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nekit [7.7K]
2 years ago
12

A square OABC with the length of a side 6 cm and circle k(O) with a radius 5 cm are given. Which of the lines OA , AB , BC , or

AC are secants to the circle k(O)?
Mathematics
1 answer:
Pavel [41]2 years ago
5 0

Answer:

AC and OA

Step-by-step explanation:

-A secant is a  line connecting two points on the circle.

-Given the square OABC of sides 6cm and a circle of r=5cm and  the center of the circle as O, and that the radius of the circle is less than the side of the square:

-The circle passes through OA and OC, but doesn't pass through AB and BC.

Hence, AC and OA are the circle's secants.

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Jordan is making gifts for volunteers and orders 4,580 personalized M&Ms. She puts 34 M&Ms in each gift. How many gifts
marin [14]

Answer:

134

Step-by-step explanation:

to find how many gifts it can make, you must find how many times 34 can go into 4580. do this by deciding 4580 by 34.

4580/34=134.7

Since you can't make less than a whole gift you must round it down to 134

8 0
2 years ago
F(x)=x2−x−1f, left parenthesis, x, right parenthesis, equals, x, squared, minus, x, minus, 1 What is the average rate of change
Alexandra [31]

Answer: The average rate of change = -1

Step-by-step explanation: Please find the attached file for the solution

5 0
2 years ago
For each system of equations, drag the true statement about its solution set to the box under the system?
natta225 [31]

Answer:

y = 4x + 2

y = 2(2x - 1)

Zero solutions.

4x + 2 can never be equal to 4x - 2

y = 3x - 4

y = 2x + 2

One solution

3x - 4 = 2x + 2 has one solution

Step-by-step explanation:

* Lets explain how to solve the problem

- The system of equation has zero number of solution if the coefficients

 of x and y are the same and the numerical terms are different

- The system of equation has infinity many solutions if the

   coefficients of x and y are the same and the numerical terms

   are the same

- The system of equation has one solution if at least one of the

  coefficient of x and y are different

* Lets solve the problem

∵ y = 4x + 2 ⇒ (1)

∵ y = 2(2x - 1) ⇒ (2)

- Lets simplify equation (2) by multiplying the bracket by 2

∴ y = 4x - 2

- The two equations have same coefficient of y and x and different

  numerical terms

∴ They have zero equation

y = 4x + 2

y = 2(2x - 1)

Zero solutions.

4x + 2 can never be equal to 4x - 2

∵ y = 3x - 4 ⇒ (1)

∵ y = 2x + 2 ⇒ (2)

- The coefficients of x and y are different, then there is one solution

- Equate equations (1) and (2)

∴ 3x - 4 = 2x + 2

- Subtract 2x from both sides

∴ x - 4 = 2

- Add 4 to both sides

∴ x = 6

- Substitute the value of x in equation (1) or (2) to find y

∴ y = 2(6) + 2

∴ y = 12 + 2 = 14

∴ y = 14

∴ The solution is (6 , 14)

y = 3x - 4

y = 2x + 2

One solution

3x - 4 = 2x + 2 has one solution

3 0
2 years ago
Uma urna contém 10 bolas identificadas pelas letras A, B, ..., J. Uma bola é extraída ao acaso da urna e sua letra é observada.
arlik [135]

Answer:

a) Probability that a letter of the drawn ball is vowel = (3/10) = 0.30

b) Probability that a letter of the drawn ball is consonant = (7/10) = 0.70

a) Probabilidade de uma letra da bola sacada ser vogal = (3/10) = 0.30

b) Probabilidade de uma letra da bola sacada ser consoante = (7/10) = 0,70

Step-by-step explanation:

English Translation

A ballot box contains 10 balls identified by the letters A, B, ..., J. A ball is drawn at random from the ballot box and its letter is observed. (Make the sample space and all events explicit). What is the probability that a letter of the drawn ball is: a) Vowel b) Consonant

Solution

The 10 balls are identified by A, B, C, D, E, F, G, H, I and J

Note that the probability of an event is given as the number of elements in that event divided by the number of elements in the sample space.

a) Probability of drawing a ball that has a vowel letter = P(v)

P(v) = n(v) ÷ n(S)

n(v) = Number of balls with vowel letters = 3 (that is, A, E and I)

n(S) = Total number of balls = 10

P(v) = (3/10) = 0.30

b) Probability of drawing a ball that has a consonant letter = P(c)

P(c) = n(c) ÷ n(S)

n(c) = Number of balls with consonant letters = 7 (that is, B, C, D, F, G, H and J)

n(S) = Total number of balls = 10

P(c) = (7/10) = 0.70

In Portugese/Em português

As 10 bolas são identificadas por A, B, C, D, E, F, G, H, I e J.

Observe que a probabilidade de um evento é fornecida como o número de elementos nesse evento dividido pelo número de elementos no espaço de amostra.

a) Probabilidade de desenhar uma bola com uma letra de vogal = P (v)

P (v) = n (v) ÷ n (S)

n (v) = Número de bolas com letras de vogal = 3 (ou seja, A, E e I)

n (S) = Número total de bolas = 10

P (v) = (3/10) = 0,30

b) Probabilidade de desenhar uma bola com uma letra consoante = P (c)

P (c) = n (c) ÷ n (S)

n (c) = Número de bolas com letras consoantes = 7 (ou seja, B, C, D, F, G, H e J)

n (S) = Número total de bolas = 10

P (c) = (7/10) = 0,70

Hope this Helps!!!!

Espero que isto ajude!!!!

3 0
2 years ago
Eula needs to buy binders that cost $4 each and notebooks that cost $2 each. She has $20. The graph of the inequality 4x + 2y ≤
professor190 [17]
If there are no notebooks purchased, then Eula may buy 5 binders. If no binders are bought, then Eula may buy 10 notebooks. If 7 notebooks are purchased, then one binder may be purchased; this will also cause Eula to have $2 extra (maybe for tax).
4 1
2 years ago
Read 2 more answers
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