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Orlov [11]
1 year ago
12

Una avenida está siendo asfaltada por etapas. En la primera etapa se asfaltó la mitad; en la segunda, la quinta parte, y en la t

ercera, la cuarta parte del total. ¿Cuál es la longitud de la avenida si aún faltan 200 m por asfaltar?
Mathematics
1 answer:
s344n2d4d5 [400]1 year ago
7 0

Answer:

Sabemos que:

L es el largo de la avenida.

En la primer etapa se asfalto la mitad, L/2, entonces lo que queda por asfaltar es:

L - L/2 = L/2.

En la segunda etapa se asfalto la quinta parte, L/5, entonces lo que queda por asfaltar es:

L/2 - L/5 = 5*L/10 - 2*L/10 = (3/10)*L

En la tercer etapa se asfalto la cuarta parte del total, L/4, entonces lo que queda por asfaltar es:

(3/10)*L - L/4 = 12*L/40 - 10L/40 = (2/40)*L

Y sabemos que este ultimo pedazo que queda por asfaltar es de 200m:

(2/40)*L = 200m

L = 200m*(40/2) = 4,000m

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myrzilka [38]

Answer:

Brian had $30 initially.Brian had $30 initially.

Step-by-step explanation:

WE are given the following in the question:

Let Brian have x dollars and Colin have y dollars.

Ration of Brian's money to Colin's money is 5:1. This, we can write the equation:

\dfrac{x}{y} = \dfrac{5}{1}\\\\x = 5y

"Brian spent £27 that day. Brian now had £3 less than Colin."

Thus, we can write the equation:

x-27 = y-3\\x-y = 24

Solving the two equation by substitution, we get,

x - y - 24\\5y - y = 24\\4y = 24\\y=6\\x = 5y =30

Thus, Brian had $30 initially.

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1 year ago
Tricia saved money, but the amount she saved didn't meet both her emergency needs and savings for her goal. Which of these would
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Tricia should take the money that she already has saved no matter how little it is and split it evenly between savings and emergency needs
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2 years ago
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An element with mass 210 grams decays by 8.3% per minute. How much of the element is remaining after 15 minutes, to the nearest
alexandr1967 [171]

Answer:

57.2 g

Step-by-step explanation:

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2 years ago
Mrs. Matthews wants to have $18,000 in the bank in 2 years. If she deposits $9000 today at 6% compounded quarterly for 2 years,
OverLord2011 [107]
Depends if you want
1. find how much he will earn, find the differnce between that and 18000
2. see how much to invest till he will  get 18000


A=P(1+ \frac{r}{n})^{nt}

A=futre amount
P=present amout
r=rate in decimal
n=number of times per year ccompounded
t=time in years


1.
A=?
P=9000
r=0.06
n=4 (quarter means 4 times per year)
t=2
?=9000(1+ \frac{0.06}{4})^{(4)(2)}
?=9000(1+ 0.015)^{8}
?=9000(1.015)^{8}
?=10138.4 will be earned
18000-10138.4=7861.6 needed

2.
A=18000
P=9000+x
r=0.06
n=4 (quarter means 4 times per year)
t=2
18000=(9000+x)(1+ \frac{0.06}{4})^{(4)(2)}
18000=(9000+x)(1+ 0.015)^{8}
18000=(9000+x)(1.015)^{8}
divide both sides by 1.015^8
15978.8=9000+x
minus 9000 both sides
6978.8 needed




if he willnot be investing any more, he needs $7861.6 more
if he will invest more he will need to invest $6978.8 more




6 0
1 year ago
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If f(x) = 1 – x, which value is equivalent to |f(i)|? options are:
g100num [7]
We have to determine which value is equivalent to | f ( i ) | if the function is: f ( x ) = 1 - x. We know that for the complex number: z = a + b i , the absolute value is: | z | = sqrt( a^2 + b^2 ). In this case: | f ( i )| = | 1 - i |. So: a = 1, b = - 1. | f ( i ) | = sqrt ( 1^2 + ( - 1 )^2) = sqrt ( 1 + 1 ) = sqrt ( 2 ). Answer: <span>C. sqrt( 2 )</span>
5 0
2 years ago
Read 2 more answers
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