Alexis has a rectangular piece of red paper that is 4 cm wide its length is twice its width she Glooze a rectangular r Alexis ha
2 answers:
Answer:
11 square centimeters of red paper will be visible on top.
Step-by-step explanation:
Width of the rectangular red sheet = w = 4 cm
Length of the rectangular red sheet = l = 2 × 4 cm = 8 cm
Area of the rectangle = l × w
Area of the rectangular red sheet = A
Width of the rectangular blue sheet = w' = 3 cm
Length of the rectangular blue sheet = l' = 7 cm
Area of the rectangular blue sheet = A'
After gluing blue paper on the top of red paper. The area of red paper that will be visible from the top is:
A - A' =
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There are a couple of different approaches you can use for this. Here's one.
1. Determine how many digits repeat. (There is just one repeating digit.)
2. Call your number x. Multiply x by 10 to the power of the number of digits found in step 1.
3. Subtract the original number, then solve for x.
_____
If you recognize that 0.333... (repeating) is 1/3, then you know that 0.0333... (repeating) is 1/10×1/3 = 1/30. Add that to 0.8 = 4/5 and you get
... 4/5 + 1/30 = 24/30 + 1/30 = 25/30 = 5/6
Answer:
They are similar for their radii, and perimeters have the same ratio: 2
Step-by-step explanation:
The similarity of circles is proved, when we can compare the ratio, between the two radii and the two perimeter and it is the same.
2. The Circle X, has a radius of 6 and the circle Y has the radius of 3.
So let's do it:
3. Now let's check the Perimeters:
4. In addition to this, we can do this Geometrically, by inserting the Circle Y within the Circle X, and if dilate by the scale factor of 2 we'll have these two circumferences coincide.
Answer:
The score that separates the lower 5% of the class from the rest of the class is 55.6.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question:
Find the score that separates the lower 5% of the class from the rest of the class.
This score is the 5th percentile, which is X when Z has a pvalue of 0.05. So it is X when Z = -1.645.
The score that separates the lower 5% of the class from the rest of the class is 55.6.