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nekit [7.7K]
1 year ago
12

A square OABC with the length of a side 6 cm and circle k(O) with a radius 5 cm are given. Which of the lines OA , AB , BC , or

AC are secants to the circle k(O)?
Mathematics
1 answer:
Pavel [41]1 year ago
5 0

Answer:

AC and OA

Step-by-step explanation:

-A secant is a  line connecting two points on the circle.

-Given the square OABC of sides 6cm and a circle of r=5cm and  the center of the circle as O, and that the radius of the circle is less than the side of the square:

-The circle passes through OA and OC, but doesn't pass through AB and BC.

Hence, AC and OA are the circle's secants.

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Find the quotient of 2,300 and (0.4 · 10^-8). In your final answer, include all of your calculations.
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Answer:

5.75x10^11

Step-by-step explanation:

quotient of 2,300 and (0.4x10^-8) is

2,300 ÷ (0.4x10^-8)

2300 = 2.3x10^3

We now have

2.3x10^3 / 0.4x10^-8

= (2.3/0.4) x ( 10^(3 - (-8))

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= 5.75 x (10^11)

= 5.75x10^11

Please mark brainliest if helpful. Thanks

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