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Naddika [18.5K]
1 year ago
7

What is the quadratic regression equation that fits these data?

Mathematics
2 answers:
Tresset [83]1 year ago
5 0

Answer:

the answer is a.

Step-by-step explanation:

I plugged your data into a graphing calculator, and got a quad reg in the picture.

lions [1.4K]1 year ago
4 0
<h2>Answer:</h2>

Option: A is the correct answer.

The quadratic equation that fits these data is:

            A.   y=2.09x^2+0.33x+3.06

<h2>Step-by-step explanation:</h2>

We are given a table of values as:

    x          y

    -4        35

    -3        20

    -2         12

    -1           6

    0           2

     1           6

     2          10

     3          24

     4          38

From the given data values we see that the points follow a parabolic path this means that the line of best fit will has a quadratic equation.

Also, the line that best represents these data points as is done by the regression calculator is:

                A.   y=2.09x^2+0.33x+3.06

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This is a simple programming question. To calculate the average of any two numbers, where one number is 1 and the other is n, simply add the two numbers and divide by 2. Therefore, the answer is:
<span>avg = (1 + n) / 2</span> 
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Mrs. Thomas has $71.00 to purchase bottles of juice for her class. If the bottles of juice cost $3.55 each, how many bottles can
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B) 20
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2 years ago
Julissa is running a 10-kilometer race at a constant pace. After running for 18 minutes, she completes 2 kilometers. After runni
trasher [3.6K]

For this case, the first thing we must do is define variables.

We have then:

t: the time in minutes

k: the number of kilometers

The relationship between both variables is direct.

Therefore, the function is:

k (t) = c * t

Where, "c" is a constant of proportionality.

To determine "c" we use the following data:

After running for 18 minutes, she completes 2 kilometers.

Substituting values:

2 = c * 18

Clearing c we have:

c = \frac{2}{18}

c = \frac{1}{9}

Then, the equation is given by:

k (t) = \frac{1}{9} * t

Answer:

An equation that can be used to represent k, the number of kilometers Julissa runs in t minutes is:

k (t) = \frac{1}{9} * t

7 0
2 years ago
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In ΔPQR, p = 220 inches, q = 890 inches and ∠R=121°. Find the length of r, to the nearest inch.
Veronika [31]

Answer:

1021

Step-by-step explanation:

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6 0
1 year ago
The taxi and takeoff time for commercial jets is a random variable x with a mean of 8.3 minutes and a standard deviation of 3.3
In-s [12.5K]

Answer:

a) There is a 74.22% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

b) There is a 1-0.0548 = 0.9452 = 94.52% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes.

c) There is a 68.74% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

The taxi and takeoff time for commercial jets is a random variable x with a mean of 8.3 minutes and a standard deviation of 3.3 minutes. This means that \mu = 8.3, \sigma = 3.3.

(a) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes?

We are working with a sample mean of 37 jets. So we have that:

s = \frac{3.3}{\sqrt{37}} = 0.5425

Total time of 320 minutes for 37 jets, so

X = \frac{320}{37} = 8.65

This probability is the pvalue of Z when X = 8.65. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{8.65 - 8.3}{0.5425}

Z = 0.65

Z = 0.65 has a pvalue of 0.7422. This means that there is a 74.22% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

(b) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes?

Total time of 275 minutes for 37 jets, so

X = \frac{275}{37} = 7.43

This probability is subtracted by the pvalue of Z when X = 7.43

Z = \frac{X - \mu}{\sigma}

Z = \frac{7.43 - 8.3}{0.5425}

Z = -1.60

Z = -1.60 has a pvalue of 0.0548.

There is a 1-0.0548 = 0.9452 = 94.52% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes.

(c) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes?

Total time of 320 minutes for 37 jets, so

X = \frac{320}{37} = 8.65

Total time of 275 minutes for 37 jets, so

X = \frac{275}{37} = 7.43

This probability is the pvalue of Z when X = 8.65 subtracted by the pvalue of Z when X = 7.43.

So:

From a), we have that for X = 8.65, we have Z = 0.65, that has a pvalue of 0.7422.

From b), we have that for X = 7.43, we have Z = -1.60, that has a pvalue of 0.0548.

So there is a 0.7422 - 0.0548 = 0.6874 = 68.74% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes.

7 0
2 years ago
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