π*7² - 24.5*sin 88.8° </span>
<span>≃ 13.5 cm² </span>
<span>(using area of ∆ = ½.a.b.sin C for the triangle) </span>
<span>b) </span>
<span>volume of water = cross-sectional area * length </span>
<span>≃ 13.5 * 30 cm³ </span>
<span>≃ 404 cm³</span>
Hoped it Helped
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Answer: There are 20 socks in the first case and there are 75 socks in the second case.
Step-by-step explanation:
Since we have given that
Number of equal groups = 5
Let the total number of socks be 's'.
According to question, expression will be
Now, Suppose number of socks in each group = 4
So, it will become,
Suppose number of socks in each group = 15
So, Total number of socks become
Hence, there are 20 socks in the first case and there are 75 socks in the second case.
Answer:
a
Step-by-step explanation:
After d days, the loaf of bread is 65 - 15d long.
l = 65 - 15d.
The graph is discrete, as he cannot cut the bread for 1.5 days, or cut 5cm of the bread off.
Answer:
Step-by-step explanation:
We have been given an equation 
. We are asked to solve our given equation.
First of all, we will add 
on both sides of equation to separate x variable on one side of equation.
Now, we will make a common denominator.
Add numerators:
Upon multiply both sides of our equation by 
, we will get:
Therefore, the solution for our given equation is .
