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inessss [21]
2 years ago
6

Margo deposited $100 into a savings account earning 4.5% simple annual interest. At the end of each year, she adds $100 to her a

ccount. Fill in the table below to figure out how much money was in Margo's account at the end of 3 years.
Mathematics
1 answer:
nadezda [96]2 years ago
7 0

Answer:

                    principal     interest              total money in account

                                                                         at the end of year

Year one       $100             $4.5                              $104.5

year two        $200          $ 9 +$4.5                         $ 213.5

year three      $300          $ 9 +$4.5 + $13.5           $ 327

Step-by-step explanation:

Simple interest for any principal is given by

I = p* r* t/100

I = interest rate accrued on principle amount

p is the amount deposited

r is the rate of interest

t is the time period of saving

_______________________________________________

For year one

p = $100

r = 4.5%

t=1

I = 100*4.5*1/100 = 4.5

_______________________________________________

For year two $100 more is added to already existing $100 in account.

p = 100 +100 = $200

r = 4.5%

t=1

I = 200*4.5*1/100 = 9

_______________________________________________

For year two $100 more is added to already existing $200 in account after two years.

p = 100 +100 +100 = $300

r = 4.5%

t=1

I = 300*4.5*1/100 = 13.5

_______________________________________________

There fore total  money in Margo account is

$300 saving deposited by her

$4.5 + $9 + $13.5 = $27 (interest accrued in three time)

Formulating the results in tabular form

                     principal     interest    total money in account

                                                            at the end of year

Year one       100               4.5                      104.5

year two        200           9 +4.5                     213.5

year three      300           9 +4.5 + 13.5           327

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jose is choosing a 3-letter password from the letters a,b,c,d. the password cannot have the same letter repeated in it. how many
kvasek [131]
Alright, so we are dealing with permutations. Permutations are the number of combinations in a specific order possible for the set. 

There's 4 letters, each one can be paired with 3 other letters, but those letters could be in different orders. To figure out how many variations of each combination there are (aka the number of permutations) use this formula:

_{n}P_{r}= \frac{n!}{(n-r)!}

r= number of elements in the subset

n= number of elements in the set

P= permutations of the set

There are only 3 elements in the subset because there is 1 that will not be repeated in each set, and there are 4 elements in the set.

Here's the math:

_{n}P_{r}= \frac{n!}{(n-r)!}

_{4}P_{3}= \frac{4!}{(4-3)!}

_{4}P_{3}= \frac{4!}{(1)!}

_{4}P_{3}= \frac{4(3)(2)(1)}{1}

_{4}P_{3}=24

There are 24 permutations. I can prove this by showing you the model:

ABCD, ABDC, ACBD, ACDB, ADBC, ADCB are the 6 arrangements possible of the set starting with the letter A. Because there are 4 letters, the total amount of permutations without repeated letters is 4 (letters) times 6 (possible arrangements), which equals 24.

Hope this helps!

Answer: 24 passwords are possible
5 0
2 years ago
Ms. Nina has 10 lbs of 25% sugar syrup. How much water does she need to add to make 10% sugar syrup
Inessa [10]
10*0.25=2.5
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25-10=15 lbs
Nina need to add 15 lbs of water
7 0
2 years ago
According to a Los Angeles Times study of more than 1 million medical dispatches from 2007 to 2012, the 911 response time for me
Reil [10]

Answer:

a) \bar X=10.65

Median =\frac{10.7+10.7}{2}=10.7

Mode= 10.7

b) Range = 11.8-8.3=3.5

s= 0.948

c)IQR = Q_3 -Q_1 = 11.05-10.55=0.5

And we can find the usual limits with:

Lower = Q_1 -1.5 IQR = 10.55 -1.5*0.5=9.8

Upperer = Q_3 +1.5 IQR = 10.55 +1.5*0.5=11.3

And since 8.3 <9.8 we can consider this value too low or as an outlier for this case.

d) The mean for this case was 10.65 and the usual values are between 9.8 and 11.3, so as we can see all are above the specified value of 6 minutes, and we can conclude that the times are not satisfying the quality standards for this case.

And they should be considered apply some strategies to reduce the response time, adding more stations around points selected at the city could be useful in order to reduce the response time.

Step-by-step explanation:

We have the following data:

11.8 10.3 10.7 10.6 11.5 8.3 10.5 10.9 10.7 11.2

Part a

We can calculate the sample mean with the following formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And if we replace we got: \bar X=10.65

For the median we need to sort the values on increasing order and we have:

8.3 10.3 10.5 10.6 10.7 10.7 10.9 11.2 11.5 11.8

Since n =10 we can calculate the median as the average between the 5th and 6th position of the dataset ordered and we got:

Median =\frac{10.7+10.7}{2}=10.7

The mode would be the most repeated value on this case:

Mode= 10.7

Part b

The range is defined as Range =Max-Min and if we replace we got:

Range = 11.8-8.3=3.5

We can calculate the standard deviation with the following formula:

s= sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And if we replace we got:

s= 0.948

Part c

For this case we can use the IQR method in order to determine if 8.3 is an outlier or not.

We can calculate the first quartile with these values: 8.3 10.3 10.5 10.6 10.7 10.7 and Q_1= \frac{10.6+10.7}{2}=10.55

And for the Q3 we can use: 10.7 10.7 10.9 11.2 11.5 11.8 and we got Q_3 = \frac{10.9+11.2}{2}=11.05

Then we can find the IQR like this:

IQR = Q_3 -Q_1 = 11.05-10.55=0.5

And we can find the usual limits with:

Lower = Q_1 -1.5 IQR = 10.55 -1.5*0.5=9.8

Upperer = Q_3 +1.5 IQR = 10.55 +1.5*0.5=11.3

And since 8.3 <9.8 we can consider this value too low or as an outlier for this case.

Part d

The mean for this case was 10.65 and the usual values are between 9.8 and 11.3, so as we can see all are above the specified value of 6 minutes, and we can conclude that the times are not satisfying the quality standards for this case.

And they should be considered apply some strategies to reduce the response time, adding more stations around points selected at the city could be useful in order to reduce the response time.

6 0
2 years ago
In the diagram, transversal t cuts across the parallel lines a and b. Match the pairs of angles with the relationship that shows
charle [14.2K]

we know that

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m∠5=m∠8 --------> by vertical angles

m∠6=m∠7 --------> by vertical angles

therefore

the answer in the attached figure

5 0
2 years ago
Katie has a necklace for $14.5 plus 6% tax. sharon buys a bracelet for $12 plus 6% tax. enter the sum, in dollars, that Katie an
REY [17]
$28.09
Because 6 percent of both of them combined is 1.59
1.59 + 14.5 + 12 = $28.09 
5 0
2 years ago
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