Answer:
The width of lot B is 11 feet, so option A is correct.
Step-by-step explanation:
Given:
- Two rectangular properties share a common side.
- Lot A is 33 feet wide and 42 feet long.
- The combined area of the lots = 1,848 square feet.
To find:
How many feet wide is Lot B?
Solution:
we know that, area of a rectangle is length x breadth
Then area of lot A = 33 x 42 = 1386 square feet.
And area of lot B = width x 42
Now, we are given that, total area = 1848
area of lot A + area of lot B = 1848
1386 + width x 42 = 1848
width x 42 = 1848 – 1386
width x 42 = 462

width = 11
Hence, the width of lot B is 11 feet, so option A is correct.
1. multiply 250 by 10% (250 * .1= 25)
2. Then subtract 25 from 250 (250 -25= 225)
2. Then multiply 225 by 16% (225 * .16 = 36)
3. Add 225 + 36 = 261.
4. 261 is your final answer
Answer:

5 StartRoot 10 EndRoot
Step-by-step explanation:
we know that
The legs of a 45°-45°-90° triangle are congruent
Let
x ----> the length of one leg of the triangle
Applying the Pythagorean Theorem

where
c is the hypotenuse
a and b are the legs
we have


substitute


Simplify

5 StartRoot 10 EndRoot