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snow_lady [41]
1 year ago
14

Assume that a fair die is rolled. The sample space is , 1, 2, 3, 4, 56, and all the outcomes are equally likely. Find P8. Expres

s your answer in exact form.
Mathematics
1 answer:
liraira [26]1 year ago
5 0

Answer:

P\left(8\right)=0

Step-by-step explanation:

Assuming that a fair die is rolled.

  • The sample space is 1, 2, 3, 4, 5, 6 and all the outcomes are equally likely.

Let  X  be the set of all possible outcomes. Let  A  be an outcome.

So, the probability that  A  occurs is:

                                                        P\left(A\right)=\frac{|A|}{|X|}

As the set of all possible outcomes of the roll of a single die is:

X=\left\{1,2,3,4,5,6\right\}

Observe that

|X|=6

Here  

|A|=0   because 8 is not in the set sample space. So, the outcome of occurring the number 8 is not possible from the all possible outcomes.

So, the probability must be zero.

In other words,

                        P\left(A\right)=\frac{|A|}{|X|}

                         P\left(8\right)=\frac{0}{6}=0

Therefore,

                   P\left(8\right)=0

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Step-by-step explanation:

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