Garth estimated the height of the door to his classroom in meters what is a reasonable estimate

Which expression is equivalent to (x^6y^8)^3\x^2y^2

Damm [24]

Answer:

$\large\boxed{\dfrac{(x^6y^8)^3}{x^2y^2}=x^{16}y^{22}}$

Step-by-step explanation:

$\dfrac{(x^6y^8)^3}{x^2y^2}\qquad\text{use}\ (ab)^n=a^nb^n\ \text{and}\ (a^n)^m=a^{nm}\\\\=\dfrac{(x^6)^3(y^8)^3}{x^2y^2}=\dfrac{x^{(6)(3)}y^{(8)(3)}}{x^2y^2}=\dfrac{x^{18}y^{24}}{x^2y^2}\qquad\text{use}\ \dfrac{a^m}{a^n}=a^{m-n}\\\\=x^{18-2}y^{24-2}=x^{16}y^{22}$

5 0

2 years ago

Read 2 more answers

Which statement is correct? StartFraction 3.56 times 10 Superscript 2 Baseline Over 1.09 times 10 Superscript 4 Baseline EndFrac

stellarik [79]

Mannn what the heck...it’s so confusing sorry I couldn’t read.its messing

5 0

2 years ago

Read 2 more answers

the table below shows a proportional relationship fill in the missing values servings 12 ,4 16 ,8 ounces 21 ? ? ? please help wi

Karolina [17]

Answer: the missing values are 7, 28 and 14

Step-by-step explanation:

In a proportional relationship, there is a constant relationship between the given variables. Thus, for any change in the value of one variable, there is a corresponding change in the value of the other variable.

The table shows a proportional relationship between values of servings

12 ,4 16 ,8

and values of ounces

21 ? ? ?

Let the missing values be x, y and z

Therefore,

21/12 = x/4

1.75 = x/4

x = 4 × 1.75

x = 7

21/12 = y/16

y = 16 × 1.75 = 28

21/12 = z/8

z = 1.75 × 8 = 14

3 0

2 years ago

If e^(xy) = 2, then what is dy/dx at the point (1, ln2)

PSYCHO15rus [73]

By implicit differentiation:

(x(dy/dx) + y)e^(xy) = 0 

Note that when differentiating e^(xy), apply chain rule. When differentiating xy, use product rule. Also: When differentiating y w/respect to x, think of that as if you are differentiating f(x). 

Then, substitute (1,ln(2)) and solve for dy/dx. 

(1(dy/dx) + ln(2))e^(1ln(2)) = 0 
((dy/dx) + ln(2))e^(ln(2)) = 0 

Note that e^(ln(2)) = 2 since e and ln are inverse of each other. 

2((dy/dx) + ln(2)) = 0 
dy/dx + ln(2) = 0 . . . . You get this expression by dividing both sides by 2 
dy/dx = -ln(2) . . . . . . .Subtract both sides by ln(2) 

Therefore, dy/dx = -ln(2) 

I hope this helps!

8 0

2 years ago

Is AB parallel to Bo? Explain.

Svetradugi [14.3K]

Answer:

AB parallel to CD because both lines have a slope of

of 4/3

Step-by-step explanation:

The question is not complete, there is no graph.

A graph for the question is attached below.

From the image attached below, line 1 passes through points A = (-3, -3) and point B = (0, 1) while line 2 passes through point C = (0, -5) and point D = (3, -1).

Two parallel are said to be parallel if the have the same slope. The slope of a line passing through points:

$(x_1,y_1)\ asnd\ (x_2,y_2).\ The\ slope \ is\ given\ as:\\\\Slope(m)=\frac{y_2-y_1}{x_2-x_1}$

Line 1 passes through points A = (-3, -3) and point B = (0, 1), the slope of line 1 is:

$Slope(m)=\frac{y_2-y_1}{x_2-x_1}=\frac{1-(-3)}{0-(-3)}=\frac{1+3}{0+3}=\frac{4}{3}$

Line 2 passes through point C = (0, -5) and point D = (3, -1). the slope of line 2 is:

$Slope(m)=\frac{y_2-y_1}{x_2-x_1}=\frac{-1-(-5)}{3-0}=\frac{-1+5}{3}=\frac{4}{3}$

Therefore AB parallel to CD because both lines have a slope of

of 4/3

7 0

2 years ago